Sarkari RiseLogin

Probability Theory Questions for SSC CGL

Free, AI-curated practice for the Probability Theory section of SSC CGL. We have 16+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

▶ Start free — SSC CGL mockAll SSC CGL resourcesAlready a user? Sign in →
Why this topic matters · 8 min read
Probability appears in SSC CGL Tier 1 Quant (2-3 questions per paper) and Tier 2 (4-5 questions). Tests basic rules: addition, multiplication, conditional probability, and permutation-based counting. Most questions are moderate difficulty; focus on clear event definition and avoiding double-counting. Weightage ~5-8% of Quant section.

Fundamental Concepts

Probability is the ratio of favorable outcomes to total possible outcomes, always between 0 and 1. Think of it as a fraction: how many ways can your desired event happen, divided by how many total ways can anything happen. Sample space is the set of all possible outcomes. An event is a subset of the sample space. In SSC CGL, you'll mostly work with discrete, finite sample spaces (dice, cards, coins, committees).

  • Probability P(E) = Number of favorable outcomes / Total number of possible outcomes
  • Sample space S = all possible outcomes; Event E is a subset of S
  • Certain event has P = 1; Impossible event has P = 0
  • Complementary event: P(E') = 1 - P(E), where E' is 'not E'
  • Mutually exclusive events cannot happen together: P(A and B) = 0
Key formulas
Basic Probability
P(E) = n(E) / n(S)
When: When all outcomes are equally likely and sample space is finite
Complement Rule
P(E') = 1 - P(E)
When: When it's easier to count 'not happening' than 'happening'
Worked examples

A die is rolled. Find P(getting a number > 4). Favorable outcomes: {5, 6} = 2. Total outcomes = 6. P = 2/6 = 1/3.

A card is drawn from a standard deck. Find P(not a heart). P(heart) = 13/52 = 1/4. P(not heart) = 1 - 1/4 = 3/4.

Addition Rule (OR Events)

When you want the probability of event A OR event B happening, use the addition rule. The key is to avoid double-counting the overlap. If events are mutually exclusive (cannot both happen), the overlap is zero. If they can overlap, subtract the intersection to avoid counting it twice.

  • For any two events: P(A or B) = P(A) + P(B) - P(A and B)
  • For mutually exclusive events: P(A or B) = P(A) + P(B)
  • Mutually exclusive means A and B cannot happen at the same time
  • Common in SSC: drawing cards, selecting committee members with restrictions
Key formulas
Addition Rule (General)
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
When: When events can overlap; subtract intersection to avoid double-counting
Addition Rule (Mutually Exclusive)
P(A ∪ B) = P(A) + P(B)
When: When A and B cannot both occur
Worked examples

A card is drawn. P(King or Heart)? P(King) = 4/52. P(Heart) = 13/52. P(King and Heart) = 1/52. P(King or Heart) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13.

A die is rolled. P(even or prime)? Even: {2,4,6}. Prime: {2,3,5}. Overlap: {2}. P = 3/6 + 3/6 - 1/6 = 5/6.

Multiplication Rule (AND Events)

When you want the probability of event A AND event B both happening, use the multiplication rule. The critical distinction is between independent events (one doesn't affect the other) and dependent events (one's outcome changes the probability of the other). Most SSC questions involve either independent events or clearly stated conditional probabilities.

  • For independent events: P(A and B) = P(A) × P(B)
  • For dependent events: P(A and B) = P(A) × P(B|A), where P(B|A) is conditional probability
  • Independent: coin flips, dice rolls with replacement, separate draws
  • Dependent: drawing cards without replacement, selecting committee members sequentially
Key formulas
Multiplication (Independent)
P(A ∩ B) = P(A) × P(B)
When: When outcome of A does not affect probability of B
Multiplication (Dependent)
P(A ∩ B) = P(A) × P(B|A)
When: When B's probability depends on A occurring first
Worked examples

Two coins are flipped. P(both heads)? Independent events. P(H on coin 1) = 1/2. P(H on coin 2) = 1/2. P(both H) = 1/2 × 1/2 = 1/4.

Two cards drawn without replacement. P(both aces)? P(1st ace) = 4/52. P(2nd ace | 1st was ace) = 3/51. P(both) = 4/52 × 3/51 = 12/2652 = 1/221.

Conditional Probability

Conditional probability is the probability of an event given that another event has already occurred. Notation: P(B|A) means 'probability of B given A has happened.' The sample space shrinks to only outcomes where A is true. SSC CGL often tests this in word problems: 'given that a person is selected from a group with a condition, find probability of another property.'

  • P(B|A) = P(A and B) / P(A), provided P(A) > 0
  • Rearranged: P(A and B) = P(A) × P(B|A)
  • Sample space reduces to only outcomes satisfying the given condition
  • Common in SSC: committee selection, defective items, disease testing scenarios
Key formulas
Conditional Probability
P(B|A) = P(A ∩ B) / P(A)
When: Finding probability of B when A is known to have occurred
Worked examples

A bag has 5 red and 3 blue balls. One red ball is drawn and not replaced. P(2nd ball is red)? P(2nd red | 1st red) = 4/7 (4 red left out of 7 total).

