Why this topic matters · 10 min read
Geometry is one of the highest-weightage topics in SSC CGL Quant, consistently fetching 4-6 questions per paper. Questions test triangles (similarity, congruence, centres), circles (chords, tangents, angles), quadrilaterals, and basic coordinate geometry. Speed wins here — most questions are solvable in 60-90 seconds if you know the right theorem directly. Expect at least 1-2 questions on triangle centres (incentre, circumcentre, centroid, orthocentre) and 1-2 on tangent-chord-angle relationships in circles every year.
Triangle Basics and Key Theorems
Triangles dominate geometry questions. You must know angle-sum property, exterior angle theorem, and side inequalities cold. The exterior angle of a triangle equals the sum of the two non-adjacent interior angles — this single rule solves dozens of SSC questions directly without full calculation.
- Sum of all angles in a triangle = 180 degrees
- Exterior angle = sum of two remote interior angles
- Sum of any two sides > third side (triangle inequality)
- In a right triangle, the hypotenuse is the longest side
- Pythagoras triples to memorise: 3-4-5, 5-12-13, 8-15-17, 7-24-25
- Median divides a triangle into two equal area triangles
Key formulas
Area (base-height)
Area = (1/2) x base x height
When: When base and corresponding height are given
Area (Heron's formula)
Area = sqrt(s(s-a)(s-b)(s-c)), where s = (a+b+c)/2
When: When all three sides are known but no height
Exterior Angle
Exterior angle = sum of two opposite interior angles
When: Any exterior angle question — fastest shortcut
Worked example
In a triangle, one angle is 70 degrees and the exterior angle at the third vertex is 120 degrees. Find the second angle. Solution: Exterior angle 120 = 70 + second angle, so second angle = 50 degrees. Third angle = 180 - 70 - 50 = 60 degrees.
Triangle Similarity and Congruence
SSC CGL loves questions where two triangles are similar and you must find a missing side or area ratio. The key rule: if triangles are similar with ratio k, their areas are in ratio k squared. Congruence (SSS, SAS, ASA, RHS) occasionally appears in reasoning-style geometry questions.
- AA (Angle-Angle) is the most common similarity criterion in SSC questions
- Corresponding sides of similar triangles are proportional
- Area ratio of similar triangles = square of side ratio
- Basic Proportionality Theorem (BPT): line parallel to one side divides other two sides proportionally
- Mid-point theorem: line joining midpoints of two sides is parallel to third side and half its length
Key formulas
Area ratio
Area1/Area2 = (side1/side2)^2
When: Any question comparing areas of two similar triangles
BPT ratio
AD/DB = AE/EC
When: When a line DE is drawn parallel to BC in triangle ABC
Worked example
Two similar triangles have sides in ratio 3:5. Find the ratio of their areas. Solution: Area ratio = 3^2 : 5^2 = 9 : 25.
Triangle Centres (Most Tested in SSC CGL)
SSC CGL repeatedly asks about the four triangle centres. Remember each centre's definition and its special angle property, especially for incentre and orthocentre — the angle formulas are direct MCQ fodder.
- Centroid: intersection of medians. Divides each median in 2:1 from vertex.
- Incentre: intersection of angle bisectors. Always inside the triangle.
- Circumcentre: intersection of perpendicular bisectors. Equidistant from all vertices.
- Orthocentre: intersection of altitudes. Can be outside (obtuse triangle).
- Incentre angle formula: angle BIC = 90 + (A/2)
- Orthocentre angle formula: angle BOC = 180 - A (where O is orthocentre)
Key formulas
Incentre angle
Angle BIC = 90 + (A/2)
When: I is incentre, angle A is the vertex angle at A
Circumcentre angle
Angle BOC = 2A
When: O is circumcentre — central angle is double inscribed angle
Orthocentre angle
Angle BHC = 180 - A
When: H is orthocentre
Worked example
In triangle ABC, angle A = 50 degrees. If I is the incentre, find angle BIC. Solution: Angle BIC = 90 + 50/2 = 90 + 25 = 115 degrees.
Circles: Chords, Tangents and Angles
Circle questions are extremely frequent. The most tested rules are: tangent is perpendicular to radius at point of contact, two tangents from external point are equal, and the angle in a semicircle is 90 degrees. The inscribed angle theorem (angle at centre = twice angle at circumference) is a single rule that solves a whole category of questions.
- Tangent from external point: two tangents are equal in length
- Tangent-radius angle = 90 degrees always
- Angle in semicircle = 90 degrees (Thales theorem)
- Inscribed angle = half the central angle on same arc
- Angles in same segment are equal
- Cyclic quadrilateral: opposite angles sum to 180 degrees
Key formulas
Central vs Inscribed angle
Central angle = 2 x Inscribed angle (same arc)
When: Any question with angle at centre vs angle at circumference
Tangent-secant from external point
PA^2 = PB x PC
When: PA is tangent, PBC is secant from external point P
Chord intersection inside circle
PA x PB = PC x PD
When: Two chords AB and CD intersect at P inside the circle
Worked example
From external point P, a tangent PT and a secant PBC are drawn. PT = 6 cm, PB = 3 cm. Find PC. Solution: PT^2 = PB x PC => 36 = 3 x PC => PC = 12 cm.
