General Chemistry (Mixed Topics) for Bihar Police Constable Exam

beginner 18 min read

Concept

General Chemistry in the Bihar Police Constable exam is not a deep academic test — it is a pattern recognition test. The paper draws from a fixed pool of concepts that appear again and again: the nature of metal and non-metal oxides, oxidation states, types of chemical bonds, allotropes, and a handful of "interesting substance" facts (white phosphorus, water, ionic compounds). Once you map these patterns, you stop studying chemistry and start collecting questions.

Here is the mental framework to anchor everything:

Think of matter as existing in a spectrum of "electron behaviour." On one end, metals give away electrons easily — their oxides are basic, their ions carry positive charge, and they form ionic bonds with non-metals. On the other end, non-metals hold electrons tightly — their oxides are acidic, they share electrons to form covalent bonds, and when the electronegativity difference between two atoms is very small, the sharing is nearly equal and you get a pure covalent bond.

Oxidation state is just the accounting system for electrons. If fluorine (the most electronegative element) is present in a compound, it will always grab electrons from everything else, including oxygen — which is why oxygen ends up with a positive oxidation state in OF₂. This feels counterintuitive because you are used to oxygen being −2, but the rule is: more electronegative element wins.

Allotropes are different physical forms of the same element. Diamond and graphite are both 100% carbon, yet one is the hardest natural substance and the other is a lubricant — because their atomic arrangement is completely different. That difference in structure (not composition) is the definition of an allotrope.

Chemical bonding comes down to electronegativity difference. Large difference → ionic bond. Small or zero difference → covalent bond. Coordinate/dative bond is a special case of covalent bonding where both electrons come from one atom. Hydrogen bonds are not true bonds — they are intermolecular attractions, but they are strong enough to give water four potential bonding sites per molecule.

These five clusters — oxide nature, oxidation states, allotropes, bonding types, and special substance properties — cover roughly 80% of the chemistry questions in Bihar Police Constable papers.


Deep Dive

1. Nature of Metal and Non-Metal Oxides

Metal oxides react with water to produce metal hydroxides (bases) and react with acids to form salt and water. This makes them basic oxides.

Na₂O + H₂O → 2NaOH (sodium hydroxide, a strong base)

Non-metal oxides react with water to form acids. CO₂ + H₂O → H₂CO₃ (carbonic acid). These are acidic oxides.

Exceptions to memorise: Aluminium oxide (Al₂O₃) and zinc oxide (ZnO) are amphoteric — they react with both acids and bases. Water itself (H₂O) is technically a neutral oxide. These exceptions appear in trickier questions.

2. Oxidation States — The Accounting System

The rules in priority order:

  1. Fluorine is always −1 (no exception — it is the most electronegative element).
  2. Oxygen is almost always −2 — except when bonded to fluorine (positive state) or in peroxides (−1, as in H₂O₂).
  3. Hydrogen is +1 with non-metals, −1 with metals (hydrides).
  4. Alkali metals (Group 1) are always +1; alkaline earth metals (Group 2) are always +2.
  5. The algebraic sum of all oxidation states in a neutral compound = 0.

Working out KMnO₄: K = +1, four oxygens = 4 × (−2) = −8 Sum must be zero: +1 + Mn − 8 = 0Mn = +7

Working out OF₂: Fluorine wins over oxygen. Each F = −1, two F's = −2. Molecule neutral: O + (−2) = 0O = +2.

This is a frequently tested twist. Drill it until it feels obvious.

3. Allotropes vs Isotopes vs Isomers vs Isotones

These four terms are perennial confusion traps in the exam:

| Term | Definition | Example | |---|---|---| | Allotropes | Same element, different structural forms | Diamond and graphite (both carbon) | | Isotopes | Same element, different mass numbers (different neutrons) | ¹²C and ¹⁴C | | Isotones | Different elements, same number of neutrons | ¹⁴C and ¹⁵N (both have 8 neutrons) | | Isomers | Same molecular formula, different structural arrangement | C₄H₁₀ can be n-butane or isobutane |

The Bihar Police paper consistently uses "allotropes" as the target answer for diamond/graphite, and the distractors are the other three terms. Know all four to eliminate quickly.

4. Chemical Bonding and Electronegativity Difference

The rule of thumb used in Indian competitive exams:

When the question says "very small electronegativity difference," the answer is covalent bond. Period. Don't overthink it.

