Why this topic matters · 9 min read
Mensuration is a high-yield topic in CTET Paper II Math-Science section, typically contributing 3-5 questions per paper. Questions test your ability to apply formulas for 2D shapes (area, perimeter) and 3D solids (volume, surface area). The exam favours direct formula application, unit conversions, and word problems involving cubes, cuboids, cylinders, and triangles. Pedagogy-linked questions may ask how to teach these concepts to Class 6-8 students using hands-on methods.
Area of 2D Shapes
Area is the amount of surface enclosed within a boundary. For Class 6-8, the key shapes are rectangle, square, triangle, parallelogram, trapezium, and circle. CTET often gives a shape and asks you to find area after a dimension change, or asks which formula a teacher should use to introduce the concept of area to students.
- Rectangle: length x breadth
- Square: side x side (or side squared)
- Triangle: half x base x height
- Parallelogram: base x height (height is perpendicular, not the slant side)
- Trapezium: half x (sum of parallel sides) x height
- Circle: pi x radius squared
Key formulas
Rectangle Area
A = l x b
When: Any rectangle or square room/field problem
Triangle Area
A = (1/2) x b x h
When: Triangle problems; h is perpendicular height, not slant
Trapezium Area
A = (1/2) x (a + b) x h
When: Cross-section problems, canal or road problems
Circle Area
A = pi x r^2
When: Circular field, circular base of cylinder
Parallelogram Area
A = b x h
When: Any slanted four-sided figure with opposite sides parallel
Worked examples
A trapezium has parallel sides 12 cm and 8 cm, height 5 cm. Area = (1/2) x (12+8) x 5 = (1/2) x 20 x 5 = 50 sq cm.
A triangle has base 10 m and height 6 m. Area = (1/2) x 10 x 6 = 30 sq m.
Perimeter of 2D Shapes
Perimeter is the total length of the boundary. CTET sometimes disguises perimeter questions as fencing, framing, or border-tile problems. A common trap is mixing up area and perimeter formulas.
- Rectangle: 2 x (l + b)
- Square: 4 x side
- Circle (Circumference): 2 x pi x r
- Triangle: sum of all three sides
- For semi-circle perimeter: pi x r + 2r (diameter + curved part)
Key formulas
Rectangle Perimeter
P = 2(l + b)
When: Fencing, border, wire-around problems
Circumference
C = 2 x pi x r
When: Wheel, circular track distance problems
Worked example
A rectangular garden is 15 m long and 10 m wide. Cost of fencing at Rs 5 per metre = 2(15+10) x 5 = 50 x 5 = Rs 250.
Surface Area of 3D Solids
Surface area is the total area of all outer faces of a solid. CTET distinguishes between Total Surface Area (TSA) which includes all faces, and Lateral (Curved) Surface Area (LSA/CSA) which excludes the top and bottom bases. Exam questions often ask for the area of material needed to make a box (TSA) versus area of the label on a tin (CSA).
- Cuboid TSA: 2(lb + bh + lh)
- Cube TSA: 6 x side squared
- Cylinder TSA: 2 x pi x r x (r + h); CSA: 2 x pi x r x h
- Cone TSA: pi x r x (r + l) where l is slant height; CSA: pi x r x l
- Sphere TSA: 4 x pi x r squared
- Hemisphere TSA: 3 x pi x r squared; CSA: 2 x pi x r squared
Key formulas
Cuboid TSA
2(lb + bh + lh)
When: Wrapping a box, painting a room
Cylinder CSA
2 x pi x r x h
When: Label on a can, painting only side of a pipe
Cylinder TSA
2 x pi x r x (r + h)
When: Making a closed tin cylinder
Sphere TSA
4 x pi x r^2
When: Painting a ball, leather for a ball
Cone Slant Height
l = sqrt(r^2 + h^2)
When: When slant height is not given, derive it first
Worked examples
A closed cylinder has radius 7 cm and height 10 cm. TSA = 2 x (22/7) x 7 x (7 + 10) = 2 x 22 x 17 = 748 sq cm.
Cube with side 5 cm. TSA = 6 x 5^2 = 6 x 25 = 150 sq cm.
Volume of 3D Solids
Volume is the space occupied by a solid. CTET questions on volume often involve finding the number of smaller solids that fit into a larger one (e.g. how many small cubes in a big cuboid), or finding how much water a container holds. Always check units: if dimensions are in cm, volume is in cubic cm.
