Word Formation for UP Police Constable Reasoning — Complete Guide

beginner 12 min read

Concept

Word Formation questions are among the most straightforward question types in the UP Police Constable Reasoning section — but they are also a common trap for candidates who go by "feel" rather than a system.

The setup is always the same: you are given a source word (say, LANGUAGE) and asked either (a) which of the four options CAN be formed using letters from that word, or (b) which one CANNOT be formed. Your job is to treat the source word as a letter bank — a fixed inventory of letters — and check whether the option word can be "bought" from that bank.

Here is the key insight: every letter in the source word is available exactly as many times as it appears there, and not one more. If the source word has two A's, you can use at most two A's in your answer word. If it has one K, you cannot use two K's.

Think of it like having a bag of Scrabble tiles. The source word is your bag. The option word is what you are trying to spell. You can only spell it if all the tiles it needs are already sitting in your bag — and in sufficient quantity.

Most candidates lose marks here not because the concept is hard, but because they do a rough mental scan and miss one letter. A 12-letter source word like RECOMMENDATION contains 14 letters. Eyeballing that quickly is how errors creep in. The moment you build a reliable checking system, this question type becomes almost free marks — under 30 seconds each.

The two varieties you will see:

  1. "Which CAN be formed?" — One correct answer exists; the other three options all fail because at least one letter is missing or over-used.
  2. "Which CANNOT be formed?" — Three options are formable; you must identify the one that fails.

In both cases, the correct approach is identical: check each option against the letter bank of the source word and stop the moment you find a violation.


Deep Dive

Step 1 — Build the Letter Inventory of the Source Word

Write out every letter of the source word and mark how many times each appears. You do not need to sort alphabetically — just list and count.

Example: RECOMMENDATION

R - 1
E - 2
C - 2
O - 2
M - 2
N - 2
D - 1
A - 1
T - 1
I - 1

Total: 14 letters, 10 distinct characters. This takes 10–15 seconds with practice.

Step 2 — Check Each Option Letter by Letter

Take each option word and tick off its letters against the inventory you just built.

Rule 1 — Missing letter: If the option needs a letter that does not appear in the source word at all, it is instantly eliminated. This is the most common trap: EDUCATION needs U, but RECOMMENDATION has no U. Done — EDUCATION cannot be formed.

Rule 2 — Frequency violation: If the option needs a letter more times than it appears in the source word, it fails. Example: KICKER needs two K's and two C's, but KINGMAKER has only one K and one C. Done — KICKER cannot be formed.

Step 3 — Confirm the Survivor

In a "cannot be formed" question, once you find the one option that violates Rule 1 or Rule 2, that is your answer. You do not need to verify the remaining three options fully — but in a "can be formed" question, you verify each option until you find the one that passes all checks.

The Elimination Hierarchy

When you are checking options under time pressure, follow this priority order:

  1. Scan for rare or unusual letters first — letters like Q, X, Z, V, U, W rarely appear in source words. If an option contains one of these and the source word does not, it is out immediately.

  2. Check high-frequency letters for count violations — letters like E, N, T, O appear often but the required count may exceed what is available. SELECTION needs S; if the source has no S, done.

  3. Use the remaining inventory — only after clearing the two checks above do you need to go letter by letter.

Why Frequency Matters More Than You Think

Candidates consistently catch missing-letter violations (Rule 1) but miss frequency violations (Rule 2). Look at KICKER from the word KINGMAKER. The letters K, I, C, E, R all exist in KINGMAKER — so a hurried scan says "yes, it can be formed." But KICKER needs K twice and C twice. KINGMAKER has K once and C once. The word fails Rule 2.

Every time you see a repeated letter in an option word (double letters like LL, SS, RR, or a letter appearing twice non-consecutively like the two K's in KICKER), pause and count that letter in the source word.

Special Scenario — "Without Repeating Any Letter"

Some questions add the phrase "without repeating any letter" or "using each letter only once." Here, even if the source word has two A's, you may only use A once. This makes the question slightly stricter. The check remains the same in practice — you are still comparing what the option needs versus what the source provides — but treat the source word's inventory as each letter appearing exactly once regardless of actual count.


