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Coordinate Geometry Lines and Circles Questions for AGNIVEER NAVY

Free, AI-curated practice for the Coordinate Geometry Lines and Circles section of AGNIVEER NAVY. We have 17+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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Why this topic matters · 8 min read
Lines and circles are the backbone of coordinate geometry in Agniveer Navy SSR/MR maths. Expect 2-3 questions mixing equation of line, distance, slope, and circle properties. Recent papers focus on practical scenarios: finding distance between ship positions, determining if a point lies inside/outside a circular patrol zone, and line intersection problems. Medium difficulty; high accuracy needed.

Equation of a Line

A line in 2D space can be written in multiple forms. The most common are slope-intercept form (y = mx + c) and general form (ax + by + c = 0). In Agniveer exams, you often need to find the equation given two points, a point and slope, or intercepts. Slope m = (y2 - y1)/(x2 - x1) tells you steepness. A horizontal line has slope 0; vertical line has undefined slope.

  • Slope-intercept form: y = mx + c (m = slope, c = y-intercept)
  • Point-slope form: y - y1 = m(x - x1) (use when you have one point and slope)
  • Two-point form: (y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
  • General form: ax + by + c = 0 (standard for distance calculations)
  • Intercept form: x/a + y/b = 1 (a = x-intercept, b = y-intercept)
  • Parallel lines have equal slopes; perpendicular lines have slopes m1 * m2 = -1
Key formulas
Slope between two points
m = (y2 - y1) / (x2 - x1)
When: Finding gradient of a line through two known points
Distance from point to line
d = |ax0 + by0 + c| / sqrt(a^2 + b^2)
When: Finding perpendicular distance from point (x0, y0) to line ax + by + c = 0
Angle between two lines
tan(theta) = |(m1 - m2) / (1 + m1*m2)|
When: Finding angle of intersection between lines with slopes m1 and m2
Worked examples

Find equation of line through (2, 3) and (5, 9). Slope m = (9-3)/(5-2) = 6/3 = 2. Using point-slope: y - 3 = 2(x - 2) => y = 2x - 1 or 2x - y - 1 = 0.

Distance from point (1, 2) to line 3x + 4y - 5 = 0: d = |3(1) + 4(2) - 5| / sqrt(9 + 16) = |3 + 8 - 5| / 5 = 6/5 = 1.2 units.

Equation of a Circle

A circle is the locus of all points equidistant from a fixed point called the center. The standard form is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is center and r is radius. The general form is x^2 + y^2 + 2gx + 2fy + c = 0. In Agniveer, you may need to identify center/radius from general form, or find if a point lies on/inside/outside a circle.

  • Standard form: (x - h)^2 + (y - k)^2 = r^2 (center at (h, k), radius r)
  • General form: x^2 + y^2 + 2gx + 2fy + c = 0 (center at (-g, -f), radius = sqrt(g^2 + f^2 - c))
  • Circle passes through origin if c = 0
  • If point (x0, y0) is on circle: (x0 - h)^2 + (y0 - k)^2 = r^2
  • Point inside circle if distance from center < r; outside if distance > r
  • Equation of circle with diameter endpoints (x1, y1) and (x2, y2): (x - x1)(x - x2) + (y - y1)(y - y2) = 0
Key formulas
Standard circle equation
(x - h)^2 + (y - k)^2 = r^2
When: When center (h, k) and radius r are known
General to standard conversion
Center: (-g, -f), Radius: sqrt(g^2 + f^2 - c)
When: Converting x^2 + y^2 + 2gx + 2fy + c = 0 to standard form
Distance from center to point
d = sqrt((x0 - h)^2 + (y0 - k)^2)
When: Checking if point (x0, y0) is inside, on, or outside circle with center (h, k)
Worked examples

Circle x^2 + y^2 - 4x + 6y - 12 = 0. Here 2g = -4 so g = -2, 2f = 6 so f = 3, c = -12. Center = (2, -3), Radius = sqrt(4 + 9 + 12) = sqrt(25) = 5.

Is point (3, 1) inside circle (x - 1)^2 + (y + 2)^2 = 16? Distance = sqrt((3-1)^2 + (1+2)^2) = sqrt(4 + 9) = sqrt(13) ≈ 3.6. Since 3.6 < 4, point is inside.

Intersection of Line and Circle

When a line intersects a circle, it can touch at 0, 1, or 2 points. If the perpendicular distance from circle center to the line equals the radius, the line is tangent (touches at 1 point). If distance < radius, line cuts the circle at 2 points (secant). If distance > radius, no intersection. Agniveer often asks: does a patrol line intersect a circular zone, or is it tangent?

