Percentage for AFCAT — Concepts, Shortcuts, and Solved PYQs

beginner 18 min read

Concept

Percentage is simply a fraction with denominator 100. The word comes from the Latin "per centum," meaning "per hundred." When you say 35%, you mean 35 out of every 100 parts. That is all it ever means — nothing more exotic.

Here is the analogy that makes it stick: think of a percentage as a universal ruler. You can compare salaries, election results, discount rates, and population growth on the same scale only because percentages normalize everything to base 100. A shopkeeper's 40% markup and a city's 10% population growth are immediately comparable even though the raw numbers are in completely different units.

The three core moves you will use in every AFCAT question:

Move 1 — Convert to a multiplier. Instead of writing "increase by 25%," write "multiply by 1.25." Instead of "decrease by 15%," write "multiply by 0.85." This single habit eliminates most calculation errors, especially in multi-step problems like compound growth or successive discounts.

Move 2 — Anchor on base 100. When a question asks "what percentage of X is Y," fix X as 100 and scale proportionally. This is not a formal algebraic step — it is a mental shortcut that bypasses equation setup.

Move 3 — Fraction-percent equivalents. A handful of fractions appear constantly in AFCAT: 1/4 = 25%, 1/5 = 20%, 1/3 ≈ 33.33%, 3/4 = 75%, 1/8 = 12.5%, 2/3 ≈ 66.67%. Recognizing these on sight saves you the multiplication step entirely.

Look — AFCAT is not a paper that throws bizarre percentage problems at you. The patterns repeat: mark-up and discount (percentage of percentage), savings as a residual (100% minus expenses), set theory with two categories (union formula), and successive change (multiplicative model). Once you recognize which template a question belongs to, you are 80% done.


Deep Dive

The Multiplier Model for Percentage Change

If a quantity changes by r%, the new quantity is the original multiplied by (1 + r/100) for an increase or (1 - r/100) for a decrease.

Formal notation: New = Original × (1 ± r/100)

This becomes powerful when changes are chained. For two successive changes of a% and b%:

Net multiplier = (1 ± a/100)(1 ± b/100)

Expanding this gives the net percentage change formula:

Net % = a + b + (ab/100) (use appropriate signs)

So a 25% increase followed by a 20% decrease: Net % = 25 + (-20) + (25 × (-20)/100) = 25 - 20 - 5 = 0%

That is zero net change — a fact that appears directly in one of the PYQs below.

Mark-Up and Discount

This is the most common disguised percentage problem in AFCAT. The trap is that mark-up percentage is on Cost Price (CP) while discount percentage is on Marked Price (MP). They are not the same base.

If you mark up by m%: MP = CP × (1 + m/100)

If you then give discount of d%: SP = MP × (1 - d/100)

Combining: SP = CP × (1 + m/100) × (1 - d/100)

Profit % = [(SP - CP) / CP] × 100 = [(1 + m/100)(1 - d/100) - 1] × 100

For the standard AFCAT question (mark up 40%, discount 15%): SP/CP = 1.40 × 0.85 = 1.19 → Profit = 19%

Residual Savings Problems

These are trivially easy once you see the structure. If someone spends a% on food and b% on rent, savings = (100 - a - b)% of income. Set that equal to the given amount and divide. No algebra needed.

Set Theory: Two-Category Problems

For any two sets A and B within a universal set: |A ∪ B| = |A| + |B| - |A ∩ B|

In percentage terms: %( A or B ) = %A + %B - %(A and B) %(Neither) = 100% - %(A or B)

This is the union formula, and it handles every "survey" or "preference" problem in AFCAT.

Successive Growth and Decay

For compound growth at rate r% per period over n periods: Final = Initial × (1 + r/100)^n

For depreciation: replace + with -.

The key insight for reverse depreciation problems (the machine question): if you are given the final value and asked for the original, divide by the multiplier rather than multiplying.

Original = Final / (multiplier)^n

For the specific case: machine depreciates 15% per year, value after 2 years = 68000. Original = 68000 / (0.85)^2 = 68000 / 0.7225 ≈ 94118

Do not try to add back 15% twice — that is wrong because 15% of 68000 is a different amount than 15% of the original.

Percentage Equation Problems

When a question says "25% of x added to 75 equals x," set it up as: 0.25x + 75 = x 75 = 0.75x x = 100

The speedup: recognize that 0.75 = 3/4, so x = 75 × 4/3 = 100. Fraction arithmetic is faster than decimal arithmetic here.

Election and Population Difference Problems

When the difference in votes between two candidates corresponds to a known percentage difference, equate that percentage to the given absolute number and solve for total.

