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Chemistry Class 12 Electrochemistry Redox Questions for AGNIVEER NAVY

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Why this topic matters · 8 min read
Electrochemistry combines redox chemistry with electron flow in cells. Agniveer Navy SSR/MR exams test galvanic cells, electrode potentials, Faraday's laws, and corrosion prevention — typically 2-3 questions in the 90-minute science paper. High weightage on practical applications like batteries and electroplating. Redox balancing and cell notation are frequent.

Redox Fundamentals

Redox (reduction-oxidation) is the simultaneous loss and gain of electrons. Oxidation is loss of electrons (OIL), reduction is gain of electrons (RIG). Every redox reaction has an oxidizing agent (accepts electrons, gets reduced) and a reducing agent (donates electrons, gets oxidized). In electrochemistry, these reactions are harnessed to produce electrical energy (galvanic cells) or driven by electrical energy (electrolytic cells).

  • Oxidation state rules: element in compound = assigned number reflecting electron distribution
  • OIL RIG mnemonic: Oxidation Is Loss, Reduction Is Gain
  • Oxidizing agent is reduced; reducing agent is oxidized (opposite-sounding but true)
  • Balancing redox: assign oxidation states, identify change, balance electrons using half-reactions
  • Half-reaction method: separate into oxidation and reduction half-reactions, balance atoms and charge, multiply to equalize electrons
Key formulas
Oxidation State Change
Change in OS = Final OS - Initial OS
When: To identify which element is oxidized/reduced in a reaction
Worked example

In Fe2+ + MnO4- reaction: Fe goes from +2 to +3 (oxidized, loses 1e-); Mn goes from +7 to +2 (reduced, gains 5e-). Balance: 5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O

Galvanic (Voltaic) Cells

A galvanic cell spontaneously converts chemical energy into electrical energy using redox reactions. Two half-cells (anode and cathode) connected by a salt bridge allow electron flow through an external circuit. The anode (negative terminal) is where oxidation occurs; the cathode (positive terminal) is where reduction occurs. The salt bridge maintains electrical neutrality by allowing ion flow.

  • Anode = oxidation site (negative in galvanic cell); Cathode = reduction site (positive in galvanic cell)
  • Electrons flow from anode to cathode through external circuit (opposite to conventional current)
  • Salt bridge prevents charge accumulation; contains inert electrolyte (KNO3, KCl)
  • Cell notation: Anode | Anode solution || Cathode solution | Cathode (double line = salt bridge)
  • EMF (electromotive force) = E°cathode - E°anode; positive EMF = spontaneous reaction
Key formulas
Cell EMF
E°cell = E°cathode - E°anode
When: To calculate standard cell potential from electrode potentials
Nernst Equation
E = E° - (0.059/n) log Q [at 25°C]
When: To find cell potential under non-standard conditions; Q = reaction quotient, n = electrons transferred
Worked example

Zn-Cu cell: Zn | Zn2+ || Cu2+ | Cu. Zn is anode (oxidized to Zn2+), Cu is cathode (Cu2+ reduced to Cu). E°cell = 0.34 - (-0.76) = 1.10 V

Electrode Potentials & Standard Reduction Potentials

Standard reduction potential (E°) is the tendency of a species to be reduced. It is measured relative to the standard hydrogen electrode (SHE = 0 V). More positive E° = stronger oxidizing agent (easier to reduce). More negative E° = stronger reducing agent (easier to oxidize). Tables of E° values allow prediction of spontaneity and cell EMF.

  • SHE (Standard Hydrogen Electrode): H+ + e- → 1/2 H2; E° = 0.00 V by definition
  • Higher (more positive) E° = better oxidizing agent; lower (more negative) E° = better reducing agent
  • Spontaneous reaction: E°cell > 0; non-spontaneous: E°cell < 0
  • Reversing a half-reaction reverses the sign of E°
  • E° values are intensive (do not change with stoichiometry); use them directly even if coefficients change

Faraday's Laws of Electrolysis

Faraday's laws quantify the relationship between electrical charge and chemical change. The first law states that the amount of substance deposited/dissolved is proportional to the charge passed. The second law states that for the same charge, the mass deposited is proportional to the molar mass divided by the number of electrons transferred.

  • First Law: mass deposited = (charge × molar mass) / (n × Faraday constant)
  • Faraday constant F = 96500 C/mol (charge of 1 mole of electrons)
  • Charge Q = current I × time t (in coulombs); Q = n × F where n = moles of electrons
  • Second Law: for same charge, mass ∝ (M/z) where M = molar mass, z = electrons transferred
  • Moles of electrons = Q / 96500; use stoichiometry to find moles of product
Key formulas
Faraday's First Law
m = (I × t × M) / (n × F)
When: To find mass of substance deposited/dissolved during electrolysis; m = mass, I = current (A), t = time (s), M = molar mass, n = electrons, F = 96500 C/mol
Charge
Q = I × t
When: To calculate total charge passed in coulombs
Moles of Electrons
n(e-) = Q / F = (I × t) / 96500
When: To find moles of electrons transferred
Worked example

Electroplating Cu: 2 A current for 1 hour. Q = 2 × 3600 = 7200 C. Cu2+ + 2e- → Cu. Moles of e- = 7200/96500 = 0.0746 mol. Moles of Cu = 0.0746/2 = 0.0373 mol. Mass of Cu = 0.0373 × 64 = 2.39 g

Electrolytic Cells & Electroplating

An electrolytic cell uses external electrical energy to drive a non-spontaneous redox reaction. The anode (positive electrode) is where oxidation occurs; the cathode (negative electrode) is where reduction occurs — opposite polarity to galvanic cells. Common applications include electroplating (coating one metal with another), electrorefining, and electrolysis of water/brine.

