Why this topic matters · 8 min read
Mixtures and Alligation appear in SSC CGL Quant 2-3 times per paper, testing ability to find average price/concentration when combining two or more quantities. High-speed topic: once you master the alligation method, you can solve in 30-45 seconds. Weightage: ~2-3% of Quant. Expect direct application (find average price), reverse problems (split a mixture), and occasionally 3-way mixtures.
Core Concept: What is Alligation?
Alligation is a shortcut method to find the average (mean) price, concentration, or ratio when two or more quantities are mixed. Instead of using weighted average formula every time, alligation gives you a visual box method that's faster. The key insight: if you mix a cheaper item with a costlier item, the average price will always lie between them. Alligation helps you find that exact average and the ratio in which they were mixed.
- Alligation is NOT a new formula—it's a visual shortcut for weighted average
- Works for price, concentration, ratio, speed, or any measurable quantity
- Two types: Alligation Medial (find average) and Alligation Alternate (find ratio)
- SSC CGL mostly tests Alligation Alternate (reverse problem: given average, find ratio)
- Always draw the box diagram—it prevents careless errors
- The method works only when mixing exactly 2 quantities (or treating 3+ as pairs)
Alligation Medial: Finding the Average
This is the straightforward direction. You have two quantities with known prices/concentrations, and you want the average. Example: 10 kg of rice at Rs 50/kg mixed with 15 kg at Rs 60/kg—what's the average price? Use weighted average. Alligation Medial is rarely tested directly in SSC CGL because it's just basic weighted average, but understanding it helps you reverse-engineer Alligation Alternate problems.
- Formula: Average = (Q1 × P1 + Q2 × P2) / (Q1 + Q2)
- Q = quantity, P = price/concentration
- Useful as a check when you solve Alligation Alternate
- Less common in SSC CGL exams—mostly appears as a verification step
Key formulas
Weighted Average
Avg = (Q1 × P1 + Q2 × P2) / (Q1 + Q2)
When: When you know both quantities and both prices, and need the average price
Worked example
10 kg sugar at Rs 8/kg + 15 kg sugar at Rs 12/kg. Average = (10×8 + 15×12)/(10+15) = (80+180)/25 = 260/25 = Rs 10.4/kg
Alligation Alternate: Finding the Ratio (The Real SSC CGL Pattern)
This is what SSC CGL tests 90% of the time. You're given the average price and the two original prices, and you must find the ratio in which they were mixed. The box method is your weapon. Draw a box with the mean (average) in the centre. Write the two prices at the top corners. Subtract diagonally: (Mean - Lower Price) and (Higher Price - Mean). These differences are your ratio. The beauty: it's always inverse—the quantity of cheaper item is proportional to (Mean - Cheaper), and vice versa.
- Box method: Centre = Mean, Corners = Two prices
- Subtract diagonally: differences become the ratio
- Ratio is INVERSE: cheaper item's ratio = (Mean - Cheaper Price), costlier item's ratio = (Costlier Price - Mean)
- Always simplify the ratio to lowest terms
- Works for any measurable quantity: price, concentration, speed, purity
- SSC CGL loves this because it's fast and tests logical thinking
Key formulas
Alligation Alternate Ratio
Q1 : Q2 = (P2 - Mean) : (Mean - P1), where P1 < Mean < P2
When: When you know two prices and the average (mean) price, and need the ratio of quantities mixed
Worked examples
Tea at Rs 40/kg mixed with tea at Rs 60/kg gives average Rs 50/kg. Find ratio. Box: 40 and 60 at corners, 50 in centre. Differences: (50-40)=10 and (60-50)=10. Ratio = 10:10 = 1:1. So equal quantities were mixed.
Rice at Rs 5/kg mixed with rice at Rs 8/kg gives average Rs 6/kg. Differences: (6-5)=1 and (8-6)=2. Ratio = 2:1 (cheaper:costlier). So 2 kg of Rs 5 rice with 1 kg of Rs 8 rice.
Three-Way Mixtures and Replacement Problems
Occasionally SSC CGL throws a 3-way mixture or a replacement problem. For 3-way: treat it as two separate 2-way problems, or use the weighted average formula directly. For replacement: a quantity is removed and replaced with another—this creates a series. If you remove and replace x units from a total of n units, after k operations, the remaining fraction of original = (1 - x/n)^k. These are less frequent but high-value if you know them.
