Series (Number, Letter & Mixed) for Agniveer Army CEE

intermediate 18 min read

Concept

A series question gives you a sequence of numbers, letters, or a combination of both, with one term missing. Your job: find the rule, then apply it to get the answer.

Think of a series like a coded message. The examiner has picked a rule — multiply by 3, add consecutive odd numbers, list perfect squares — and then written out the results. You are reversing the process. You see the output and figure out the rule. Once the rule clicks, the answer is just arithmetic.

Here is a useful analogy. Imagine a machine on an assembly line. You feed it one number, it applies a fixed operation, and out comes the next number. The sequence you see on paper is just a list of everything the machine produced. Your task is to figure out what the machine does, then ask: "What would it produce next?"

Series questions in the Agniveer Army CEE span three types:

The trap most test-takers fall into: they spend too long on a hard pattern when the answer could be confirmed by elimination. If you spot two plausible rules, check both against the given options — the correct rule will match exactly one option. The wrong rule will either match none or match more than one, which itself tells you something.


Deep Dive

The Seven Pattern Families You Must Recognise Instantly

Every number series in Agniveer CEE belongs to one of these families. Memorise the fingerprints.

1. Arithmetic Progression (AP) Each term increases or decreases by a fixed number (common difference d).

2. Geometric Progression (GP) Each term is multiplied (or divided) by a fixed ratio r.

3. Squares and Cubes

4. Fibonacci-type Each term = sum of the two immediately before it.

5. Difference Series (1st and 2nd order) When the terms themselves do not follow a neat rule, compute the differences between consecutive terms. If those differences form an AP or GP, you have a difference series.

6. Compound Rule ("do two things") Two operations are applied together each step.

7. Alternating Series (Two interleaved sequences) Odd-positioned terms follow one rule; even-positioned terms follow another.

Letter Series: The Position Mapping Method

Convert each letter to its alphabetical position number (A=1, B=2, ..., Z=26). Analyse the resulting number sequence using the seven families above. Convert back.

Watch the wrap-around: after Z (=26) comes A (=1) again. If your next position exceeds 26, subtract 26.

Mixed Series: The Split-Track Method

Split the sequence into two groups: all letters, all numbers.


Memory Tricks & Shortcuts

patternRatio Check in 3 Seconds

When you see a series where each term looks 2×–4× the previous, divide term 2 by term 1. If you get a clean integer, you have a GP. Verify with one more pair. Done — no subtraction needed at all.

Example: 7, 14, 28, 56 — divide 14÷7=2, confirm 28÷14=2. Rule is ×2. No need to write differences.

Standard method (compute all differences, note they are not constant, then compute ratios): 4 steps. This ratio-first check: 2 steps. Saves roughly 20 seconds on a 4-term GP.

patternSquare Root Snap

If the terms are all larger two-digit or three-digit numbers that look "familiar" (100, 81, 64, 49...), immediately try: is each term a perfect square? Take √(first term) mentally. If it is a whole number, you have a squares series.

√100 = 10, √81 = 9, √64 = 8, √49 = 7 → next root is 6 → 6² = 36.

Standard method (compute differences: -19, -17, -15... then figure out the decreasing-odd-difference pattern): 5 steps. Square-root snap: 2 steps. At least 30 seconds faster.

patternFibonacci Thumb Test

Add the last two terms you can see. If the result equals the next term shown, you have confirmed a Fibonacci-type series. Stop all other analysis immediately.

Example: 1, 1, 2, 3, 5, 8, ? — add 5+8=13. Check: does 13 appear in the options? Yes. Lock in.

Standard method (try AP, GP, difference analysis, give up, then try Fibonacci): potentially 60+ seconds. Fibonacci thumb test on recognition: under 10 seconds.

estimationDoubling + Constant — The ×2±k Probe

When terms roughly double but not exactly, probe the rule ×2 + k or ×2 - k for small values of k (0, 1, 2, 3).

Example: 3, 7, 15, 31 — is it GP? 7÷3 ≈ 2.3, not clean. Try ×2+1: 3×2+1=7 ✓, 7×2+1=15 ✓, 15×2+1=31 ✓. Rule confirmed. Next: 31×2+1=63.

Standard method (compute differences 4, 8, 16 — recognise these double — then add next difference 32: 31+32=63): 4 steps. ×2±k probe: 3 steps and more intuitive for compound rules. Saves 15–20 seconds.

eliminationElimination by Parity

Before solving the full pattern, check if the missing term must be odd or even. Most rules preserve parity predictably in a GP or AP. If three of the four options are eliminated by parity alone, you have a near-certain answer in 5 seconds.

Example: 15, 30, 60, 120, ? — all terms are even after the first (×2 each time). The next must be even. Options: 240, 180, 300, 200 — all even here, so parity does not eliminate. But if one option were 241 or 301, parity would kill it instantly.

This works best on AP series where odd+odd=even, even+even=even patterns are predictable. Eliminates 1–2 wrong options in under 5 seconds, shrinking guesswork from 25% to 33–50% if you are stuck.


Fast-Solving Framework

In the exam hall, run this decision tree in order. Stop as soon as you hit a match.

Step 1 — Glance at the terms. Are they recognisable as squares (1, 4, 9, 16...) or cubes (1, 8, 27, 64...)? If yes, apply Square Root Snap or Cube Root Snap.

Step 2 — Compute first-order differences. Subtract each term from the next. Are all differences equal? → AP. Done.

Step 3 — Compute ratios. Divide each term by the one before it. Are all ratios equal? → GP. Done.