In a group of 100 people, 60 are male and 40 female. 20 males and 10 females wear glasses. P(male | wears glasses)? P(M and G) = 20/100. P(G) = 30/100. P(M|G) = (20/100) / (30/100) = 20/30 = 2/3.

Permutations and Combinations in Probability

Many SSC CGL probability questions require counting favorable and total outcomes using permutations (order matters) or combinations (order doesn't matter). A committee selection uses combinations; arranging people in a line uses permutations. Always identify whether order matters before choosing the counting method.

  • Permutations nPr = n! / (n-r)! — use when order matters (arrangements, sequences)
  • Combinations nCr = n! / (r!(n-r)!) — use when order doesn't matter (selections, committees)
  • In probability: P(E) = (favorable outcomes counted via nCr or nPr) / (total outcomes counted same way)
  • SSC trap: forgetting to use combinations for 'selecting' and permutations for 'arranging'
Key formulas
Permutations
nPr = n! / (n-r)!
When: Counting arrangements where order matters
Combinations
nCr = n! / (r!(n-r)!)
When: Counting selections where order doesn't matter
Worked examples

A committee of 3 is selected from 5 people. Total ways = 5C3 = 10. If we want a specific person included, favorable = 4C2 = 6. P = 6/10 = 3/5.

3 people are arranged in a line from 5 available. Total arrangements = 5P3 = 60. If person A must be first, favorable = 4P2 = 12. P = 12/60 = 1/5.

⚠ Common mistakes to avoid
  • Forgetting to subtract P(A and B) in addition rule — leads to double-counting overlaps. Always ask: 'Can both events happen together?'
  • Confusing independent and dependent events — assuming without replacement is independent, or vice versa. Check the problem statement explicitly.
  • Using permutations when combinations are needed (or vice versa) — 'selecting a committee' needs combinations; 'arranging in order' needs permutations.
  • Misidentifying the sample space — especially in multi-step problems. Redefine sample space carefully after each condition.
  • Calculating conditional probability backwards — P(A|B) is NOT the same as P(B|A). Always read 'given' carefully.
  • Forgetting the complement rule when direct counting is hard — if P(E) is complex, try P(E') = 1 - P(not E) instead.
🧠 Memory aids
  • OR = ADD (with subtraction for overlap). AND = MULTIPLY. Think: 'OR spreads, AND narrows.'
  • DICE acronym for dependent events: Draw, Inspect, Check, Exclude — each step changes the pool.
  • Combinations = Committee (order irrelevant). Permutations = Podium (order matters, 1st/2nd/3rd).
  • Conditional P(B|A) = 'B given A' = shrink sample space to A, then find B within it.
🎯 SSC CGL exam tips
  • SSC CGL Tier 1 typically has 2-3 probability questions, mostly basic addition/multiplication rules or simple permutation-combination counting. Expect 1-2 minutes per question if you know the concept.
  • Tier 2 has 4-5 questions with slightly higher complexity: multi-step conditional probability, committee selection with constraints, or card/dice problems with multiple conditions.
  • Recent papers show a trend toward word-problem style questions rather than abstract notation. Read carefully and define events clearly before calculating.
  • Complement rule is a time-saver in SSC — if a problem asks 'at least one,' use P(at least one) = 1 - P(none). This saves calculation.
  • Always verify your answer is between 0 and 1. If you get a probability > 1 or < 0, you've made an error. Recheck your counting or formula application.

Sample questions

Q1 · hard · AI-verified
Two cards are drawn successively without replacement from a well-shuffled deck of 52 cards. What is the probability that the first card is a King and the second card is an Ace?
  1. 4/2652
  2. 8/663
  3. 1/169
  4. 4/663
Q2 · hard · AI-verified
If P(A/B) = 0.4, P(B) = 0.5, and P(A) = 0.3, what is P(B/A)?
  1. 3/5
  2. 2/3
  3. 1/2
  4. 4/5
Q3 · medium · AI-verified
A bag contains 5 red balls, 3 blue balls, and 2 green balls. If one ball is drawn at random, what is the probability that it is NOT red?
  1. 3/5
  2. 2/5
  3. 1/2 is wrong; it's 3/10
  4. 1/2
Q4 · easy · AI-verified
A fair coin is tossed once. What is the probability of getting a tail?
  1. 0
  2. 1/2
  3. 1
  4. 1/4
Q5 · medium · AI-verified
Two dice are thrown simultaneously. What is the probability of getting a sum of 8?
  1. 1/6
  2. 5/36
  3. 7/36
  4. 4/36
💡 Want answers + explanations + 11+ more Probability Theory questions? Sign up free →
⭐ Recommended for SSC CGL aspirants

Full AI 6-Month

all your target exams · 6 months · unlimited mocks + AI
₹799~₹4.4/day
Sign up free, then unlockSee all plans →

More SSC CGL topics

One Word Substitution
277+ practice questions
Idioms and Phrases
264+ practice questions
Fill in the Blanks
252+ practice questions
Spotting Errors
229+ practice questions
Antonyms
228+ practice questions
Synonyms
215+ practice questions

Free practice, AI explanations, 24 exams — all in one app

Daily 10-Q quiz · AI doubt solver in Hindi + English · adaptive mocks · 49,000+ practice questions (19,000+ verified PYQs).

Sign up freePricingTry Daily 10-Q