Fractions for SSC MTS — Types, Comparison, and Mixed Number Arithmetic

beginner 18 min read

Concept

A fraction is a way of expressing a part of a whole. Write it as p/q where p is the numerator (how many parts you have) and q is the denominator (how many equal parts the whole is divided into). The denominator can never be zero — dividing into zero parts is undefined.

Think of a pizza cut into 8 equal slices. If you eat 3 slices, you've consumed 3/8 of the pizza. The 8 tells you how the pizza was divided; the 3 tells you what you took.

Types you must know for SSC MTS:

The practical skill SSC MTS tests is not just knowing these definitions — it's being fast at comparing fractions and computing with mixed fractions. Both types appear in almost every MTS paper.


Deep Dive

Converting Between Mixed and Improper Fractions

To convert a mixed fraction a(b/c) to improper form: a(b/c) = (a × c + b) / c

Example: 5(3/4) = (5 × 4 + 3)/4 = 23/4

To convert back from improper to mixed: Divide numerator by denominator. Quotient is the whole number, remainder is the new numerator.

Example: 45/12 — divide 45 by 12: quotient 3, remainder 9. So 45/12 = 3(9/12) = 3(3/4).

Arithmetic with Fractions

Addition and Subtraction — you need a common denominator (LCM of all denominators):

a/p + b/q = (a × q + b × p) / (p × q) when p and q share no common factor.

For mixed fractions, handle the whole-number parts and fractional parts separately, then combine. This is faster than converting everything to improper fractions when the whole numbers are large.

Example: (5 + 2/3) - (3 + 1/6) Step 1: Whole number part: 5 - 3 = 2 Step 2: Fraction part: 2/3 - 1/6 = 4/6 - 1/6 = 3/6 = 1/2 Step 3: Combine: 2 + 1/2 = 2(1/2) — done.

Multiplication: Straight across. (a/b) × (c/d) = ac/bd. Cancel common factors before multiplying to keep numbers small.

Division: Flip the second fraction and multiply. (a/b) ÷ (c/d) = (a/b) × (d/c) = ad/bc.

Comparing Fractions — The Core Exam Skill

Method 1: Common Denominator Convert all fractions to the same denominator (the LCM). Then compare numerators directly.

Example: Compare 7/8, 6/7, 3/4. LCM of 8, 7, 4 = 56. 7/8 = 49/56, 6/7 = 48/56, 3/4 = 42/56. Order: 49 > 48 > 42, so 7/8 > 6/7 > 3/4. Clean.

Method 2: Cross-Multiplication (for two fractions) To compare a/b and c/d, compute a×d vs b×c. If a×d > b×c, then a/b > c/d.

Example: Compare 6/7 and 7/8. 6×8 = 48 vs 7×7 = 49. Since 48 < 49, we have 6/7 < 7/8. Done in 3 seconds.

Method 3: Decimal Conversion Divide numerator by denominator mentally. Best when fractions have denominators 4, 5, 8, 10, 20, 25.

4/5 = 0.80, 9/11 ≈ 0.818, 7/9 ≈ 0.778, 11/13 ≈ 0.846. Largest is 11/13.

Method 4: Complement Method (for fractions close to 1) Look at what each fraction is missing from 1. 1 - 7/8 = 1/8. 1 - 6/7 = 1/7. 1 - 3/4 = 1/4. The fraction with the smallest "deficit" is the largest. 1/8 < 1/7 < 1/4, so 7/8 > 6/7 > 3/4.

This is the fastest method when fractions are all close to 1 — which happens often in SSC MTS.

Fraction-of-a-Group Problems

These appear as word problems. The logic: if 1/5 of girls and 1/8 of boys participated, and you need the fraction of total students, you can't just add 1/5 + 1/8. The denominators represent different group sizes.

The trick is to pick concrete numbers that satisfy the given ratios, compute the participants, then find the fraction of the total. This is covered in the PYQ section below.


