Electricity & Magnetism for Bihar Police Constable — Ohm's Law, Circuits, and More

intermediate 18 min read

Concept

Electricity is the flow of electric charge — specifically electrons — through a conductor. Think of it like water flowing through a pipe. The pipe is the wire, water pressure is voltage (V), the rate of flow is current (I), and anything that restricts flow is resistance (R).

Here is the analogy that sticks: imagine a narrow pipe connecting two tanks at different heights. The height difference drives water from high to low — that is voltage doing the same job in a circuit, pushing current from high potential to low. A thicker pipe allows more flow with less resistance. Squeeze the pipe (increase resistance) and the flow drops.

Three core quantities you must own:

Ohm's Law ties them together: V = IR. This one equation generates most of the numerical questions you will see.

Power is how fast electrical energy is used: P = VI = I²R = V²/R. In exam questions, you will almost always get two out of three variables and need to find the third. The formula P = I²R is the most commonly tested form.

Electrical energy consumed = P × t (Power × time). When you see "units consumed" or "kWh", you are working with this. 1 unit = 1 kWh = 1000 W used for 1 hour.

The difference between series and parallel circuits shapes everything about how household wiring and exam questions work. Series means resistors are chained end-to-end; parallel means they share the same two terminals. Your home runs on parallel — so each appliance gets full voltage and switching one off does not kill the others.

Deep Dive

Ohm's Law and Resistance

V = IR holds when temperature is constant. For a given material, resistance depends on:

Low resistivity = good conductor. Metals like copper and silver have very low resistivity — that is why wires are made of copper. Nichrome (an alloy of nickel and chromium) has high resistivity, which is why it is used in heaters. Among pure metals, chromium has lower resistivity than nichrome, iron, or nickel — important for the PYQ you will see below.

Series Circuits

Resistors R₁, R₂, R₃ in series:

The key rule: in series, more resistance = more voltage drop across that component.

So for 50 Ω and 100 Ω in series with the same current I flowing through both:

The 100 Ω resistor gets exactly double the voltage of the 50 Ω one.

Parallel Circuits

Resistors in parallel:

Household wiring is parallel because:

  1. Every appliance gets the full supply voltage (220 V in India)
  2. Appliances operate independently — turning off the fan does not turn off the light
  3. Adding more appliances does not change voltage for others (though it increases total current drawn)

Power and Energy

Three equivalent forms — use whichever two quantities are given:

| Given | Formula | |---|---| | V and I | P = VI | | I and R | P = I²R | | V and R | P = V²/R |

Energy calculation: Energy (kWh) = Power (kW) × Time (hours)

Convert watts to kilowatts by dividing by 1000. Then multiply by hours. The result is directly in units (kWh).

AC vs DC

AC is used for long-distance transmission because its voltage can be stepped up or down using transformers — DC cannot be transformed this way.

Electromagnetic Induction

When a conductor moves through a magnetic field (or when a magnetic field changes around a conductor), an EMF (electromotive force) is induced — this is Faraday's Law. This is the principle behind:

For generators, use Fleming's Right-Hand Rule: stretch thumb, index, and middle finger of the right hand mutually perpendicular. Thumb = motion direction, Index = magnetic field, Middle = induced current direction.

Magnetic Effect of Current

A current-carrying wire creates a magnetic field around it — this is the basis of electromagnets. The strength of the magnetic field increases with:

Memory Tricks & Shortcuts

patternVIR Triangle — Kill Three Formulas in One

Draw a triangle with V at top, I at bottom-left, R at bottom-right. Cover what you want to find:

  • Cover V → V = I × R
  • Cover I → I = V / R
  • Cover R → R = V / I

For power, draw a second triangle: P at top, I at bottom-left, V at bottom-right.

  • Cover P → P = I × V
  • Cover I → I = P / V
  • Cover V → V = P / I

Then combine: since V = IR, substitute into P = IV to get P = I²R or P = V²/R.