Quadrilaterals and Polygons
SSC tests properties of parallelogram, rhombus, rectangle, square, and trapezium. The diagonal properties and area formulas are the most asked. For regular polygons, the interior angle formula is directly applied in one-step questions.
- Parallelogram: opposite sides equal, diagonals bisect each other
- Rhombus: all sides equal, diagonals bisect at 90 degrees
- Rectangle: all angles 90 degrees, diagonals are equal
- Square: all sides equal + all angles 90 degrees
- Trapezium area = (1/2) x (sum of parallel sides) x height
- Interior angle of regular n-gon = (n-2) x 180 / n
Key formulas
Rhombus area
Area = (1/2) x d1 x d2
When: d1 and d2 are the two diagonals
Trapezium area
Area = (1/2) x (a + b) x h
When: a and b are parallel sides, h is height
Regular polygon interior angle
Interior angle = (n-2) x 180 / n
When: n is number of sides
Worked example
A rhombus has diagonals 10 cm and 24 cm. Find its area. Solution: Area = (1/2) x 10 x 24 = 120 sq cm.
⚠ Common mistakes to avoid
- Confusing incentre and circumcentre angle formulas: Incentre gives 90 + A/2, Circumcentre gives 2A — mixing these costs marks every year.
- Forgetting that the area ratio of similar triangles is the SQUARE of the side ratio, not the ratio itself.
- Assuming orthocentre is always inside the triangle — it goes outside for obtuse triangles and lands on the right-angle vertex for right triangles.
- In tangent-secant problems, using PT = PB instead of PT^2 = PB x PC — a very common algebraic slip under time pressure.
- For cyclic quadrilaterals, adding all four angles instead of using opposite angles sum to 180 degrees.
🧠 Memory aids
- CICO for triangle centres order from always-inside to sometimes-outside: Centroid Inside, Circumcentre can go outside (obtuse), Orthocentre definitely outside (obtuse). Incentre is ALWAYS inside — think I = Inside.
- For incentre angle: BIC = 90 + half of A. Think 'I add 90 and take half' — the incentre is generous, it adds 90.
- Tangent-secant rule: PA squared = near times far (PB is near, PC is far on secant). Square the solo, multiply the pair.
- SRAS mnemonic for rhombus: Sides equal, Right angles at diagonals, Area = half product of diagonals, Sides bisect angles.
🎯 SSC CGL exam tips
- SSC CGL typically places 4-6 geometry questions in Tier 1 Quant. Expect 1-2 on triangle centres (especially incentre angle), 1-2 on circle tangents/chords, and 1 on similar triangles area ratio.
- Triangle centre questions in recent papers (2022-2024) almost always give you one angle and ask for the angle at a specific centre — memorise the three formulas and you solve these in under 30 seconds.
- Circle questions frequently use the tangent-secant power rule or ask for the angle subtended at centre vs circumference. Draw a quick diagram — it reveals the theorem instantly.
- Avoid deriving from scratch under exam pressure. These are theorem-recall questions, not derivation questions. If you cannot recall the theorem in 10 seconds, mark and move on.
- For quadrilateral area questions, check if it is a rhombus first (all sides equal) — the diagonal formula is the fastest route. Trapezium area is the second most tested shape in this category.
Q1 · medium · PYQ 2025
In triangle ABC, medians AD, BE, and CF intersect at the centroid G. What is the ratio of the area of triangle GAB to the area of triangle ABC?
- 1 : 3
- 2 : 3
- 1 : 2
- 1 : 4
Q2 · medium · PYQ 2025
When a transversal intersects two parallel lines, one of the alternate interior angles is 115°. What is the measure of the angle that lies opposite to it on the alternate interior side?
- 65°
- 180°
- 115°
- 90°
Q3 · medium · PYQ 2024
In △ABC, the perimeter is 40 cm, 2AB = BC (BC > AB), and AC – AB = 10 (AC > AB). Find AB.
- 8 cm
- 9 cm
- 7 cm
- 6 cm
Q4 · hard · AI-verified
In triangle ABC, angle A = 60°, side b = 8 cm, and side c = 12 cm. Find the area of the triangle using the sine formula.
- 36 cm²
- 24√3 cm²
- 48 cm²
- 32√3 cm²
Q5 · hard · AI-verified
In a triangle ABC, the sides are in the ratio 3:4:5. If the perimeter is 84 cm, find the area of the triangle.
- 294 cm²
- 420 cm²
- 336 cm²
- 252 cm²