Memory Tricks & Shortcuts

patternComplement Method for Near-1 Fractions

When all fractions have numerators just one less than their denominators (like 3/4, 6/7, 7/8, 9/11), compute the "gap" from 1 for each: 1/4, 1/7, 1/8, 1/11 respectively. The fraction with the smallest gap is the largest. You compare unit fractions (bigger denominator = smaller unit fraction) instead of doing LCM. Standard method (LCM of 8,7,4 = 56, convert 3 fractions): ~40 seconds. Complement method: ~10 seconds.

patternSeparate Whole and Fractional Parts for Mixed Arithmetic

When adding or subtracting mixed fractions like 10(2/3) + 3(1/6) - 5(5/6) - 2(1/3), group the whole numbers separately from the fractions. Whole part: 10 + 3 - 5 - 2 = 6. Fraction part: 2/3 + 1/6 - 5/6 - 1/3 = 4/6 + 1/6 - 5/6 - 2/6 = -2/6 = -1/3. Final answer: 6 - 1/3 = 5(2/3). Converting everything to improper fractions first requires handling numbers like 32/3 and 35/6, slowing you down by 3-4 steps.

substitutionPick a Smart Number for Fraction-of-Group Word Problems

When the problem gives fractions of two sub-groups (boys and girls), pick concrete numbers equal to the LCM of the denominators or use the ratio directly. If 2/5 of boys and 3/7 of girls participate, and boys:girls = 5:7, let boys = 5, girls = 7. Participants = 2 + 3 = 5. Total = 12. Fraction = 5/12. This avoids setting up algebraic equations entirely. Standard algebraic approach: ~60 seconds. Number-picking: ~20 seconds.

patternCross-Multiply to Compare Two Fractions Instantly

To decide which of two fractions is larger, cross-multiply and compare. For a/b vs c/d: compute a×d and b×c. The fraction on the side of the larger product wins. Example: Is 70/80 > 84/108? Cross: 70×108 = 7560 vs 80×84 = 6720. Since 7560 > 6720, 70/80 > 84/108. No LCM needed. Standard method (find LCM of 80 and 108 = 2160): ~45 seconds. Cross-multiply: ~15 seconds.

eliminationSimplify Before You Compare

Always reduce fractions to lowest terms before comparing or computing. 84/108 — divide both by 12: 7/9. 42/60 — divide both by 6: 7/10. Now comparing 7/9 vs 7/10 is trivial (same numerator, larger denominator = smaller fraction). This eliminates 2-3 steps of working with large numbers. Works whenever both numerator and denominator share a visible common factor (look for multiples of 2, 3, 5, 7 first).


Fast-Solving Framework

In the exam hall, classify the question type in 3 seconds:

Comparison question (which is largest/smallest/greater than X): → Are all fractions close to 1? Use complement method (fastest). → Only two fractions to compare? Cross-multiply. → Three or more with no obvious pattern? Simplify first, then convert to decimals or find LCM.

Arithmetic question (compute a sum/difference of mixed fractions): → Separate whole numbers from fractions. Add/subtract whole parts. Add/subtract fractional parts using LCM. Combine. → If the fractional part subtraction gives a negative result (e.g., 1/6 - 5/6 = -4/6), borrow 1 from the whole number part.

Word problem with fraction-of-a-group: → Identify the sub-groups and their fractions. → Pick concrete numbers (use the denominator values or given ratio directly). → Count participants, count total, divide.

Always reduce your final answer to lowest terms. SSC MTS options are always simplified — an unsimplified answer won't match any option even if your arithmetic is correct.


Solved PYQs

Why this question: The most fundamental comparison question — tests whether you know a method beyond "convert everything to decimals."

Previous Year Questionपिछले वर्ष का प्रश्न2017
Which of the following is true?
  1. 3/4 > 6/7 > 7/8
  2. 6/7 > 7/8 > 3/4
  3. 7/8 > 6/7 > 3/4
  4. 6/7 > 3/4 > 7/8
Solutionसमाधान
Converting to a common denominator of 56: 7/8=49/56, 6/7=48/56, 3/4=42/56. Since 49>48>42, we have 7/8 > 6/7 > 3/4.

Solving path: The complement method is cleanest here. Deficits from 1: 3/4 is missing 1/4, 6/7 is missing 1/7, 7/8 is missing 1/8. Since 1/8 < 1/7 < 1/4, the order from largest to smallest is 7/8 > 6/7 > 3/4. Match with option C.


Why this question: Classic trap — students instinctively add 1/5 + 1/8 and get 13/40, which is option A (a planted distractor).

Previous Year Questionपिछले वर्ष का प्रश्न2016
In a college, 1/5th of the girls and 1/8th of the boys took part in a social camp. The total number of students in the college took part in the camp is:
  1. 13/80
  2. 13/40
  3. 2/13
  4. 4/15
Solutionसमाधान
Out of every 5 girls, 1 participates; out of every 8 boys, 1 participates. From a group of 5+8=13 students, 1+1=2 participate. So fraction = 2/13.