(% difference) × Total = Absolute difference

If A has 45% and B has 35%, the gap is 10%. If 10% of total = 12000, then total = 120000. Direct division — no equations needed.


Memory Tricks & Shortcuts

patternThe Multiplier Chain

Convert every percentage change to a decimal multiplier immediately. Chain multiplications instead of computing step by step.

Example: 40% markup then 15% discount. Standard method: Compute MP = 140, then SP = 140 × 0.85 = 119. Two separate multiplications. ~40 seconds. Shortcut: Write 1.40 × 0.85 in one step. Note 1.4 × 0.85 = 1.4 × (1 - 0.15) = 1.4 - 0.21 = 1.19. Done in ~12 seconds. The product minus 1 gives you the profit/loss fraction directly. 0.19 = 19% profit.

patternSuccessive Change Net Formula

For two successive percentage changes a and b (with signs), the net change is a + b + ab/100.

Example: +25% then -20%. Standard method: 100 → 125 → 100. Three steps, two multiplications. ~35 seconds. Shortcut: 25 + (-20) + (25 × (-20)/100) = 5 - 5 = 0. Mental arithmetic in ~8 seconds. The ab/100 term is the second-order correction. When both are positive, it adds; when signs differ, it subtracts. This is the term most people miss in exam conditions.

eliminationResidual Method for Savings/Income

Never set up a full equation for income problems. Identify the savings percentage directly by subtracting all expense percentages from 100.

Example: 60% on food, 20% on rent, saves Rs. 4000. Standard method: Let income = x, set up 0.20x = 4000. ~25 seconds. Shortcut: Savings % = 100 - 60 - 20 = 20%. Income = 4000 / 0.20 = 4000 × 5 = 20000. Mental division by a unit fraction. ~10 seconds. Works for any number of expense categories. Just subtract them all from 100 and divide savings by that fraction.

patternUnion Formula for Neither Problems

%(Neither) = 100 - %A - %B + %(both).

Example: 45% like tea, 35% like coffee, 20% like both. Standard method: Draw a Venn diagram, fill in regions. ~40 seconds. Shortcut: Neither = 100 - 45 - 35 + 20 = 40. Straight arithmetic, 4 numbers, ~8 seconds. The critical step people get wrong: they subtract the overlap twice (once from each set) and forget to add it back. The formula automatically corrects for that.

substitutionReverse Depreciation: Divide, Never Add Back

To find original value before n periods of r% depreciation, divide the current value by (1 - r/100)^n. Do not add the percentage back to the current value.

Example: 15% annual depreciation, current value 68000, find value 2 years ago. Wrong approach: 68000 + 15% + 15% ≈ 90000. This is incorrect because the percentages apply to different bases. Correct shortcut: (0.85)^2 = 0.7225. Then 68000 / 0.7225. Note 0.7225 = 5776/8000 — or just compute 68000 / 0.7225 ≈ 94118. Standard method (trial-and-error with large numbers): ~90 seconds. Division method: ~30 seconds once you know 0.85^2.


Fast-Solving Framework

Read the question and immediately classify it into one of five templates:

Template 1 — Equation type ("X% of N + constant = N"): Isolate N algebraically, use fraction equivalents for speed.

Template 2 — Residual type (income/savings/expenses): Add up all given percentages, subtract from 100, divide the given amount by that residual fraction.

Template 3 — Mark-up + discount type: Multiply (1 + markup/100) × (1 - discount/100), subtract 1, convert to percentage.

Template 4 — Set theory type (survey/preference with "both" and "neither"): Apply Neither = 100 - A - B + Both. Done in one line.

Template 5 — Growth/decay type: Apply Final = Initial × (multiplier)^n. For reverse problems, divide Final by (multiplier)^n.

Template 6 — Difference type (elections, comparisons): Express the difference as a percentage of total, equate to the given absolute difference, divide.

If a question feels hard, you have probably mis-classified it. Re-read the first and last sentences — the first sentence gives you the template, the last sentence tells you what you are solving for.


Solved PYQs

Why this question — This is the canonical mark-up-and-discount question. The trap is applying both percentages to the same base.

Previous Year Questionपिछले वर्ष का प्रश्न
A shopkeeper marks his goods 40% above the cost price. If he gives a discount of 15% on the marked price, what is his profit percentage?
एक दुकानदार अपने सामान पर लागत मूल्य से 40% अधिक का मूल्य अंकित करता है। यदि वह अंकित मूल्य पर 15% की छूट देता है, तो उसका लाभ प्रतिशत क्या होगा?
  1. 19%
  2. 21%
  3. 25%
  4. 30%
  1. 19%
  2. 21%
  3. 25%
  4. 30%
Solutionसमाधान
Let CP = 100. MP = 140. SP after 15% discount = 140 × 0.85 = 119. Profit = 119 - 100 = 19. Profit% = 19%.
मान लेते हैं CP = 100। MP = 140। 15% छूट के बाद SP = 140 × 0.85 = 119। लाभ = 119 - 100 = 19। लाभ% = 19%।

Solving path: Fix CP = 100. MP = 100 × 1.40 = 140. SP = 140 × 0.85 = 119. Profit = 19 on a base of 100 → 19%. The shortcut: 1.40 × 0.85 = 1.19, profit = 19%, directly from the multiplier.