  • Tangent condition: distance from center to line = radius (1 point of contact)
  • Secant condition: distance from center to line < radius (2 points of contact)
  • No intersection: distance from center to line > radius
  • To find intersection points, substitute line equation into circle equation and solve quadratic
  • Discriminant of quadratic tells number of real solutions: positive = 2 points, zero = 1 point (tangent), negative = no intersection
Key formulas
Tangent condition
Distance from center to line = r
When: Checking if line is tangent to circle
Worked example

Is line x + y = 5 tangent to circle (x - 1)^2 + (y - 1)^2 = 8? Center (1, 1), radius = sqrt(8) = 2√2. Distance = |1 + 1 - 5| / sqrt(2) = 3/sqrt(2) ≈ 2.12. Since 2.12 > 2√2 ≈ 2.83 is false, distance < radius, so line cuts circle at 2 points (not tangent).

Practical Agniveer Scenarios

Agniveer Navy questions often frame geometry in naval context: ship positions as points, patrol zones as circles, navigation routes as lines. You may be asked: distance between two ship positions, whether a ship at point P is within a circular defense zone, or if a straight-line course intersects a restricted circular area. These are direct applications of distance formula, circle equations, and line-circle intersection.

  • Ship position A at (x1, y1), Ship B at (x2, y2): distance = sqrt((x2-x1)^2 + (y2-y1)^2)
  • Patrol zone center at (h, k) with radius r: point (x, y) is safe if sqrt((x-h)^2 + (y-k)^2) > r
  • Navigation route as line ax + by + c = 0: check if it passes through restricted circle
  • Closest point on line to circle center determines if line is tangent, secant, or misses
⚠ Common mistakes to avoid
  • Confusing slope formula order: always (y2 - y1)/(x2 - x1), not reversed. Reversing gives negative reciprocal.
  • In general circle form x^2 + y^2 + 2gx + 2fy + c = 0, forgetting that center is (-g, -f) not (g, f). The negative sign is critical.
  • Forgetting to take square root when converting general form to radius: radius = sqrt(g^2 + f^2 - c), not just g^2 + f^2 - c.
  • Distance formula from point to line: using |ax + by + c| without dividing by sqrt(a^2 + b^2). The denominator is essential.
  • Assuming a line always intersects a circle without checking distance condition first. Always verify distance from center to line vs. radius.
🧠 Memory aids
  • SLOPE = RISE/RUN = (y2 - y1)/(x2 - x1). Think of climbing a hill: rise is vertical, run is horizontal.
  • CIRCLE CENTER from general form: flip the sign of g and f. If equation has +2gx, center x-coordinate is -g.
  • TANGENT = TOUCHING: distance from center to line equals radius. One point of contact only.
  • SECANT = CUTTING: distance from center to line is less than radius. Line cuts through, two points.
  • PERPENDICULAR SLOPES multiply to -1: if m1 = 2, then m2 = -1/2 for perpendicular line.
🎯 AGNIVEER NAVY exam tips
  • Agniveer papers (2022-2024) show 1-2 questions on line equations (finding equation from two points or point-slope form) and 1-2 on circle (identifying center/radius or checking if point is inside). Expect one mixed question combining both.
  • Distance formula (point to line) appears frequently in 'restricted zone' or 'closest approach' scenarios. Practice this formula until you can apply it in 30 seconds.
  • Tangent/secant distinction is tested indirectly: 'Does patrol route intersect defense zone?' Solve by comparing distance to radius.
  • General form of circle is more common in question stems than standard form. Learn the conversion (center = (-g, -f), radius = sqrt(g^2 + f^2 - c)) thoroughly.
  • Time management: line and circle questions are typically 2-3 minutes each if you know formulas. Avoid algebraic errors by double-checking discriminant and distance calculations.

Sample questions

Q1 · medium · AI-verified
What is the radius of the circle whose equation is x² + y² = 49?
  1. √7
  2. 14
  3. 7
  4. 49
Q2 · easy · AI-verified
A line has the equation 2x + 3y = 12. What is its y-intercept?
  1. 3
  2. 6
  3. 4
  4. 2
Q3 · medium · AI-verified
The equation of the circle with centre (1, -3) and radius 5 is:
  1. (x-1)² + (y+3)² = 25
  2. (x-1)² + (y-3)² = 25
  3. (x+1)² + (y-3)² = 25
  4. (x-1)² + (y+3)² = 5
Q4 · easy · AI-verified
What is the slope of the line passing through the points (1, 3) and (4, 9)?
  1. 1
  2. 6
  3. 3
  4. 2
Q5 · medium · AI-verified
Find the equation of the line passing through (2, 3) and parallel to the line 3x - 4y + 5 = 0.
  1. 3x + 4y - 18 = 0
  2. 4x - 3y + 1 = 0
  3. 3x - 4y - 6 = 0
  4. 3x - 4y + 6 = 0
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