Standard approach (memorising 6 separate formulas): 3-4 minutes to recall under pressure. With both triangles drawn at the top of your rough sheet before the exam starts: 15 seconds to answer any power/voltage/current/resistance question.

patternSeries vs Parallel — The ONE Rule to Remember Each

Series: Same Current, resistances Add → remember "SCA" (Series: Current same, Add resistances). Parallel: Same Voltage, Reciprocals add → remember "SVR" (Same Voltage, Reciprocals).

For a two-resistor parallel shortcut: R_total = (R₁ × R₂) / (R₁ + R₂) — product over sum. No need to compute reciprocals.

Standard method (computing 1/R₁ + 1/R₂ with LCM): 5 steps. Product-over-sum shortcut: 2 steps. Saves roughly 30 seconds on a numerical question.

estimationUnits Consumed — Lock the Conversion

The trap: question gives power in Watts, but energy must be in kWh (units).

Lock this sequence: W ÷ 1000 = kW → kW × hours = units.

For the 100 W bulb question: 100 ÷ 1000 = 0.1 kW. Time = 10 h/day × 3 days = 30 hours. Energy = 0.1 × 30 = 3 units. Done in under 20 seconds once you have the conversion locked.

Most wrong answers come from forgetting to divide by 1000. Do the division first, always.

patternConductors Ranking — Resistivity Mental List

Best conductors in order (lowest to highest resistivity): Silver → Copper → Gold → Aluminium → Iron → Nichrome.

Key anchors: Copper is the standard wire material. Nichrome is the heater wire. For exam options that mix pure metals with alloys, the pure metal almost always wins. Nichrome is an alloy — it will lose to chromium (a pure metal component) in conductivity comparisons.

Recalling this costs 3 seconds vs. trying to reconstruct from scratch under exam pressure.

patternVoltage Division in Series — Direct Ratio

In a series circuit, voltage across each resistor is directly proportional to its resistance. No current calculation needed.

V₁ : V₂ = R₁ : R₂

For 50 Ω and 100 Ω in series across a total voltage: V distributes as 50:100 = 1:2. So the 100 Ω gets twice the voltage of the 50 Ω. Write the ratio, read the answer — 4 steps instead of 8. Saves about 40 seconds.

Fast-Solving Framework

When you see an electricity question in the exam hall, run this decision tree in your head:

Is it a conceptual question (conductor, AC/DC, circuit type)?

Is it a numerical question?

Is it a circuit configuration question?

Never start a numerical without writing down what is given and what is asked. One wrong substitution wastes more time than the 10 seconds of setup saves.

Solved PYQs

Why this question: Tests knowledge of material properties — resistivity is a standard topic, and the trap here is confusing Nichrome (a common alloy) with its constituent metals.

Previous Year Questionपिछले वर्ष का प्रश्न2023
Which is a better conductor?
  1. Nichrome
  2. Iron
  3. Chromium
  4. Nickel
Solutionसमाधान
Among the given options, Chromium has lower resistivity compared to Nichrome (an alloy of nickel and chromium). Chromium is a better conductor than Nichrome, Nickel, and Iron among these choices.

Solving path: Eliminate on knowledge of material types. Nichrome is a nickel-chromium alloy — it has high resistivity by design (used in heaters). Chromium as a pure metal has significantly lower resistivity than the alloy Nichrome. Between iron, nickel, and chromium as pure metals, chromium has the lowest resistivity among these options. Answer: Chromium.


Why this question: Classic P = I²R application. The two-step structure (find P first, then R) is the standard format Bihar Police uses for heater/appliance numericals.

Previous Year Questionपिछले वर्ष का प्रश्न2023
An electric heater does 200 J of work in 2 seconds. Find the resistance of the heater if the current in the circuit is 2 A.
  1. 25 Ω
  2. 10 Ω
  3. 20 Ω
  4. 5 Ω
Solutionसमाधान
Power = 200/2 = 100 W. Using P = I²R: 100 = (2)² × R = 4R, so R = 25 Ω.

Solving path: Step 1 — Power = Work/Time = 200/2 = 100 W. Step 2 — Use P = I²R: 100 = (2)² × R = 4R. Therefore R = 100/4 = 25 Ω. The trap options (10 Ω, 20 Ω, 5 Ω) catch you if you forget to square the current or use the wrong formula.