Why this question — Tests whether you can set up and solve a single-variable percentage equation without over-complicating it.

Previous Year Questionपिछले वर्ष का प्रश्न
If 25% of a number is added to 75, the result is the number itself. What is the number?
यदि किसी संख्या का 25%, 75 में जोड़ दिया जाए तो परिणाम वही संख्या हो जाती है। वह संख्या क्या है?
  1. 100
  2. 120
  3. 150
  4. 200
  1. 100
  2. 120
  3. 150
  4. 200
Solutionसमाधान
Let the number be x. According to the condition: 25% of x + 75 = x. So 0.25x + 75 = x. This gives 75 = 0.75x, hence x = 100.
मान लेते हैं संख्या x है। शर्त के अनुसार: x का 25% + 75 = x। अतः 0.25x + 75 = x। इससे 75 = 0.75x, अतः x = 100।

Solving path: 0.25x + 75 = x75 = 0.75xx = 75 × (4/3) = 100. Recognize 0.75 = 3/4, so multiply by its reciprocal 4/3. This is faster than decimal division.


Why this question — Classic residual savings problem. Gets people who try to set up a full equation instead of reading off the savings percentage.

Previous Year Questionपिछले वर्ष का प्रश्न
A man spends 60% of his income on food, 20% on rent and saves the rest. If his savings is Rs. 4000, what is his total income?
एक आदमी अपनी आमदनी का 60% खाने पर, 20% किराए पर खर्च करता है और बाकी बचाता है। यदि उसकी बचत Rs. 4000 है, तो उसकी कुल आमदनी क्या है?
  1. Rs. 20000
  2. Rs. 18000
  3. Rs. 22000
  4. Rs. 25000
  1. Rs. 20000
  2. Rs. 18000
  3. Rs. 22000
  4. Rs. 25000
Solutionसमाधान
He saves = 100% - 60% - 20% = 20% of income. 20% of income = 4000. So total income = 4000 × 5 = Rs. 20000.
वह बचत करता है = 100% - 60% - 20% = आय का 20%। आय का 20% = 4000। अतः कुल आय = 4000 × 5 = रु. 20000।

Solving path: Expenses = 60% + 20% = 80%. Savings = 20%. So 20% of income = 4000. Income = 4000 × 5 = 20000. That multiplication by 5 is because 20% = 1/5, so the whole = 5 times the part.


Why this question — Tests the union formula. Many candidates add 45 + 35 = 80 and subtract from 100, forgetting to account for the overlap correctly.

Previous Year Questionपिछले वर्ष का प्रश्न
In a survey, 45% people like tea, 35% like coffee and 20% like both. What percentage of people like neither tea nor coffee?
एक सर्वे में 45% लोग चाय पसंद करते हैं, 35% कॉफी पसंद करते हैं और 20% दोनों पसंद करते हैं। कितने प्रतिशत लोग न चाय पसंद करते हैं और न कॉफी?
  1. 40%
  2. 35%
  3. 30%
  4. 25%
  1. 40%
  2. 35%
  3. 30%
  4. 25%
Solutionसमाधान
People liking tea or coffee = 45% + 35% - 20% = 60%. People liking neither = 100% - 60% = 40%.
चाय या कॉफी पसंद करने वाले = 45% + 35% - 20% = 60%। कुछ भी पसंद न करने वाले = 100% - 60% = 40%।

Solving path: People who like tea or coffee = 45 + 35 - 20 = 60%. Neither = 100 - 60 = 40%. The subtraction of 20% removes the double-counting of people who like both.


Why this question — Election percentage difference problem. The key is recognizing that the 12000-vote margin corresponds directly to the percentage gap, not to valid votes only.

