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Mensuration Questions for RRB NTPC

Free, AI-curated practice for the Mensuration section of RRB NTPC. We have 30+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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📍 Mensuration is also tested in:
SSC CGL (47)SSC MTS (44)SSC CHSL (30)CDS (19)
Why this topic matters · 9 min read
Mensuration is one of the highest-scoring and most frequently tested topics in RRB NTPC Quant. Expect 3 to 5 questions per attempt, mostly on 2D shapes (rectangle, circle, triangle) and 3D solids (cylinder, cone, sphere, cuboid). Questions test formula recall under time pressure, unit conversions, and combined-shape problems. Difficulty is low to medium — a well-prepared candidate can solve these in under 90 seconds each. Never skip this topic.

2D Shapes: Area and Perimeter

Two-dimensional mensuration deals with flat shapes. You need to memorize area and perimeter formulas cold — there is no time to derive them in the exam. The most tested shapes are rectangle, square, triangle, circle, and trapezium. Watch out for questions that give perimeter and ask for area, or vice versa — these require two steps.

  • Rectangle: Area = length x breadth; Perimeter = 2(l + b)
  • Square: Area = side squared; Perimeter = 4 x side; Diagonal = side x root 2
  • Triangle: Area = half x base x height; for equilateral = (root3 / 4) x side squared
  • Circle: Area = pi x r squared; Circumference = 2 x pi x r
  • Trapezium: Area = half x (sum of parallel sides) x height
  • Rhombus: Area = half x product of diagonals
Key formulas
Rectangle Area
A = l x b
When: Given length and breadth directly
Circle Area
A = pi x r^2
When: Given radius or diameter of a circular field, plate, etc.
Equilateral Triangle Area
A = (sqrt(3)/4) x a^2
When: All three sides are equal
Trapezium Area
A = (1/2) x (a + b) x h
When: Two parallel sides a and b given with height h
Rhombus Area
A = (1/2) x d1 x d2
When: Diagonals d1 and d2 are given
Worked examples

A rectangular park is 60 m long and 40 m wide. Find cost of fencing at Rs 5 per metre. Perimeter = 2(60+40) = 200 m. Cost = 200 x 5 = Rs 1000.

A circle has diameter 14 cm. Area = pi x 7^2 = (22/7) x 49 = 154 sq cm.

3D Shapes: Volume and Surface Area

Three-dimensional mensuration covers solids. RRB NTPC loves cylinder and cuboid questions — often framed as tanks, pipes, or boxes. Key distinction: Total Surface Area (TSA) includes all faces; Curved or Lateral Surface Area (CSA/LSA) excludes the base and top. Volume questions often involve cost of filling or capacity problems.

  • Cuboid: Volume = l x b x h; TSA = 2(lb + bh + lh)
  • Cube: Volume = a cubed; TSA = 6 x a squared; Diagonal = a x root 3
  • Cylinder: Volume = pi x r squared x h; CSA = 2 x pi x r x h; TSA = 2 x pi x r x (r + h)
  • Cone: Volume = one-third x pi x r squared x h; CSA = pi x r x l; where slant height l = root(r squared + h squared)
  • Sphere: Volume = four-thirds x pi x r cubed; TSA = 4 x pi x r squared
  • Hemisphere: Volume = two-thirds x pi x r cubed; CSA = 2 x pi x r squared; TSA = 3 x pi x r squared
Key formulas
Cylinder Volume
V = pi x r^2 x h
When: Tank, pipe, drum capacity problems
Cone Slant Height
l = sqrt(r^2 + h^2)
When: CSA or TSA of cone asked but slant height not given
Sphere Volume
V = (4/3) x pi x r^3
When: Ball, shot-put melting or casting problems
Cube Diagonal
d = a x sqrt(3)
When: Longest diagonal of a cube asked
Hemisphere TSA
TSA = 3 x pi x r^2
When: Bowl with flat base — total surface including flat base
Worked examples

A cylindrical tank has radius 7 m and height 10 m. Volume = (22/7) x 49 x 10 = 1540 cubic metres.

A metallic sphere of radius 3 cm is melted to form a cylinder of radius 3 cm. Find height. Volume of sphere = (4/3) x pi x 27 = 36 pi. pi x 9 x h = 36 pi. h = 4 cm.

Unit Conversions and Scaling

Many NTPC mistakes happen not in formula recall but in unit conversion. Area scales as the square of the linear dimension; volume scales as the cube. If a side doubles, area becomes 4 times, volume becomes 8 times. Questions on 'carpet cost' require converting sq metres to sq cm or vice versa carefully.

