Simple Interest for SSC CGL — Formula, Tricks, and PYQ Walkthrough

beginner 15 min read

Concept

Simple Interest (SI) is the most transparent form of interest calculation — the interest earned each year is always the same fixed amount, calculated only on the original principal, never on accumulated interest.

Think of it like a daily-wage contract. If you lend ₹10,000 to a friend at 10% per annum, you earn ₹1,000 every single year. The second year, you still earn ₹1,000 on the same ₹10,000 — your friend doesn't owe you interest on last year's interest. That flat, predictable structure is what makes it "simple."

The core formula is:

SI=P×R×T100SI = \frac{P \times R \times T}{100}

Where:

And the Amount (A) — what you get back at the end — is:

A=P+SI=P+P×R×T100=P(1+RT100)A = P + SI = P + \frac{P \times R \times T}{100} = P\left(1 + \frac{RT}{100}\right)

Here's what makes SSC CGL SI questions tick: they almost never just ask you to calculate SI directly. They give you two of the four variables (P, R, T, SI or A) and ask for the third or fourth. So you need all four derived forms cold:

P=SI×100R×TP = \frac{SI \times 100}{R \times T}

R=SI×100P×TR = \frac{SI \times 100}{P \times T}

T=SI×100P×RT = \frac{SI \times 100}{P \times R}

The questions look different on the surface — "find the rate," "find the principal," "in how many years" — but they all reduce to one of these four forms. Once that clicks, SI becomes a one-line topic.


Deep Dive

The Base Formula and Its Four Avatars

The formula SI=PRT{100}SI = \frac{PRT}\{100\} is the anchor. Every SSC CGL SI question is a manipulation of this single equation. Drill the derived forms until you can write them in your sleep:

| Given | Find | Formula | |---|---|---| | P, R, T | SI | SI=PRT{100}SI = \frac{PRT}\{100\} | | SI, R, T | P | P=SI×100R×TP = \frac{SI \times 100}{R \times T} | | SI, P, T | R | R=SI×100P×TR = \frac{SI \times 100}{P \times T} | | SI, P, R | T | T=SI×100P×RT = \frac{SI \times 100}{P \times R} |

Working with Amount vs. Interest

Look — a very common trap in CGL questions is giving you the Amount (A) and asking about interest or principal. The moment you see "amounts to ₹X," subtract the principal first:

SI=APSI = A - P

Only then plug into the formula. Students who skip this step lose a mark every time.

Example: ₹2,500 amounts to ₹3,250 in 4 years. SI = 3,250 − 2,500 = ₹750. Now find R. Done. Never try to directly substitute A into the SI formula.

The Rate-Time Interchangeability Trick

Here's something CGL setters exploit regularly: if a problem says "rate and time are equal" or gives you a constraint linking R and T, you can substitute one variable. For instance, if R = T = n, then:

SI=P×n×n100=Pn2100SI = \frac{P \times n \times n}{100} = \frac{Pn^2}{100}

This creates a quadratic — but in CGL, the numbers are always clean, so just test the options.

When T is in Months or Days

Always convert before substituting:

Missing this conversion is a free mark lost.

Ratio-Based SI Problems

Some CGL questions state: "SI on a sum for 3 years at 5% equals SI on another sum for 2 years at 6%." These are product problems. You just equate:

P1×3×5=P2×2×6P_1 \times 3 \times 5 = P_2 \times 2 \times 6

15P1=12P2    P1P2=1215=4515P_1 = 12P_2 \implies \frac{P_1}{P_2} = \frac{12}{15} = \frac{4}{5}

No need to find absolute values — the ratio comes directly from the product of R and T.

Difference Between SI and Compound Interest (CI) Over 2 Years

This is a bridge topic that regularly appears in CGL. For 2 years at rate R% on principal P:

CISI=P×(R100)2CI - SI = P \times \left(\frac{R}{100}\right)^2

Know this. It lets you solve CI-vs-SI comparison questions without computing CI from scratch.

Installment-Type SI Problems

Occasionally CGL will ask: "A sum is split into two parts; one earns SI at r₁% and another at r₂%; total interest is ₹X — find the parts." Use the weighted average / alligation approach:

Part1Part2=r2ravgravgr1\frac{\text{Part}_1}{\text{Part}_2} = \frac{r_2 - r_{avg}}{r_{avg} - r_1}

Where ravgr_{avg} is the effective rate derived from total interest and total principal.