Coordinate (dative) bond: One atom donates both electrons. This appears in NH₄⁺, H₃O⁺, and some questions on complex compounds. The bond itself is identical to a covalent bond once formed — the distinction is in formation, not structure.

5. Hydrogen Bonds in Water

Each water molecule has:

Total: 4 hydrogen bonds per molecule maximum. This explains water's unusually high boiling point, surface tension, and the fact that ice floats (hydrogen bonds hold molecules further apart in solid state).

6. Ionic Compounds and Electrical Conductivity

Ionic compounds in solid state do not conduct electricity — the ions are locked in a crystal lattice. Dissolve them in water, and the lattice breaks down, releasing free ions. These mobile ions carry charge, making the solution a good conductor (विद्युत का सुचालक). This is why the answer is always "abundance of ions in aqueous solution" — not "high lattice energy" (that would actually resist dissolution).

7. White Phosphorus and Spontaneous Combustion

White phosphorus (P₄) has an ignition temperature of approximately 34°C — just above room temperature. In open air, friction and atmospheric oxygen are enough to ignite it. This is why it is stored under water. Red phosphorus is a more stable allotrope of phosphorus and does not spontaneously combust. This distinction (white vs red phosphorus) is exactly what the 2014 Bihar Police paper tested.


Memory Tricks & Shortcuts

patternFINE Rule for Oxidation States

Remember F-I-N-E as the priority order for oxidation state assignment: Fluorine = always −1. Ionic metals (Group 1 = +1, Group 2 = +2). Neutral compound sums to zero. Exceptions are oxygen in peroxides (−1) and bonded to F (+2).

Apply this in sequence for any compound: standard method of random guessing takes 30–40 seconds; this rule resolves any two-element compound in under 10 seconds.

eliminationAIIO Confusion Buster

Allotropes = same Atom, different Arrangement. Isotopes = same element, different masIs. Isotones = different elements, same neutrOns. Isomers = same formula, different structure.

When the exam asks about diamond and graphite: same element (carbon), different arrangement → allotropes. Eliminate isotopes (different neutrons), isotones (different elements), isomers (molecular formula concept, not applicable to elements). This elimination takes 5 seconds vs reading all options carefully (20 seconds).

patternMOB Rule for Oxide Nature

Metal oxide → Basic. Non-Metal oxide → Acidic. Amphoteric exceptions: Al₂O₃ and ZnO.

Mnemonic: "MOB rules the acid world" — Metal Oxide is Basic. When you see "nature of metal oxide" in the question, your hand should move to "basic" before you finish reading the options. Standard reading time: 15 seconds. With MOB: 3 seconds.

patternWater's 4 Hands

Picture a water molecule as a person with 4 hands: 2 hands holding H atoms (donor sites), 2 hands from oxygen lone pairs (acceptor sites). Maximum hydrogen bonds = 4 hands. When the question asks "maximum hydrogen bonds in one water molecule," count the hands: 2 + 2 = 4. No calculation needed, 3 seconds flat.

eliminationWhite vs Red Phosphorus — The Storage Clue

The clue is always in the question context: "spontaneous combustion" or "stored under water" → white phosphorus. Red phosphorus is stable in air. If the question mentions any form of self-ignition or unusual storage requirement, white phosphorus is the answer. This pattern-match eliminates 3 wrong options in under 5 seconds.


Fast-Solving Framework

When you see a chemistry question in the Bihar Police paper, run this 3-step filter in under 10 seconds:

Step 1 — Category identification. Is the question about: (a) oxide nature, (b) oxidation state, (c) allotrope/isotope/isomer/isotone, (d) bonding type, or (e) a specific substance's property?

Step 2 — Apply the fixed rule.

Step 3 — Eliminate, don't compute. In most Bihar Police chemistry questions, three options are definitively wrong. Use elimination to arrive at the answer rather than deriving it from scratch. If your rule gives you a direct answer, mark it. If two options seem plausible, apply the exception check (amphoteric oxides, oxygen in OF₂, etc.).

Target: every chemistry MCQ solved in under 20 seconds using this framework.


Solved PYQs

Why this question: The nature of metal oxides is a fundamental concept tested across all Bihar/UP Police exams. It tests whether you know the acid-base behaviour of oxides, not just memorisation.

