Free, AI-curated practice for the Matrices and Determinants section of AGNIVEER NAVY. We have 19+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.
A matrix is a rectangular array of numbers arranged in rows and columns. Think of it like a table of data. The order (or size) of a matrix is written as m x n, where m is rows and n is columns. In Agniveer Navy exams, you'll mostly work with 2x2 and 3x3 matrices. Matrix addition and subtraction are element-wise (add/subtract corresponding entries). Matrix multiplication is trickier: the number of columns in the first matrix must equal the number of rows in the second. The result's element at position (i,j) is the dot product of row i from the first matrix and column j from the second matrix.
If A = [[1,2],[3,4]] and B = [[5,6],[7,8]], then AB[1,1] = 1*5 + 2*7 = 19
Transpose of [[1,2,3],[4,5,6]] is [[1,4],[2,5],[3,6]]
A determinant is a single number calculated from a square matrix. For a 2x2 matrix, it's straightforward: ad - bc. For 3x3, use the expansion method along any row or column (usually the first row or a row with zeros). The determinant tells you if a matrix is invertible (non-zero determinant) and is crucial for solving systems of equations using Cramer's rule. In Agniveer Navy papers, expect direct calculation of determinants and identifying singular (non-invertible) matrices.
For [[2,3],[4,5]], det = 2*5 - 3*4 = 10 - 12 = -2
For [[1,0,2],[0,3,0],[4,0,5]], expanding row 1: 1(3*5-0*0) - 0 + 2(0*0-3*4) = 15 - 24 = -9
Cramer's rule is a method to solve a system of linear equations using determinants. If you have n equations in n unknowns, write the coefficient matrix A and constant vector b. Each unknown x_i equals det(A_i) / det(A), where A_i is A with column i replaced by b. This method is fast for 2x2 and 3x3 systems and appears frequently in Agniveer Navy papers. Only use if det(A) ≠ 0 (unique solution exists).
System: 2x + 3y = 8, 4x + 5y = 14. A = [[2,3],[4,5]], det(A) = -2. A_x = [[8,3],[14,5]], det(A_x) = 40-42 = -2, so x = -2/-2 = 1. A_y = [[2,8],[4,14]], det(A_y) = 28-32 = -4, so y = -4/-2 = 2.
Verify: 2(1) + 3(2) = 8 ✓, 4(1) + 5(2) = 14 ✓
The inverse of a square matrix A, written A^(-1), is the matrix such that AA^(-1) = A^(-1)A = I (identity). For a 2x2 matrix [[a,b],[c,d]], the inverse is (1/det) * [[d,-b],[-c,a]]. For 3x3, use the adjugate method: A^(-1) = (1/det(A)) * adj(A). The adjugate is the transpose of the cofactor matrix. In Agniveer Navy, you may be asked to find the inverse or use it to solve AX = B as X = A^(-1)B.
For [[2,1],[5,3]], det = 6-5 = 1, so A^(-1) = [[3,-1],[-5,2]]
Verify: [[2,1],[5,3]] * [[3,-1],[-5,2]] = [[6-5,-2+2],[15-15,-5+6]] = [[1,0],[0,1]] ✓
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