Percentage for Agniveer Vayu — Concepts, Tricks & Solved PYQs

beginner 15 min read

Concept

Percentage literally means "per hundred" — it is a ratio expressed as parts out of 100. When you say 35%, you mean 35 out of every 100 units. That is the entire foundation. Everything else — discounts, profit, elections, population change — is just this one idea applied to a context.

Here is the analogy that makes it click: imagine a cricket ground with exactly 100 seats. Whatever fraction of those seats is occupied gives you the percentage directly. If 60 seats are filled, that is 60%. If the ground now has 250 seats and 150 are filled, you scale: (150/250) × 100 = 60% — same answer, different total.

The three quantities in any percentage problem are:

The master formula is:

Percentage=PartWhole×100\text{Percentage} = \frac{\text{Part}}{\text{Whole}} \times 100

Rearranging gives you two more forms you'll use constantly:

Part=Percentage100×Whole\text{Part} = \frac{\text{Percentage}}{100} \times \text{Whole}

Whole=Part×100Percentage\text{Whole} = \frac{\text{Part} \times 100}{\text{Percentage}}

Pick the form based on what is unknown. In most Agniveer Vayu questions, the Whole is unknown — you are given a percentage and its actual value, and asked for the total. The election-type question is the classic example of this pattern.

One thing beginners trip over: the base matters. A 20% increase followed by a 20% decrease does not bring you back to the original. The second 20% is applied to a larger number, so the net effect is a small loss. This asymmetry is why successive discount and percentage change questions are exam favourites.


Deep Dive

Percentage Change

Percentage Change=New ValueOld ValueOld Value×100\text{Percentage Change} = \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \times 100

If the result is positive, it is an increase. If negative, a decrease. The old value is always the base — not the new value, not the average.

Example: Price rises from 80 to 100. (100 - 80) / 80 × 100 = 25% increase

Now reverse it: Price falls from 100 to 80. (80 - 100) / 100 × 100 = -20% decrease

Same two numbers, different bases, different percentages. This is the most common confusion in the exam.

Successive Percentage Changes

This is where Agniveer Vayu loves to test you. Two successive changes of a% and b% are NOT simply (a + b)%. The correct single equivalent change is:

Net %=a+b+ab100\text{Net \%} = a + b + \frac{ab}{100}

Where a and b carry their signs (positive for increase, negative for decrease).

For two successive discounts of d1% and d2%:

Equivalent single discount=1(1d1100)(1d2100)\text{Equivalent single discount} = 1 - \left(1 - \frac{d1}{100}\right)\left(1 - \frac{d2}{100}\right)

Or using the formula: d1 + d2 - (d1 × d2)/100

Let's verify with 10% and 20% discounts: 10 + 20 - (10 × 20)/100 = 30 - 2 = 28%

And with 20% and 30%: 20 + 30 - (20 × 30)/100 = 50 - 6 = 44%

Both match the PYQs exactly. Memorise this formula — it is a direct mark on the paper.

Fraction ↔ Percent Conversions

You need these cold. Calculating 2/7 × 100 mid-exam costs 20 seconds. Knowing 2/7 ≈ 28.57% costs zero.

| Fraction | Percentage | |----------|------------| | 1/2 | 50% | | 1/3 | 33.33% | | 2/3 | 66.67% | | 1/4 | 25% | | 3/4 | 75% | | 1/5 | 20% | | 2/5 | 40% | | 3/5 | 60% | | 4/5 | 80% | | 1/6 | 16.67% | | 1/8 | 12.5% | | 3/8 | 37.5% | | 1/10 | 10% | | 1/12 | 8.33% |

Election / Majority Problems

Standard format: Candidate A gets X%, wins by Y votes. Find total votes.

The margin between two candidates is (X - (100 - X))% = (2X - 100)% of total votes.

Set that equal to the given margin and solve:

Total Votes=Margin in votes(2X100)/100\text{Total Votes} = \frac{\text{Margin in votes}}{(2X - 100)/100}

For 60% winner, margin percentage = 2(60) - 100 = 20%. So total = 1200 / 0.20 = 6000.

Finding the Original Value

"After a 20% increase, the price is 600. What was the original price?"

Do NOT subtract 20% from 600. That is wrong.

Original × 1.20 = 600 Original = 600 / 1.20 = 500

The multiplier approach: increase by p% means multiply by (1 + p/100), decrease by p% means multiply by (1 - p/100). To reverse, divide by that multiplier.


Memory Tricks & Shortcuts

patternSuccessive Discount Formula

Use a + b - ab/100 for two successive discounts or percentage changes. Works in both directions (use negative values for decreases if mixing increase/decrease).

Example: 10% and 20% discounts → 10 + 20 - (10×20)/100 = 30 - 2 = 28%. No multiplications of decimals needed.

Standard method (multiply 0.9 × 0.8 = 0.72, then 1 - 0.72 = 0.28): 5 steps. This formula: 3 steps. In the exam hall, that saves about 15 seconds per question, and these questions appear in pairs.

patternElection Margin = (2W - 100)% of Total

Whenever the winner's percentage W is given and you need total votes: margin% = 2W - 100. Divide the actual margin by this percentage (as a decimal).