Why this question: A direct conceptual question about household wiring — one of the most frequently tested facts in this chapter across multiple state police exams.

Previous Year Questionपिछले वर्ष का प्रश्न2023
The electric appliances in a house are connected
  1. in series
  2. in parallel
  3. either in series or in parallel
  4. both in series and parallel
Solutionसमाधान
Household electrical appliances are connected in parallel so that each appliance gets the same voltage and can be operated independently.

Solving path: The reason is functional: parallel connection ensures each appliance gets the same 220 V regardless of what else is running, and allows independent switching. Series would mean all appliances share one current path — switching one off kills all. Answer: in parallel.


Why this question: Energy unit conversion is the single most common arithmetic trap in electricity questions. This tests whether you correctly convert W to kW before multiplying by hours.

Previous Year Questionपिछले वर्ष का प्रश्न2023
A 100 W electric bulb is used for 10 hours a day. How many units of electrical energy are consumed by the bulb in 3 days? (1 unit = 1 kWh)
  1. 3.00
  2. 1.08
  3. 0.33
  4. 2.16
Solutionसमाधान
Energy = Power × Time = 100 W × (10 × 3) hours = 100 W × 30 h = 3000 Wh = 3.00 kWh = 3 units.

Solving path: Power = 100 W = 0.1 kW. Total time = 10 hours/day × 3 days = 30 hours. Energy = 0.1 kW × 30 h = 3.0 kWh = 3 units. The traps at 1.08 and 2.16 catch you if you calculate for only 1 or 2 days, or forget the kW conversion.


Why this question: This is a multi-statement series circuit question in Hindi — tests voltage division logic and whether you can eliminate false statements quickly.

Previous Year Questionपिछले वर्ष का प्रश्न2012
दो 50 और 100Ω के प्रतिरोध किसी परिपथ में श्रेणीक्रम में जुड़े हैं। निम्न विकल्प संभव हैं (i) दोनों प्रतिरोधों के बीच विभवान्तर अलग-अलग होगा। (ii) दोनों प्रतिरोधों के बीच विभवान्तर समान होगा। (iii) 50 प्रतिरोध के लिये विभवान्तर 100 वाले प्रतिरोध से दुगुना होगा। (iv) 100 प्रतिरोध के लिये विभवान्तर 52 वाले प्रतिरोध से दुगुना होगा। उपर्युक्त विकल्पों में कौन कौन-से विकल्प सही हैं?
दो 50 और 100Ω के प्रतिरोध किसी परिपथ में श्रेणीक्रम में जुड़े हैं। निम्न विकल्प संभव हैं (i) दोनों प्रतिरोधों के बीच विभवान्तर अलग-अलग होगा। (ii) दोनों प्रतिरोधों के बीच विभवान्तर समान होगा। (iii) 50 प्रतिरोध के लिये विभवान्तर 100 वाले प्रतिरोध से दुगुना होगा। (iv) 100 प्रतिरोध के लिये विभवान्तर 52 वाले प्रतिरोध से दुगुना होगा। उपर्युक्त विकल्पों में कौन कौन-से विकल्प सही हैं?
  1. (i) व (iv)
  2. (ii) व (iii)
  3. (i) व (ii)
  4. (ii) व (i)
  1. (i) व (ii)
  2. (ii) व (iii)
  3. (i) व (iv)
  4. (ii) व (i)
Solutionसमाधान
In series circuit, same current flows but voltage is proportional to resistance. So 50Ω and 100Ω will have different voltages (statement i is true). The 100Ω resistor will have double the voltage of 50Ω resistor (statement iv is true). Hence (i) and (iv) are correct.

Solving path: In series, current is the same through both resistors. Voltage across each = I × R, so V₅₀ = 50I and V₁₀₀ = 100I. Statement (i): voltages are different — TRUE. Statement (ii): voltages are equal — FALSE. Statement (iii): V₅₀ is double V₁₀₀ — FALSE (it is half, not double). Statement (iv): V₁₀₀ is double V₅₀ — TRUE. Correct pair: (i) and (iv).

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