Solving path: You cannot add 1/5 and 1/8 directly because they apply to different-sized groups. Use concrete numbers: imagine 5 girls and 8 boys (13 students total). Girls participating: 1. Boys participating: 1. Total participating: 2 out of 13. Fraction = 2/13. If you chose 13/40, you fell for the trap.


Why this question: Tests the separate-parts method on a longer expression with four mixed fractions.

Previous Year Questionपिछले वर्ष का प्रश्न2025
10(2/3) + 3(1/6) − 5(5/6) − 2(1/3) = ?
  1. 5(2/3)
  2. 5(1/3)
  3. 6
  4. 8
Solutionसमाधान
Converting: 32/3 + 19/6 − 35/6 − 7/3 = (64+19−35−14)/6 = 34/6 = 5(4/6) = 5(2/3).

Solving path: Whole parts: 10 + 3 - 5 - 2 = 6. Fraction parts: 2/3 + 1/6 - 5/6 - 1/3. Convert to sixths: 4/6 + 1/6 - 5/6 - 2/6 = (4+1-5-2)/6 = -2/6 = -1/3. Combine: 6 - 1/3 = 5(2/3). Match option A.


Why this question: Tests whether you can identify which option exceeds a target fraction — requires simplifying the target first.

Previous Year Questionपिछले वर्ष का प्रश्न2025
Which of the following is greater than 84/108?
  1. 70/80
  2. 14/25
  3. 21/40
  4. 42/60
Solutionसमाधान
84/108 = 7/9 ≈ 0.778. Check options: 42/60 = 0.7, 70/80 = 0.875, 14/25 = 0.56, 21/40 = 0.525. Only 70/80 = 0.875 > 0.778.

Solving path: Simplify 84/108: divide both by 12 to get 7/9 ≈ 0.778. Now scan options. 42/60 = 7/10 = 0.70 — less. 14/25 = 0.56 — less. 21/40 = 0.525 — less. 70/80 = 7/8 = 0.875 — greater. Answer: option A. The simplification step is what makes this fast.


Why this question: Four fractions without the near-1 pattern, so you need a reliable decimal or LCM method.

Previous Year Questionपिछले वर्ष का प्रश्न2025
Which of the following is the largest?
  1. 7/9
  2. 4/5
  3. 9/11
  4. 11/13
Solutionसमाधान
Converting to decimals: 4/5=0.80, 7/9≈0.778, 9/11≈0.818, 11/13≈0.846. The largest is 11/13.

Solving path: Convert each to decimal. 4/5 = 0.800. 7/9 = 0.777.... 9/11 = 0.818.... 11/13 = 0.846.... The largest is 11/13. Note the complement method also works: deficits are 1/5=0.2, 2/9≈0.222, 2/11≈0.182, 2/13≈0.154. Smallest deficit is 2/13, confirming 11/13 is the largest.


Why this question: Combines ratio and fraction-of-a-group — a slightly harder word problem that often trips up students who set up algebraic equations.

Previous Year Questionपिछले वर्ष का प्रश्न
In a school, 2/5 of boys and 3/7 of girls participated in sports. If the ratio of boys to girls is 5:7, what fraction of total students participated?
एक स्कूल में, 2/5 लड़के और 3/7 लड़कियाँ खेल में भाग लीं। यदि लड़कों और लड़कियों का अनुपात 5:7 है, तो कुल छात्रों का कौन सा भाग भाग लेते हैं?
  1. 5/12
  2. 29/60
  3. 19/35
  4. 31/60
  1. 5/12
  2. 29/60
  3. 19/35
  4. 31/60
Solutionसमाधान
Let boys = 5k and girls = 7k (ratio 5:7). Boys participating = 2/5 × 5k = 2k. Girls participating = 3/7 × 7k = 3k. Total participants = 2k + 3k = 5k. Total students = 5k + 7k = 12k. Fraction = 5k/12k = 5/12.
माना लड़के = 5k और लड़कियाँ = 7k (अनुपात 5:7)। खेल में भाग लेने वाले लड़के = 2/5 × 5k = 2k। खेल में भाग लेने वाली लड़कियाँ = 3/7 × 7k = 3k। कुल भाग लेने वाले = 2k + 3k = 5k। कुल छात्र = 5k + 7k = 12k। भिन्न = 5k/12k = 5/12।

Solving path: Boys:Girls = 5:7. Let boys = 5, girls = 7 (total = 12). Boys participating: 2/5 × 5 = 2. Girls participating: 3/7 × 7 = 3. Total participating: 2 + 3 = 5. Fraction = 5/12. The concrete-number approach avoids any algebraic setup.


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