- Cuboid: l x b x h
- Cube: side cubed
- Cylinder: pi x r squared x h
- Cone: (1/3) x pi x r squared x h
- Sphere: (4/3) x pi x r cubed
- Hemisphere: (2/3) x pi x r cubed
Key formulas
Cuboid Volume
V = l x b x h
When: Box, tank, room capacity
Cylinder Volume
V = pi x r^2 x h
When: Water tank, pipe, candle
Cone Volume
V = (1/3) x pi x r^2 x h
When: Ice-cream cone, funnel — note: 1/3 of cylinder
Sphere Volume
V = (4/3) x pi x r^3
When: Ball, globe problems
Worked examples
A cylindrical tank of radius 3.5 m and height 5 m. Volume = (22/7) x 3.5^2 x 5 = (22/7) x 12.25 x 5 = 192.5 cubic m.
How many small cubes of side 2 cm fit in a cuboid 10 cm x 8 cm x 6 cm? Volume of cuboid = 480 cu cm. Volume of cube = 8 cu cm. Number = 480/8 = 60 cubes.
Unit Conversions (Exam Trap Alert)
CTET frequently hides the real difficulty of a question in unit conversion. Always convert all dimensions to the same unit before applying any formula. Remember: 1 m = 100 cm, so 1 sq m = 10,000 sq cm, and 1 cubic m = 1,000,000 cubic cm. For volume of liquids: 1 litre = 1000 cubic cm.
- 1 m = 100 cm; 1 m^2 = 10,000 cm^2; 1 m^3 = 10^6 cm^3
- 1 litre = 1000 cm^3 (very common in tank/water problems)
- 1 km = 1000 m; 1 hectare = 10,000 m^2
- Always check: answer in sq units for area/surface area, cubic units for volume
Key formulas
Litres to cm^3
1 litre = 1000 cm^3
When: Capacity/water-filling problems
Hectare to m^2
1 hectare = 10,000 m^2
When: Field/land area problems
⚠ Common mistakes to avoid
- Using slant height instead of perpendicular height in the triangle or cone area/volume formula — CTET loves to give slant height and check if you use the right one.
- Confusing CSA and TSA of a cylinder: painting only the curved side uses CSA; making a closed container uses TSA.
- Forgetting the factor of 1/3 in cone volume and 2/3 in hemisphere volume — cone is one-third of the corresponding cylinder.
- Not converting units before calculation, especially when radius is in cm but the answer is asked in litres or metres.
- Mixing up perimeter and area formulas in word problems — fencing = perimeter, painting/tiling = area.
🧠 Memory aids
- CATS for 3D volumes: Cube = s^3, A cylinder = pi r^2 h, Two-thirds hemisphere = (2/3) pi r^3, Sphere = (4/3) pi r^3.
- Cone is CONE-third of cylinder: Volume of cone = (1/3) x Volume of cylinder with same r and h.
- TSA vs CSA: Think of a tin can — CSA is just the label (side only), TSA is label plus top plus bottom lids.
- For trapezium: Average the two parallel sides, then multiply by height. Think of it as a stretched rectangle.
🎯 CTET PAPER II exam tips
- CTET Paper II typically has 2-4 direct mensuration questions in the 30-question Math-Science block. Surface area and volume of cylinders and cuboids appear most frequently across recent papers.
- At least one question is usually a word problem: a tank is filled with water, find time or quantity — these test both volume formula and unit conversion (litres).
- Pedagogy-linked mensuration questions ask how a teacher should introduce area to Class 6 students — the correct answer usually involves activities like covering surfaces with unit squares (constructivist approach).
- Questions involving cones and spheres are less frequent than cuboids and cylinders but do appear — memorise the 1/3 relationship between cone and cylinder as a quick check.
- Time-saving tip: Use pi = 22/7 when radius is a multiple of 7, and pi = 3.14 otherwise. CTET options are usually designed to work cleanly with one of these.
Q1 · hard · AI-verified
A metallic sphere of radius 6 cm is melted and recast into small spheres of radius 1 cm each. How many small spheres can be made?
- 216
- 36
- 108
- 72
Q2 · hard · AI-verified
The perimeter of a semicircle (including the diameter) is 72 cm. What is the area of the semicircle? (Use π = 22/7)
- 616 cm²
- 308 cm²
- 462 cm²
- 154 cm²
Q3 · hard · AI-verified
A parallelogram has a base of 18 cm and a height of 12 cm. A triangle with the same base and height is cut from it. What is the area of the remaining portion?
- 54 cm²
- 108 cm²
- 162 cm²
- 216 cm²
Q4 · hard · AI-verified
The length, breadth, and height of a room are 8 m, 6 m, and 4 m respectively. The cost of painting the four walls at ₹15 per m² is:
- ₹2880
- ₹2160
- ₹1440
- ₹1680
Q5 · hard · AI-verified
Water is flowing through a cylindrical pipe of radius 3.5 cm at a speed of 10 m/s. How much water (in litres) flows through the pipe in 1 minute? (Use π = 22/7; 1 m³ = 1000 litres)
- 2640 litres
- 3080 litres
- 2310 litres
- 1540 litres