  • 1 metre = 100 cm; 1 sq metre = 10000 sq cm; 1 cubic metre = 1000000 cubic cm
  • 1 hectare = 10000 sq metres — used in land area questions
  • If radius doubles: Area becomes 4 times, Volume becomes 8 times
  • If each side of cube is tripled: Volume becomes 27 times
  • Always check whether diameter or radius is given for circle/cylinder/sphere problems
Key formulas
Area Scale Rule
New Area = Old Area x (scale factor)^2
When: Side is scaled by a factor in ratio questions
Volume Scale Rule
New Volume = Old Volume x (scale factor)^3
When: Linear dimensions are scaled uniformly
Worked example

If the side of a square is increased by 20%, new area = old area x (1.2)^2 = 1.44 times old area. So area increases by 44%.

Combined and Composite Shapes

RRB NTPC occasionally asks about shapes made by combining two figures — for example, a cylinder topped with a cone (like a rocket), or a rectangular field with a semicircular end. Strategy: break into known shapes, find each part separately, then add. For hollow cylinders or rings, subtract the inner from the outer.

  • Composite shape area or volume = sum of individual parts
  • Ring (annulus) area = pi x (R squared minus r squared)
  • Hollow cylinder volume = pi x (R squared minus r squared) x h
  • Read the problem carefully to know if both ends are open or closed when finding CSA vs TSA
  • For path-around problems: outer area minus inner area gives path area
Key formulas
Ring Area
A = pi x (R^2 - r^2)
When: Circular path or ring cross-section
Hollow Cylinder Volume
V = pi x (R^2 - r^2) x h
When: Pipe wall volume problems
Worked example

A circular garden of radius 10 m has a path of 2 m around it. Area of path = pi x (12 squared minus 10 squared) = pi x (144 - 100) = 44 pi = 138.16 sq m (approx 138 sq m).

⚠ Common mistakes to avoid
  • Using diameter instead of radius in circle, cylinder, sphere formulas — always halve the diameter first before plugging in.
  • Confusing CSA and TSA for cylinder and cone — if the question says 'sheet needed to make a can with open top', use CSA + one base only.
  • Forgetting to find slant height before computing cone CSA — you must calculate l = root(r squared + h squared) first.
  • Unit mismatch — mixing metres and centimetres in cost-of-tiling problems leads to answers off by factors of 10000.
  • In scaling questions, applying the factor once instead of squaring it for area or cubing it for volume — e.g. if side doubles, area is 4 times NOT 2 times.
🧠 Memory aids
  • Cylinder, Cone, Sphere — CCS: all share pi and r. Cylinder is full, Cone is one-third, Sphere has that 4/3 with r cubed. Remember: C-Full, Co-Third, S-Four-Third.
  • For TSA of hemisphere remember 3: TSA = 3 pi r squared. Think of it as 2 (curved) + 1 (flat base) = 3 parts of pi r squared.
  • PACT mnemonic for 2D shapes: Parallelogram = base x height; Area of circle = pi r squared; Circle Circumference = 2 pi r; Trapezium = half sum of parallels x height.
  • Scaling trick: Area goes up by the SQUARE, Volume goes up by the CUBE. Remember: 2D needs square, 3D needs cube — same as their dimension count.
🎯 RRB NTPC exam tips
  • RRB NTPC Stage 1 typically has 3 to 4 mensuration questions out of 30 Quant questions. Stage 2 may have slightly more with higher difficulty.
  • Circle and cylinder are the most repeated shapes — prioritize these two above all others. Sphere and cone appear occasionally.
  • Questions are often indirect: 'cost of painting', 'volume of water to fill a tank', 'area of a path around a garden' — learn to identify which formula applies from the real-world context.
  • Use pi = 22/7 when radius is a multiple of 7, and pi = 3.14 otherwise — this avoids messy decimals and speeds up calculation.
  • Target time: 60 to 90 seconds per mensuration question. If you cannot recall the formula in 10 seconds, mark for review and move on — do not waste time deriving formulas during the exam.

Sample questions

Q1 · hard · AI-verified
A hollow cylinder has an external radius of 8 cm, internal radius of 6 cm, and height of 14 cm. What is the volume of the material used? (Use π = 22/7)
  1. 1232 cubic cm
  2. 1056 cubic cm
  3. 1408 cubic cm
  4. 924 cubic cm
Q2 · hard · AI-verified
A cone and a hemisphere have the same base radius of 7 cm. If their volumes are equal, what is the height of the cone? (Use π = 22/7)
  1. 14 cm
  2. 21 cm
  3. 28 cm
  4. 7 cm
Q3 · hard · AI-verified
The diagonal of a rhombus are 16 cm and 12 cm. If each side of the rhombus is extended by 25%, what will be the area of the new rhombus formed?
  1. 150 cm²
  2. 200 cm²
  3. 250 cm²
  4. 300 cm²
Q4 · hard · AI-verified
A regular hexagon has a side length of 6 cm. What is the area of the hexagon?
  1. 108 cm²
  2. 72 cm²
  3. 93.6 cm²
  4. 86.4 cm²
Q5 · hard · AI-verified
A cuboid has dimensions 12 cm × 8 cm × 6 cm. What is the length of its space diagonal?
  1. 14√2 cm
  2. 2√61 cm
  3. 16 cm
  4. 12√3 cm
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