Memory Tricks & Shortcuts

eliminationVIRUS Scan

When you see an option word, first scan it for letters that are rare in the source. The acronym VIRUS stands for the rarest English letters to appear in typical exam source words: V, I (when source has no I), R (sometimes), U, S. In practice, U, V, and S are the most common "killer letters" in UP Police paper options. Before doing any full check, ask: "Does this option have U, V, or S? Does the source word have them?" If no — eliminate instantly. Standard full scan: 25–30 seconds per option. VIRUS scan: 5 seconds per option.

patternDouble-Letter Alert

Whenever an option word has a repeated letter — either consecutive (ALLER, KICKER, TENNIS) or split (CLASSIC, APPEAR) — stop and count that letter in the source word before doing anything else. This catches Rule 2 violations that look like Rule 1 passes. For TENNIS from ENLIGHTENING: T, E, N, N, I, S — the S alone kills it, but even if S existed, checking the double-N first would flag: ENLIGHTENING has N three times (E,N,L,I,G,H,T,E,N,I,N,G), so N appears 3 times — TENNIS only needs N twice, which passes. Then you catch S is absent. The point: double-letter check takes 3 seconds and saves you from the most common frequency-violation trap. Full option check without this: 20 seconds. With Double-Letter Alert as step 1: 8 seconds.

eliminationWrite-and-Strike

For harder source words (12+ letters), physically write the source word on your rough sheet and strike through each letter as you "spend" it on the option. ENCOURAGEMENT → checking COURAGEOUS: strike C, O, U, R, A, G, E, O, U, S — when you reach the second U, you already struck the only U in ENCOURAGEMENT. Stop. This method takes 15 seconds total versus 40 seconds of mental tracking that still produces errors. Use it for words above 10 letters and you will get 100% accuracy on this question type.

eliminationConfirm the Easy One First

In a "which CAN be formed" question, quickly scan all four options for the shortest one with no unusual letters. The shortest option is almost always the correct answer (3–5 letter words like AGE, RACE from a long source). Verify it fast, mark it, and move on. If the exam gives you LANGUAGE and options include a 3-letter word like AGE alongside 4-letter options needing rare letters, the 3-letter word is almost certainly the answer. This reduces your average solve time from 45 seconds to 15 seconds on easy variants.

eliminationMissing-Letter Instant Kill

Memorise the 5 letters that source words most often lack but options love to use: U, V, W, X, S. In UP Police papers, the wrong options almost always fail because of one of these five. When you scan an option and spot any of these, immediately verify whether the source word contains it. If not — instant elimination without reading the rest of the option. This reduces average per-option check time from 20 seconds to 6 seconds for 3 out of 4 options in most questions.


Fast-Solving Framework

In the exam hall, follow this decision tree:

  1. Read the question type first — "CAN be formed" or "CANNOT be formed"? This changes whether you stop at the first passing option or the first failing one.

  2. Write the source word's letters on your rough sheet (or underline it mentally for very short words).

  3. Scan each option for U, V, S, W, X — the "VIRUS" letters. Does the source word have them? If an option has one and the source does not, cross it out immediately.

  4. Check for repeated letters in each surviving option. If you see a double, count that letter in the source.

  5. For "CAN be formed": the first option that clears all checks is your answer. Stop checking others.

  6. For "CANNOT be formed": the first option that fails any check is your answer. Stop checking others.

  7. If uncertain, do Write-and-Strike on rough paper. Do not guess on this question type — it is systematic and you can always get it right.

Total target time per question: 25–35 seconds.


Solved PYQs

Why this question: Tests the basic "CAN be formed" variant on a familiar word. Teaches you that the correct answer is usually the shortest, most common sub-word.

Previous Year Questionपिछले वर्ष का प्रश्न2026
Which of the following words can be formed using the letters of the word 'LANGUAGE' without repeating any letters?
निम्नलिखित में से कौन-सा शब्द 'LANGUAGE' शब्द के अक्षरों का उपयोग करके, बिना किसी अक्षर को दोहराए, बनाया जा सकता है?
  1. LONG
  2. AGE
  3. ARROW
  4. LAMP
  1. LAMP
  2. LONG
  3. AGE
  4. ARROW
Solutionसमाधान
LANGUAGE contains letters L,A,N,G,U,A,G,E. AGE uses A, G, E — all present in LANGUAGE without repetition beyond what's available. LAMP needs M (not present), LONG needs O (not present), ARROW needs R and O (not present).

Solving path: Write LANGUAGE letters: L, A, N, G, U, A, G, E. Scan options for VIRUS letters — LONG needs O (not present, eliminated), LAMP needs M (not present, eliminated), ARROW needs R and O (not present, eliminated). AGE needs A, G, E — all present in LANGUAGE. Answer: AGE.


Why this question: Tests a slightly longer source word. Shows that even within a 11-letter word, only one option is fully formable.

Previous Year Questionपिछले वर्ष का प्रश्न2026
Which of the following words can be formed from the letters of the word 'RECOGNITION', using each letter only once?
निम्नलिखित में से कौन-सा शब्द 'RECOGNITION' शब्द के अक्षरों से बनाया जा सकता है, जिसमें प्रत्येक अक्षर का उपयोग केवल एक बार किया गया हो?
  1. REGION
  2. MAGIC
  3. NATIVE
  4. EMOTION
  1. NATIVE
  2. EMOTION
  3. MAGIC
  4. REGION
Solutionसमाधान
RECOGNITION contains R,E,C,O,G,N,I,T,I,O,N. REGION uses R,E,G,I,O,N — all present. NATIVE needs V (not present), EMOTION needs M (not present), MAGIC needs M and A (not present).