Example: W = 60%, margin = 1200 votes → 2(60) - 100 = 20% → total = 1200 / 0.2 = 6000.

Standard method (write winner = 0.6T, loser = 0.4T, subtract, solve): 4 equations. This: 2 steps. Saves approximately 20 seconds.

substitutionReverse Percentage via Multiplier Division

"A number after X% increase becomes N. Find original." Divide N by (1 + X/100). Never subtract X% from N.

Example: After 25% increase → 500. Original = 500 / 1.25 = 400.

Trap method (500 × 0.75 = 375): wrong answer in 5 seconds. Correct method: 1 division step. Zero extra time, zero error — just the right setup.

patternFraction Table for Instant Conversion

Pre-load fractions 1/2 through 1/12 (see table in Deep Dive). When a question gives you a percentage like 12.5% or 37.5%, immediately convert to fraction (1/8 or 3/8) and work with clean integers instead of decimals.

Example: 37.5% of 240 → (3/8) × 240 = 90. Done in one step vs. 0.375 × 240 long multiplication. Saves 10-15 seconds and eliminates decimal errors.

patternNet Effect of Two Equal Changes

If a value increases by X% then decreases by X%, the net change is always a decrease of X²/100 %.

Example: +20% then -20% → net = -(20²/100)% = -4%. The value does NOT return to original.

Standard method (compute each step separately): 4 multiplications. This formula: 1 squaring. Saves about 20 seconds and eliminates the common "it cancels out" trap.


Fast-Solving Framework

When a percentage question appears, identify the type in the first 5 seconds:

Type 1 — Find the percentage: Use (Part/Whole) × 100. Confirm which is the "whole" (it is always the original or reference value).

Type 2 — Find the part: Use (Percentage/100) × Whole. Convert ugly percentages to fractions first.

Type 3 — Find the whole (election, original price): Use Part = (Percentage/100) × Whole, rearrange to Whole = Part × 100 / Percentage. For elections, use the (2W - 100) shortcut.

Type 4 — Successive changes: Count how many percentage changes are applied one after another. If two, use a + b - ab/100. If three, apply the formula twice in sequence.

Type 5 — Reverse percentage: Identify the final value and the percentage applied. Divide by the multiplier (1 ± p/100).

One rule above all: in every percentage problem, write down the base first. Half the errors in this topic happen because students apply a percentage to the wrong number.


Solved PYQs

Why this question: The most direct test of successive discount. Appears almost every year. Students who add 10 + 20 = 30% lose a mark in under 5 seconds.

Previous Year Questionपिछले वर्ष का प्रश्न2023
Two successive discounts of 10% and 20% are equivalent to a single discount of?
  1. 30%
  2. 28%
  3. 25%
  4. 27%
Solutionसमाधान
Equivalent single discount = 1 - (0.9)(0.8) = 1 - 0.72 = 0.28 = 28%.

Solving path: Apply the formula a + b - ab/100 = 10 + 20 - (10 × 20)/100 = 30 - 2 = 28%. Alternatively: original price = 100, after 10% discount = 90, after 20% on that = 90 × 0.8 = 72. Single discount = (100 - 72)/100 = 28%. Both routes give 28%. The formula is faster by 2-3 steps.


Why this question: Tests the election problem structure. The trap is dividing 1200 by 60 (getting 20 instead of 6000). You must recognise that the margin is a percentage of the total, not the winner's share.

Previous Year Questionपिछले वर्ष का प्रश्न2023
In an election, The winner gets 60% of the total votes and wins the election by 1200 votes then find the number of total voters in the election.
  1. 10000
  2. 6000
  3. 12000
  4. 8000
Solutionसमाधान
Winner gets 60%, loser gets 40%, margin = 20% of total = 1200, so total voters = 1200/0.20 = 6000.

Solving path: Winner = 60%, loser = 40%, gap = 20% of total. Set 0.20 × T = 1200, so T = 6000. Using the shortcut: (2 × 60 - 100) = 20%, total = 1200 / 0.20 = 6000. Answer: 6000 (option B).


Why this question: Same type as the first PYQ but with larger discount values. Tests whether you know the formula or are just adding percentages. Placed in a different year to show this pattern is not a fluke — it is a recurring examiner favourite.

Previous Year Questionपिछले वर्ष का प्रश्न2022
Successive discounts of 20% and 30% are equivalent to a single discount of
  1. 40%
  2. 35%
  3. 44%
  4. 42%
Solutionसमाधान
After a 20% discount, the price is 80% of original; after a further 30% discount it becomes 80% × 70% = 56% of original. So the single equivalent discount is 100% − 56% = 44%.

Solving path: a + b - ab/100 = 20 + 30 - (20 × 30)/100 = 50 - 6 = 44%. Or: start with 100, after 20% discount = 80, after 30% on 80 = 80 × 0.7 = 56. Equivalent single discount = 100 - 56 = 44%. Answer: 44% (option C).


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