- Three-way mixtures: use weighted average or break into pairs
- Replacement formula: Remaining = Original × (1 - Removed/Total)^(Number of operations)
- Replacement is common in concentration/purity problems
- Always check if the problem is asking for amount removed, amount remaining, or final concentration
- Draw a timeline for replacement problems—prevents confusion
Key formulas
Replacement Series
Final Quantity = Initial × (1 - x/n)^k
When: When a quantity is repeatedly removed and replaced; x = amount removed each time, n = total, k = number of operations
Worked example
A container has 100 L of milk. 10 L is removed and replaced with water. This happens 3 times. Final milk = 100 × (1 - 10/100)^3 = 100 × (0.9)^3 = 100 × 0.729 = 72.9 L
Concentration and Purity Problems
Alligation works identically for concentration (% of pure substance) and purity (% of metal in alloy). A 50% alcohol solution mixed with 80% alcohol solution to get 60% solution—same box method applies. The 'price' is replaced by 'concentration' or 'purity %'. This variant appears 1-2 times per SSC CGL paper. The logic is identical; only the units change.
- Concentration problems use the same alligation box method
- Purity of alloys (gold, silver) follows the same pattern
- Always express concentration as a percentage or decimal before applying the method
- Common trap: forgetting to convert % to decimal or vice versa
- Reverse problem: given final concentration and two original concentrations, find ratio
⚠ Common mistakes to avoid
- Forgetting the ratio is INVERSE: students often write (Mean - Cheaper) : (Costlier - Mean) instead of reversing it. Remember: the cheaper item's quantity is proportional to the gap between mean and cheaper price.
- Not simplifying the ratio: SSC CGL expects simplified form. If you get 10:15, reduce to 2:3. Unsimplified answers are marked wrong.
- Confusing Alligation Medial with Alternate: Medial is forward (find average), Alternate is reverse (find ratio). 90% of SSC CGL tests Alternate.
- Careless arithmetic in the box: students subtract in the wrong direction or forget to subtract diagonally. Always draw the box and label clearly: Mean in centre, prices at corners.
- Misidentifying which price is higher: if you swap P1 and P2, your ratio flips. Always check: is the mean between the two prices? If not, re-read the problem.
- Ignoring units: if the problem mixes kg and litres, convert first. Alligation works on quantities, so units must match.
🧠 Memory aids
- BOX METHOD = ALLIGATION ALTERNATE. Draw a box, put mean in centre, prices at corners, subtract diagonally, ratio is the differences. Inverse relationship: cheaper item gets the larger difference.
- MEAN LIES BETWEEN: The average price always lies between the two original prices. If it doesn't, you've misread the problem.
- DIAGONAL SUBTRACTION: Top-left minus centre, centre minus bottom-left (or vice versa). The differences are your ratio. Think of it as 'distance from mean'.
- REPLACEMENT POWER RULE: (1 - x/n)^k. Each operation multiplies by the same factor. Useful for milk-water, concentration, purity problems over multiple steps.
🎯 SSC CGL exam tips
- SSC CGL Quant papers (Tier 1) typically have 1-2 Alligation Alternate problems in the 25-question set. They appear in the medium difficulty range (Q 12-18 approx). Expect 45-60 seconds per question if you know the method.
- Recent papers (2022-2024) show a shift toward 3-way or replacement variants. If you see 'milk and water' or 'alloy purity', immediately think Alligation.
- Tier 2 (Descriptive) occasionally asks for detailed working. Always show the box diagram—it demonstrates clarity and earns partial credit if arithmetic is slightly off.
- Common SSC CGL twist: 'A mixture of two types of oil costs Rs X. Oil A costs Rs Y, Oil B costs Rs Z. If 10 kg of A is used, how much of B?' Recognize this as Alligation Alternate, find the ratio, then scale to the given quantity.
- Time-saving tip: Once you draw the box and find the ratio, don't recalculate. If the ratio is 3:2 and you need 10 kg total, immediately: 3/(3+2) × 10 = 6 kg of first, 4 kg of second. No need to re-solve.
Q1 · hard · AI-verified
A goldsmith has two gold alloys. Alloy X contains 80% gold and Alloy Y contains 60% gold. If 18 grams of Alloy X is mixed with 12 grams of Alloy Y, what is the percentage of gold in the final alloy?
- 72%
- 70%
- 68%
- 74%
Q2 · medium · PYQ 2014
Gold and copper are mixed to make an alloy. If the ratio required gives 15 times as the mean, with gold at 19 times and copper at 9 times, find the required ratio of gold to copper.
- 3:2
- 2:1
- 2:3
- 1:2
Q3 · hard · AI-verified
Two solutions contain salt dissolved in water. Solution A has 12% salt and Solution B has 8% salt. In what ratio must they be mixed to get a solution with 11% salt?
- 3:1
- 1:2
- 2:1
- 1:3
Q4 · hard · AI-verified
Three types of sugar costing ₹30, ₹35, and ₹50 per kg are mixed in the ratio 3:2:1. What is the cost per kg of the mixture?
- ₹36
- ₹38
- ₹40
- ₹35
Q5 · hard · AI-verified
Two alloys of gold contain gold at 10% and 20% respectively. In what ratio should they be mixed to get an alloy containing 14% gold? If 24 kg of the first alloy is used, how much of the second alloy is needed?
- 16 kg
- 20 kg
- 32 kg
- 24 kg