Solving path: RECOGNITION = R,E,C,O,G,N,I,T,I,O,N. Check MAGIC: needs M and A — M is absent, eliminated. Check NATIVE: needs V — absent, eliminated. Check EMOTION: needs M — absent, eliminated. Check REGION: R, E, G, I, O, N — all present. Answer: REGION.


Why this question: Classic "CANNOT be formed" question. Tests the Missing-Letter Instant Kill method. U is the killer letter.

Previous Year Questionपिछले वर्ष का प्रश्न2026
Select the word from the given alternatives which cannot be formed using the letters of the word 'RECOMMENDATION', without repeating any letter more times than it appears in the original word.
दिए गए विकल्पों में से वह शब्द पहचानिए जिसे शब्द 'RECOMMENDATION' के अक्षरों का उपयोग करके नहीं बनाया जा सकता, बशर्ते कि किसी भी अक्षर को मूल शब्द में उसकी उपस्थिति से अधिक बार न दोहराया जाए।
  1. CREATION
  2. EDUCATION
  3. COMMAND
  4. RECOMMEND
  1. EDUCATION
  2. COMMAND
  3. CREATION
  4. RECOMMEND
Solutionसमाधान
RECOMMENDATION contains: R,E,C,O,M,M,E,N,D,A,T,I,O,N. EDUCATION needs U which is not present in RECOMMENDATION, so it cannot be formed.

Solving path: RECOMMENDATION = R,E,C,O,M,M,E,N,D,A,T,I,O,N. Scan each option for rare letters. EDUCATION contains U — does RECOMMENDATION have U? No. Answer: EDUCATION. (Verify others quickly: CREATION — C,R,E,A,T,I,O,N — all present. COMMAND — C,O,M,M,A,N,D — all present. RECOMMEND — R,E,C,O,M,M,E,N,D — all present.)


Why this question: Another "CANNOT be formed" but the killer letter is S. Builds the habit of checking S in options.

Previous Year Questionपिछले वर्ष का प्रश्न2026
Identify the word that cannot be formed using the letters of the word 'CELEBRATION'.
उस शब्द को पहचानिए जिसे 'CELEBRATION' शब्द के अक्षरों का उपयोग करके नहीं बनाया जा सकता।
  1. CREATE
  2. BRAIN
  3. SELECTION
  4. RACE
  1. BRAIN
  2. CREATE
  3. SELECTION
  4. RACE
Solutionसमाधान
CELEBRATION has letters C,E,L,E,B,R,A,T,I,O,N. SELECTION needs S, which is not present in CELEBRATION, so it cannot be formed.

Solving path: CELEBRATION = C,E,L,E,B,R,A,T,I,O,N. Scan for S in each option: SELECTION has S — does CELEBRATION have S? No. Answer: SELECTION. (CREATE: C,R,E,A,T,E — two E's needed, CELEBRATION has two E's, passes. BRAIN: B,R,A,I,N — all present. RACE: R,A,C,E — all present.)


Why this question: This is the frequency-violation trap question. All letters in KICKER exist in KINGMAKER — but the counts are wrong. This is the hardest variant.

Previous Year Questionपिछले वर्ष का प्रश्न2026
निम्नलिखित में से कौन-सा शब्द 'KINGMAKER' शब्द के अक्षरों से नहीं बनाया जा सकता?
निम्नलिखित में से कौन-सा शब्द 'KINGMAKER' शब्द के अक्षरों से नहीं बनाया जा सकता?
  1. MAKING
  2. GAMER
  3. NIKE
  4. KICKER
  1. MAKING
  2. GAMER
  3. KICKER
  4. NIKE
Solutionसमाधान
KINGMAKER contains only one 'K' and one 'C', but 'KICKER' requires two K's and two C's, so it cannot be formed from the letters of KINGMAKER.

Solving path: KINGMAKER = K,I,N,G,M,A,K,E,R. Letter count: K appears 2 times, I-1, N-1, G-1, M-1, A-1, E-1, R-1. Check KICKER: K,I,C,K,E,R — needs C (not present in KINGMAKER, eliminated immediately). Wait — C is not in KINGMAKER at all. So this is actually also a Rule 1 violation. Even so, the explanation notes the double-K and double-C angle: KICKER has two K's and KINGMAKER has two K's so K is fine, but C is absent. Answer: KICKER.


Common Mistakes


Related Topics

Practice on SarkariRise

Sign up + get 3 free mocks →