Memory Tricks & Shortcuts

patternPRT-over-100 Hand Lock

Write P, R, T in a mental triangle with 100 at the bottom. To find any one of the four quantities, cover it with your finger — what remains is the calculation. Covering SI gives PRT/100. Covering P gives (SI×100)/(R×T). This visual lock eliminates formula confusion entirely. Standard method (recalling four separate formulas): ~20s. This triangle recall: ~4s.

eliminationExtract SI from Amount First

Any question saying "amounts to ₹X" is a two-step question in disguise. Immediately write: SI = Amount − Principal before doing anything else. This single reflex eliminates the most common SSC CGL trap. Students who skip this step solve the wrong problem 40% of the time. Adding this first-step habit reduces errors to near zero with zero extra time cost.

estimationPercent-per-Year as a Fraction

Convert the rate to a decimal fraction immediately. 8% per year = 0.08 per year. For T years, the multiplier on P is simply (1 + 0.08T). For ₹5,000 at 8% for 3 years: multiplier = 1 + 0.24 = 1.24. Amount = 5,000 × 1.24 = ₹6,200. SI = ₹1,200. This decimal-multiplier method works faster than the PRT/100 route when P is a round number: standard method ~40s, multiplier method ~15s.

patternR×T Product Lock for Ratio Questions

For any question comparing two SI situations, forget P, R, T individually — just compute the R×T product for each. Equal SI means equal (P × R × T) products. Equal principal means equal R×T products. This collapses three-variable ratio problems into one multiplication each side: 3 steps instead of 7+. Use when the question says "equal interest" or "equal principal" with two different rate-time pairs.

substitutionBackwards from Options Using 10% Anchor

When finding rate and options are given, test the middle option first (not option A). Compute SI with that rate — if it's too high, eliminate top options; if too low, eliminate bottom. Most CGL SI rate questions resolve in one or two substitutions. This beats the full R = (SI×100)/(P×T) calculation when P×T produces an ugly number: standard calculation ~35s, substitution from options ~15s.


Fast-Solving Framework

When you see an SI question in the exam hall, run this decision tree in order:

Step 1 — Identify what's given and what's asked. Tag each number: is it P, R, T, SI, or A?

Step 2 — Is "amount" mentioned? If yes, extract SI = A − P before anything else. Non-negotiable.

Step 3 — Is T in months or days? Convert to years immediately.

Step 4 — Which formula avatar do you need?

Step 5 — Does the answer match an option? If not, check whether you subtracted A−P, check unit conversion, and verify you didn't use Amount where SI was needed.

Total time target: straightforward SI question in 25−35 seconds. If you're past 45 seconds, substitute options instead of computing.


Solved PYQs

Why this question: Direct SI calculation — the most fundamental question type. Tests whether you can execute PRT/100 cleanly without errors.

Previous Year Questionपिछले वर्ष का प्रश्न
A sum of ₹5,000 is invested at a simple interest rate of 8% per annum. What will be the interest earned after 3 years?
₹5,000 की राशि को 8% प्रति वर्ष की साधारण ब्याज दर पर निवेश किया जाता है। 3 साल बाद कितना ब्याज मिलेगा?
  1. ₹1,000
  2. ₹960
  3. ₹1,500
  4. ₹1,200
  1. ₹1,000
  2. ₹960
  3. ₹1,500
  4. ₹1,200
Solutionसमाधान
Simple Interest = (P × R × T) / 100 = (5000 × 8 × 3) / 100 = 1,20,000 / 100 = ₹1,200.
साधारण ब्याज = (मूलधन × दर × समय) / 100 = (5000 × 8 × 3) / 100 = 1,20,000 / 100 = ₹1,200।

Solving path: P = 5,000, R = 8, T = 3. SI = (5000 × 8 × 3) / 100 = 120,000 / 100 = ₹1,200. Using decimal multiplier: 8% × 3 = 24% of 5,000 = ₹1,200. Both routes under 20 seconds.


Why this question: Tests reverse calculation — "find the rate." The Amount-to-SI extraction step is the critical first move here.