Previous Year Questionपिछले वर्ष का प्रश्न2021
What is the nature of the oxides of metals?
  1. Neutral
  2. Basic
  3. Acidic
  4. None of these
Solutionसमाधान
Metal oxides are generally basic in nature because they react with water to form metal hydroxides (bases) and react with acids to form salt and water.

Solving path: Apply MOB rule instantly. Metal oxide → Basic. Options: Neutral / Basic / Acidic / None. Mark Basic in 3 seconds. The reasoning: metal oxides react with water to form hydroxides (alkaline) and react with acids to form salt + water — both hallmarks of a base.


Why this question: Diamond vs graphite is among the most frequently recycled chemistry questions in state police exams. The trap is "isotopes" — because students associate "same element" with isotopes.

Previous Year Questionपिछले वर्ष का प्रश्न2021
Graphite and diamonds are_________.
  1. allotropes
  2. isotones
  3. isomers
  4. isotopes
Solutionसमाधान
Graphite and diamond are both pure forms of carbon but differ in their crystal structure, making them allotropes of carbon.

Solving path: Same element (carbon) + different physical structure = allotropes. Isotopes require different neutron counts (not applicable here). Isomers require the same molecular formula (a concept for compounds, not pure elements). Isotones require different elements. Eliminate all three distractors in 5 seconds, mark allotropes.


Why this question: Oxygen in OF₂ is a classic trick question. Every student knows oxygen is −2. This question tests whether you know the exception when oxygen bonds with fluorine.

Previous Year Questionपिछले वर्ष का प्रश्न2021
Which one of the following is the oxidation state of oxygen in OF₂?
  1. -1
  2. +2
  3. +1
  4. -2
Solutionसमाधान
In OF₂ (oxygen difluoride), fluorine is more electronegative than oxygen and each F has oxidation state −1. Since the molecule is neutral, oxygen has an oxidation state of +2.

Solving path: Fluorine is the most electronegative element — it always takes −1. Two fluorines = −2 total. Molecule is neutral, so oxygen compensates: O + (−2) = 0O = +2. The answer +2 feels wrong to most students (because they default to oxygen = −2), which is why this question keeps appearing. Lock in the FINE rule: Fluorine wins, always.


Why this question: Calculating the oxidation state of a transition metal in a compound is a standard Bihar Police pattern. KMnO₄ is the most commonly tested example.

Previous Year Questionपिछले वर्ष का प्रश्न2021
Oxidation number of Mn in KMnO₄ is
  1. -6
  2. +6
  3. +7
  4. -7
Solutionसमाधान
In KMnO₄, K is +1 and each O is −2 (total −8). For the compound to be neutral: +1 + Mn − 8 = 0, so Mn = +7.

Solving path: Assign known values first. K = +1 (Group 1 metal). O = −2 each, four oxygens = −8. Compound is neutral: +1 + Mn + (−8) = 0Mn = +7. The distractor +6 is there because students sometimes count only three oxygens or make an arithmetic error. Write the equation out once and you won't slip.


Why this question: Spontaneous combustion of white phosphorus is a direct factual recall question. It appeared in 2014 Bihar Police and similar questions appear in UP Police papers regularly.

Previous Year Questionपिछले वर्ष का प्रश्न2014
निम्नलिखित में से किस पदार्थ में स्वतः प्रवर्तित दहन (spontaneous combustion) के गुण है?
निम्नलिखित में से किस पदार्थ में स्वतः प्रवर्तित दहन (spontaneous combustion) के गुण है?
  1. लाल फास्फोरस
  2. काला कोयता
  3. सफेद फास्फोरस
  4. पीला सल्फर
  1. काला कोयता
  2. लाल फास्फोरस
  3. पीला सल्फर
  4. सफेद फास्फोरस
Solutionसमाधान
White phosphorus undergoes spontaneous combustion in air at room temperature because of its very low ignition temperature (~34°C), catching fire without any external ignition source.

Solving path: The keyword "spontaneous combustion" (स्वतः प्रवर्तित दहन) points immediately to white phosphorus. Red phosphorus is stable in air — it is the safe, non-reactive form. Black coal and yellow sulphur do not self-ignite at room temperature. White phosphorus has an ignition temperature of about 34°C, meaning it catches fire in open air without any external ignition. Mark सफेद फास्फोरस.


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