Free, AI-curated practice for the Vectors and Three D Geometry Basic section of AGNIVEER NAVY. We have 15+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.
A position vector locates a point in 3D space using coordinates (x, y, z). Direction cosines are the cosines of angles a line makes with the three coordinate axes. They always satisfy l² + m² + n² = 1, where l, m, n are direction cosines. Think of direction cosines as 'direction fingerprints' — every line has a unique set. Direction ratios are proportional to direction cosines but don't have to sum to 1.
Direction ratios 1:2:2. Find direction cosines. Answer: l=1/3, m=2/3, n=2/3 (divide each by sqrt(1+4+4)=3)
Point A(1,2,3), point B(4,6,11). Find position vector AB. Answer: AB = 3i + 4j + 8k, magnitude = sqrt(9+16+64) = sqrt(89)
Dot product of two vectors gives a scalar (single number). It measures how much two vectors point in the same direction. If vectors are perpendicular, dot product is zero — this is the key test for perpendicularity. Dot product is commutative: a·b = b·a. Geometrically, a·b = |a||b|cos(θ), where θ is angle between them.
a = 2i + 3j + k, b = i - j + 2k. Find a·b. Answer: 2(1) + 3(-1) + 1(2) = 2 - 3 + 2 = 1
Check if 2i + j - k and i - 2j - 4k are perpendicular. Dot product = 2(1) + 1(-2) + (-1)(-4) = 2 - 2 + 4 = 4 ≠ 0, so NOT perpendicular
Cross product of two vectors gives another vector perpendicular to both. It's anti-commutative: a × b = -(b × a). The magnitude |a × b| = |a||b|sin(θ) equals the area of parallelogram formed by the two vectors. Cross product is zero if vectors are parallel. Use determinant method with i, j, k for calculation.
a = i + 2j + 3k, b = 2i - j + k. Find a × b. Answer: i(2·1 - 3·(-1)) - j(1·1 - 3·2) + k(1·(-1) - 2·2) = i(5) - j(-5) + k(-5) = 5i + 5j - 5k
Distance between two points is straightforward: use the distance formula. Distance from a point to a line requires the perpendicular from the point to the line. Distance between two skew lines (non-parallel, non-intersecting lines in 3D) uses a special formula involving cross product. These are high-frequency exam questions.
Distance between (1,2,3) and (4,6,11): sqrt((4-1)² + (6-2)² + (11-3)²) = sqrt(9+16+64) = sqrt(89)
Line passes through (1,0,0) with direction 1:1:1. Distance from (2,2,2) to this line: Use cross product method. Vector from (1,0,0) to (2,2,2) is (1,2,2). Direction d = (1,1,1). Cross product (1,2,2)×(1,1,1) = (0,1,-1), magnitude sqrt(2). Distance = sqrt(2)/sqrt(3) = sqrt(2/3)
A line in 3D can be written in vector form r = a + λb (where a is position vector of a point, b is direction vector, λ is parameter) or Cartesian form (x-x₁)/l = (y-y₁)/m = (z-z₁)/n. A plane is defined by a normal vector and a point, or by equation ax + by + cz + d = 0. Exam questions often ask for equation of line through two points or plane through three points.
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