Previous Year Questionपिछले वर्ष का प्रश्न
At what rate of simple interest per annum will ₹2,500 amount to ₹3,250 in 4 years?
किस वार्षिक साधारण ब्याज दर पर ₹2,500 की राशि 4 साल में ₹3,250 हो जाएगी?
  1. 8%
  2. 6%
  3. 7.5%
  4. 10%
  1. 8%
  2. 6%
  3. 7.5%
  4. 10%
Solutionसमाधान
Interest = 3250 − 2500 = ₹750. Rate = (SI × 100) / (P × T) = (750 × 100) / (2500 × 4) = 75000 / 10000 = 7.5% per annum.
ब्याज = 3250 − 2500 = ₹750। दर = (750 × 100) / (2500 × 4) = 75000 / 10000 = 7.5% प्रति वर्ष।

Solving path: Step 1 — extract SI: 3,250 − 2,500 = ₹750. Step 2 — R = (750 × 100) / (2,500 × 4) = 75,000 / 10,000 = 7.5%. Check options — 7.5% is there. Done in ~25 seconds.


Why this question: Classic "find the principal" — tests the inverted formula under time pressure.

Previous Year Questionपिछले वर्ष का प्रश्न
The simple interest on a sum of money at 6% per annum for 2 years is ₹840. What is the principal amount?
किसी राशि पर 6% प्रति वर्ष की दर से 2 साल का साधारण ब्याज ₹840 है। मूलधन कितना है?
  1. ₹7,000
  2. ₹8,400
  3. ₹6,000
  4. ₹5,600
  1. ₹7,000
  2. ₹8,400
  3. ₹6,000
  4. ₹5,600
Solutionसमाधान
Principal = (SI × 100) / (R × T) = (840 × 100) / (6 × 2) = 84,000 / 12 = ₹7,000.
मूलधन = (SI × 100) / (दर × समय) = (840 × 100) / (6 × 2) = 84,000 / 12 = ₹7,000।

Solving path: P = (840 × 100) / (6 × 2) = 84,000 / 12 = ₹7,000. The division 84,000 ÷ 12 — think of it as 84,000 ÷ 12 = 7,000 directly (12 × 7 = 84). No long division needed.


Why this question: Tests the "find time" variant — the least practiced of the four formula avatars, which is exactly why it shows up on CGL.

Previous Year Questionपिछले वर्ष का प्रश्न
In how many years will a sum of ₹6,500 amount to ₹9,100 at a simple interest rate of 10% per annum?
₹6,500 की राशि 10% वार्षिक साधारण ब्याज दर पर कितने सालों में ₹9,100 हो जाएगी?
  1. 6 years
  2. 3 years
  3. 4 years
  4. 5 years
  1. 6 साल
  2. 3 साल
  3. 4 साल
  4. 5 साल
Solutionसमाधान
SI = 9100 - 6500 = ₹2,600. Time = (SI × 100) / (P × R) = (2600 × 100) / (6500 × 10) = 260000 / 65000 = 4 years.
ब्याज = 9100 - 6500 = ₹2,600। समय = (2600 × 100) / (6500 × 10) = 4 वर्ष। अतः 4 वर्षों में राशि ₹9,100 हो जाएगी।

Solving path: SI = 9,100 − 6,500 = ₹2,600. T = (2,600 × 100) / (6,500 × 10) = 260,000 / 65,000 = 4 years. Simplify before multiplying: 2,600/6,500 = 4/10, then 4/10 × 100/10 = 400/100 = 4. Cleaner mental arithmetic.


Why this question: Combines finding SI and then computing Amount — two steps, one question. Tests whether you know Amount = P + SI.

Previous Year Questionपिछले वर्ष का प्रश्न
A person deposits ₹12,000 in a bank at 7.5% per annum simple interest. What will be the amount after 2 years?
एक व्यक्ति बैंक में ₹12,000, 7.5% वार्षिक साधारण ब्याज दर पर जमा करता है। 2 साल बाद कुल राशि कितनी होगी?
  1. ₹13,200
  2. ₹14,400
  3. ₹14,100
  4. ₹13,800
  1. ₹13,200
  2. ₹14,400
  3. ₹14,100
  4. ₹13,800
Solutionसमाधान
SI = (12000 × 7.5 × 2) / 100 = 180000 / 100 = ₹1,800. Amount = 12000 + 1800 = ₹13,800.
साधारण ब्याज = (12000 × 7.5 × 2) / 100 = ₹1,800। कुल राशि = 12000 + 1800 = ₹13,800।

Solving path: SI = (12,000 × 7.5 × 2) / 100. Compute 12,000 × 7.5 = 90,000. Then 90,000 × 2 = 180,000. Divide by 100 = ₹1,800. Amount = 12,000 + 1,800 = ₹13,800. Using decimal multiplier: 7.5% × 2 = 15% of 12,000 = ₹1,800. Same answer, slightly faster mental path.


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