Step 4 — Add last two terms. Does the sum equal the next given term? → Fibonacci. Done.

Step 5 — Compute second-order differences. Take the differences of the differences from Step 2. Are these equal or do they double? → Difference series or compound rule.

Step 6 — Try ×2±k probe for compound rules.

Step 7 — Suspect two interleaved sequences. Separate odd and even positions. Analyse each track from Step 1.

If none work in 60 seconds: use elimination — check parity, rough magnitude, and cross out obviously wrong options. Take your best guess and move on. Do not let one series question steal time from five others.


Solved PYQs

Why this question: The classic Fibonacci recognition question. This exact series appears repeatedly across competitive exams. If you do not know Fibonacci on sight, you will spend 40 seconds re-deriving the pattern.

Previous Year Questionपिछले वर्ष का प्रश्न
What is the missing number: 1, 1, 2, 3, 5, 8, ?
लुप्त संख्या ज्ञात कीजिए: 1, 1, 2, 3, 5, 8, ?
  1. 13
  2. 11
  3. 15
  4. 10
  1. 13
  2. 11
  3. 15
  4. 10
Solutionसमाधान
This is the Fibonacci series where each term is the sum of the previous two terms. 5 + 8 = 13.
यह फिबोनाची श्रृंखला है जहाँ प्रत्येक पद पिछले दो पदों का योग है। 5 + 8 = 13।

Solving path: Apply the Fibonacci Thumb Test immediately. 5+8=13. Check options — 13 is option A. Lock in. Time: under 10 seconds.


Why this question: Pure GP. The "×3 series" is one of the most common GP variants in Agniveer CEE. Tests whether you check ratios before wasting time on differences.

Previous Year Questionपिछले वर्ष का प्रश्न
Complete the series: 4, 12, 36, 108, ?
श्रृंखला पूरी कीजिए: 4, 12, 36, 108, ?
  1. 324
  2. 216
  3. 432
  4. 540
  1. 324
  2. 216
  3. 432
  4. 540
Solutionसमाधान
Each term is multiplied by 3. 4×3=12, 12×3=36, 36×3=108, 108×3=324.
प्रत्येक पद को 3 से गुणा किया जाता है। 4×3=12, 12×3=36, 36×3=108, 108×3=324।

Solving path: Ratio Check — 12÷4=3, 36÷12=3. Rule: ×3. Next: 108×3=324. Option A. Time: 15 seconds.


Why this question: Compound rule ×2+1. AP and GP analyses both fail here, which panics many test-takers. This question teaches you to probe ×2±k when simple methods break down.

Previous Year Questionपिछले वर्ष का प्रश्न
Find the missing number: 3, 7, 15, 31, ?
लुप्त संख्या ज्ञात कीजिए: 3, 7, 15, 31, ?
  1. 63
  2. 47
  3. 55
  4. 71
  1. 63
  2. 47
  3. 55
  4. 71
Solutionसमाधान
The pattern is: multiply by 2 and add 1. 3×2+1=7, 7×2+1=15, 15×2+1=31, 31×2+1=63.
पैटर्न है: 2 से गुणा करके 1 जोड़ना। 3×2+1=7, 7×2+1=15, 15×2+1=31, 31×2+1=63।

Solving path: Differences: 4, 8, 16 — these double, so the series is not simple AP. Try ×2+1: 3×2+1=7 ✓, 7×2+1=15 ✓, 15×2+1=31 ✓. Next: 31×2+1=63. Option A. Time: 20 seconds.


Why this question: Descending squares. Tests whether you recognise the "neat large numbers" fingerprint. Many test-takers try subtraction (differences: -19, -17, -15...) and still get there but take twice as long.

Previous Year Questionपिछले वर्ष का प्रश्न
What comes next: 100, 81, 64, 49, ?
अगली संख्या क्या होगी: 100, 81, 64, 49, ?
  1. 36
  2. 25
  3. 16
  4. 9
  1. 36
  2. 25
  3. 16
  4. 9
Solutionसमाधान
These are perfect squares in descending order: 10², 9², 8², 7², 6². So next is 6² = 36.
ये घटते क्रम में पूर्ण वर्ग हैं: 10², 9², 8², 7², 6²। अतः अगला 6² = 36 है।

Solving path: Square Root Snap — √100=10, √81=9, √64=8, √49=7. Next root = 6. 6²=36. Option A. Time: 10 seconds.


Why this question: Difference series with doubling differences. The raw terms do not follow AP or GP, so you must go to second-order analysis. This tests whether you actually use the full decision tree.

Previous Year Questionपिछले वर्ष का प्रश्न
Find the next term: 3, 8, 18, 38, ?
अगला पद ज्ञात कीजिए: 3, 8, 18, 38, ?
  1. 78
  2. 68
  3. 88
  4. 58
  1. 78
  2. 68
  3. 88
  4. 58
Solutionसमाधान
The differences are 5, 10, 20 (each doubling). Next difference would be 40, so 38 + 40 = 78.
अंतर 5, 10, 20 हैं (प्रत्येक दोगुना हो रहा है)। अगला अंतर 40 होगा, इसलिए 38 + 40 = 78।

Solving path: Differences: 8-3=5, 18-8=10, 38-18=20. The differences are 5, 10, 20 — each doubles (GP ×2). Next difference = 40. So next term = 38+40=78. Option A. Time: 25 seconds.


Common Mistakes


Related Topics

Practice on SarkariRise

Sign up + get 3 free mocks →