  • Anode = positive terminal (oxidation); Cathode = negative terminal (reduction) in electrolytic cell
  • Electroplating: object to be plated is cathode; plating metal is anode; electrolyte contains plating metal salt
  • At cathode: reduction (metal ion gains electrons, deposits); at anode: oxidation (anode metal dissolves or water oxidizes)
  • Faraday's laws apply to calculate mass deposited and current-time relationships
  • Overvoltage: extra voltage needed to overcome kinetic barriers; affects which species oxidizes/reduces

Corrosion & Cathodic Protection

Corrosion is unwanted oxidation of metals, typically by oxygen and moisture. Iron rusting is the classic example: Fe is oxidized to Fe2+/Fe3+, O2 is reduced to OH-. Cathodic protection prevents corrosion by making the metal the cathode of a galvanic cell, either by connecting a more active metal (sacrificial anode) or applying external current (impressed current).

  • Rusting requires Fe, O2, and water; occurs faster in acidic/salty environments
  • Sacrificial anode method: connect more active metal (Zn, Mg) to protect Fe; active metal corrodes instead
  • Impressed current method: apply external voltage to make metal cathode; prevents oxidation
  • Passivation: thin oxide layer (e.g., Al2O3 on aluminum) protects underlying metal
  • Galvanizing: coating Fe with Zn layer; Zn acts as sacrificial anode if coating is scratched
⚠ Common mistakes to avoid
  • Confusing anode/cathode polarity between galvanic and electrolytic cells. Remember: in galvanic, anode is negative; in electrolytic, anode is positive. Mnemonic: 'An Ox Red Cat' (Anode Oxidation Reduction Cathode) works for both.
  • Forgetting to reverse the sign of E° when reversing a half-reaction. If you flip the equation, flip the sign of E°.
  • Using E° values with wrong stoichiometry. E° is intensive — do not multiply by coefficients. Only Q (reaction quotient) in Nernst equation depends on stoichiometry.
  • Mixing up oxidation state change with electron transfer. A species with +2 OS losing 1 electron becomes +3 OS; the change in OS equals electrons transferred only if the species is monatomic.
  • In Faraday calculations, forgetting to match electrons transferred (n) to the balanced half-reaction. If Cu2+ + 2e- → Cu, then n = 2, not 1.
🧠 Memory aids
  • OIL RIG: Oxidation Is Loss, Reduction Is Gain — the core of redox chemistry.
  • An Ox Red Cat: Anode Oxidation, Reduction Cathode — works for both galvanic and electrolytic cells if you remember polarity flips.
  • PEMDAS for galvanic cells: Positive (cathode) Electrons Move Down the wire from Anode to external circuit; Spontaneous.
  • FAD: Faraday's law, Amperes (current), Duration (time) — the three variables in electrolysis calculations.
🎯 AGNIVEER NAVY exam tips
  • Agniveer Navy exams frequently ask: 'Which is the anode/cathode?' and 'Calculate mass deposited.' Expect 1-2 Faraday law problems with realistic electroplating or electrorefining scenarios.
  • Cell notation questions are common. Practice writing Zn | Zn2+ || Cu2+ | Cu and identifying which half-reaction is oxidation/reduction.
  • Electrode potential comparisons (E° tables) appear often. Know that more positive E° = stronger oxidizer; use E°cell = E°cathode - E°anode to predict spontaneity.
  • Corrosion and cathodic protection are practical topics the Navy values. Expect 1 question on sacrificial anodes or galvanizing.
  • Time pressure is real in Agniveer exams (90 min for ~60 questions). Pre-memorize Faraday constant (96500 C/mol) and the Nernst coefficient (0.059 at 25°C) to save calculation time.

Sample questions

Q1 · hard · AI-verified
For the cell: Zn | Zn²⁺(0.001 M) || Cu²⁺(0.1 M) | Cu, the E°cell = 1.10 V at 298 K. What is the Ecell using the Nernst equation? (log 100 = 2, R=8.314, T=298 K, F=96500 C/mol)
  1. 1.13 V
  2. 1.10 V
  3. 1.04 V
  4. 1.16 V
Q2 · hard · AI-verified
How many grams of copper will be deposited at the cathode when a current of 2 A is passed through CuSO₄ solution for 965 seconds? (Atomic mass of Cu = 63.5 g/mol, F = 96500 C/mol)
  1. 0.635 g
  2. 0.318 g
  3. 1.270 g
  4. 1.905 g
Q3 · medium · AI-verified
In a galvanic cell, oxidation takes place at which electrode?
  1. Anode
  2. Salt bridge
  3. Cathode
  4. Both anode and cathode
Q4 · medium · AI-verified
During the electrolysis of dilute sulphuric acid (H₂SO₄), which gas is evolved at the cathode?
  1. Hydrogen (H₂)
  2. Oxygen (O₂)
  3. Sulphur dioxide (SO₂)
  4. Hydrogen sulphide (H₂S)
Q5 · medium · AI-verified
How many moles of electrons are transferred when 2 moles of Al³⁺ are completely reduced to Al metal?
  1. 2 mol
  2. 3 mol
  3. 4 mol
  4. 6 mol
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