Previous Year Questionपिछले वर्ष का प्रश्न
In an election, candidate A got 45% votes, candidate B got 35% votes and the remaining 20% votes were invalid. If A won by 12000 votes, find the total number of votes polled.
एक चुनाव में, उम्मीदवार A को 45% वोट मिले, उम्मीदवार B को 35% वोट मिले और बाकी 20% वोट अमान्य थे। अगर A ने 12000 वोटों से जीत हासिल की, तो कुल कितने वोट डाले गए?
  1. 120000
  2. 140000
  3. 150000
  4. 160000
  1. 120000
  2. 140000
  3. 150000
  4. 160000
Solutionसमाधान
Valid votes = 80% of total. A got 45% and B got 35% of total votes. Difference = 10% of total = 12000. So total votes = 120000.
वैध वोट = कुल का 80%। A को कुल का 45% और B को 35% मिले। अंतर = कुल का 10% = 12000। अतः कुल वोट = 120000।

Solving path: A got 45%, B got 35% of total votes polled. Margin = 10% of total = 12000. Total = 12000 / 0.10 = 120000. Note: the 20% invalid votes are a distractor — you are already working with percentages of total votes, so invalid votes do not affect the difference calculation between A and B.


Why this question — Compound growth over two periods. Tests whether you apply growth multiplicatively or additively (a very common mistake).

Previous Year Questionपिछले वर्ष का प्रश्न
The population of a city increases by 10% annually. If the current population is 50000, what will be the population after 2 years?
एक शहर की आबादी हर साल 10% बढ़ती है। अगर मौजूदा आबादी 50000 है, तो 2 साल बाद आबादी कितनी होगी?
  1. 60500
  2. 61000
  3. 60000
  4. 55000
  1. 60500
  2. 61000
  3. 60000
  4. 55000
Solutionसमाधान
Population after 1 year = 50000 × 1.10 = 55000. Population after 2 years = 55000 × 1.10 = 60500.
1 साल बाद जनसंख्या = 50000 × 1.10 = 55000। 2 साल बाद जनसंख्या = 55000 × 1.10 = 60500।

Solving path: Year 1: 50000 × 1.10 = 55000. Year 2: 55000 × 1.10 = 60500. The common wrong answer is 60000, which comes from 50000 × 1.20 (adding 10% twice instead of compounding). The 500-rupee difference is the interest-on-interest term.


Why this question — Reverse depreciation. Tests whether you understand that percentages apply to the value at the start of each period, not the current value.

Previous Year Questionपिछले वर्ष का प्रश्न
The value of a machine depreciates by 15% every year. If its current value is Rs. 68000, what was its value 2 years ago?
एक मशीन की कीमत हर साल 15% घटती है। अगर इसकी मौजूदा कीमत Rs. 68000 है, तो 2 साल पहले इसकी कीमत क्या थी?
  1. Rs. 94118
  2. Rs. 90000
  3. Rs. 85000
  4. Rs. 80000
  1. Rs. 94118
  2. Rs. 90000
  3. Rs. 85000
  4. Rs. 80000
Solutionसमाधान
Let value 2 years ago = V. After 1 year = 0.85V. After 2 years = 0.85 × 0.85V = 0.7225V = 68000. So V = 68000/0.7225 = Rs. 94118.
2 साल पहले मान = V मान लेते हैं। 1 साल बाद = 0.85V। 2 साल बाद = 0.85 × 0.85V = 0.7225V = 68000। अतः V = 68000/0.7225 = रु. 94118।

Solving path: V × (0.85)^2 = 68000. V = 68000 / 0.7225 ≈ 94118. To compute 0.7225: (0.85)^2 = 0.85 × 0.85. Think of it as (1 - 0.15)^2 = 1 - 0.30 + 0.0225 = 0.7225. Then 68000 / 0.7225 — the answer 94118 matches option A directly, so stop once you confirm the denominator is around 0.72.


Why this question — Successive percentage change. The net result of 0% is counterintuitive enough that it appears as an AFCAT question precisely to catch students who add percentages.

Previous Year Questionपिछले वर्ष का प्रश्न
A number is first increased by 25% and then decreased by 20%. What is the net percentage change?
एक संख्या को पहले 25% बढ़ाया जाता है और फिर 20% घटाया जाता है। कुल मिलाकर कितने प्रतिशत का बदलाव हुआ?
  1. 0%
  2. 5%
  3. 3%
  4. -2%
  1. 0%
  2. 5%
  3. 3%
  4. -2%
Solutionसमाधान
Let original number = 100. After 25% increase = 125. After 20% decrease = 125 × 0.80 = 100. Net change = 0%.
मूल संख्या = 100 मान लेते हैं। 25% वृद्धि के बाद = 125। 20% कमी के बाद = 125 × 0.80 = 100। कुल परिवर्तन = 0%।

Solving path: Use the formula: 25 + (-20) + (25 × (-20)/100) = 25 - 20 - 5 = 0. Or use multipliers: 1.25 × 0.80 = 1.00. Either way, the net change is exactly 0%. Do not add 25 and -20 to get 5% — that ignores the second-order term.


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