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Time, Speed and Distance Questions for SSC CGL

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📍 Time, Speed and Distance is also tested in:
SSC MTS (20)CDS (14)
Why this topic matters · 8 min read
Time, Speed and Distance is a high-frequency Quant topic in SSC CGL Tier 1 and Tier 2, typically appearing in 2-3 questions per paper. Tests include basic formula application, relative speed (trains/boats), average speed, and multi-leg journey problems. Aspirants must master unit conversion and relative motion concepts to score quickly under exam pressure.

Core Relationship and Unit Conversion

Speed is the rate at which distance is covered per unit time. The fundamental relationship is Distance = Speed × Time. In SSC CGL, questions often mix units (km/h, m/s, km/min) to test conversion skill. Remember: 1 km/h = 5/18 m/s and 1 m/s = 18/5 km/h. This conversion is tested almost every exam cycle. Always convert to consistent units before solving.

  • Distance = Speed × Time (rearrange as needed)
  • To convert km/h to m/s: multiply by 5/18
  • To convert m/s to km/h: multiply by 18/5
  • Always check units before substituting into formulas
  • Speed is always positive; direction is handled separately in relative motion
Key formulas
Basic Distance Formula
D = S × T
When: Finding distance, speed, or time in straightforward problems
km/h to m/s Conversion
Speed(m/s) = Speed(km/h) × 5/18
When: Converting speed from km/h to m/s for consistency
m/s to km/h Conversion
Speed(km/h) = Speed(m/s) × 18/5
When: Converting speed from m/s to km/h
Worked examples

A car travels 120 km in 2 hours. Speed = 120/2 = 60 km/h. Convert to m/s: 60 × 5/18 = 50/3 ≈ 16.67 m/s.

A train moves at 15 m/s. Convert to km/h: 15 × 18/5 = 54 km/h.

Relative Speed: Trains and Objects

When two objects move, their relative speed depends on direction. If moving in same direction, relative speed = difference of speeds. If moving in opposite directions, relative speed = sum of speeds. This is the most tested concept in SSC CGL. Train problems often ask about crossing platforms, poles, or other trains. When a train crosses a pole, it travels its own length. When crossing a platform or another train, it travels its length plus the other object's length.

  • Same direction: Relative Speed = S1 - S2 (faster minus slower)
  • Opposite direction: Relative Speed = S1 + S2
  • Train crossing pole: Distance = Length of train only
  • Train crossing platform/bridge: Distance = Length of train + Length of platform
  • Train crossing another train: Distance = Sum of both train lengths
  • Time to cross = Distance / Relative Speed
Key formulas
Relative Speed (Same Direction)
RS = |S1 - S2|
When: Two objects moving in same direction
Relative Speed (Opposite Direction)
RS = S1 + S2
When: Two objects moving towards each other
Time to Cross
T = (L1 + L2) / RS
When: Finding time for one object to completely cross another
Worked examples

Train A (100 m) at 60 km/h crosses a pole in: T = 100 / (60 × 5/18) = 100 / (50/3) = 6 seconds.

Train A (100 m) at 60 km/h and Train B (150 m) at 40 km/h move towards each other. RS = 60 + 40 = 100 km/h = 250/9 m/s. Time to cross = (100 + 150) / (250/9) = 250 × 9/250 = 9 seconds.

Average Speed and Multi-Leg Journeys

Average speed is NOT the arithmetic mean of speeds. It is total distance divided by total time. This is a critical trap in SSC CGL. When someone travels different distances at different speeds, or same distance at different speeds, you must calculate total distance and total time separately. A common variant: same distance covered at two different speeds — use harmonic mean formula.

  • Average Speed = Total Distance / Total Time (not average of speeds)
  • For same distance at two speeds: Avg Speed = 2S1×S2 / (S1 + S2) (harmonic mean)
  • For different distances: Add all distances, add all times, then divide
  • Harmonic mean applies only when distances are equal
  • Always verify units are consistent across all legs
Key formulas
Average Speed (General)
Avg Speed = Total Distance / Total Time
When: Multi-leg journey with varying speeds and distances
Average Speed (Equal Distances)
Avg Speed = 2S1×S2 / (S1 + S2)
When: Same distance covered at two different speeds
Worked examples

A person travels 100 km at 50 km/h, then 100 km at 100 km/h. Time1 = 100/50 = 2 hrs, Time2 = 100/100 = 1 hr. Avg Speed = 200/3 ≈ 66.67 km/h. (NOT 75 km/h, which is the arithmetic mean.)

A car travels 60 km at 40 km/h and 60 km at 60 km/h. Using harmonic mean: Avg = 2×40×60 / (40+60) = 4800/100 = 48 km/h.

Boats and Streams (Relative Speed in Fluids)

Boat problems are variations of relative speed. Downstream: boat speed + stream speed. Upstream: boat speed - stream speed. The stream adds or subtracts from the boat's effective speed. This is tested frequently in Tier 1. Key insight: if a boat takes time T1 downstream and T2 upstream for the same distance, you can set up equations to find boat speed and stream speed separately.

  • Downstream speed = Boat speed + Stream speed
  • Upstream speed = Boat speed - Stream speed
  • Time downstream < Time upstream (for same distance)
  • If speeds are given, use relative speed formula directly
  • If times are given, set up equations: D = (B+S)×T1 = (B-S)×T2
Key formulas
Downstream Speed
S_down = B + S_stream
When: Boat moving with the current
Upstream Speed
S_up = B - S_stream
When: Boat moving against the current
Boat Speed (from times)
B = (S_up + S_down) / 2
When: Deriving boat speed from upstream and downstream speeds
Worked examples

A boat's speed in still water is 10 m/s, stream speed is 2 m/s. Downstream = 10+2 = 12 m/s, Upstream = 10-2 = 8 m/s.

A boat covers 60 km downstream in 3 hours and 60 km upstream in 5 hours. S_down = 60/3 = 20 km/h, S_up = 60/5 = 12 km/h. Boat speed = (20+12)/2 = 16 km/h, Stream speed = (20-12)/2 = 4 km/h.

⚠ Common mistakes to avoid
  • Confusing average speed with arithmetic mean of speeds. Always use Total Distance / Total Time.
  • Forgetting to convert units before calculation. A 60 km/h speed and a 10 m/s speed cannot be directly compared or added without conversion.
  • In train crossing problems, forgetting to add both train lengths when two trains cross each other. Only the pole case uses single train length.
  • Misapplying harmonic mean formula when distances are unequal. Harmonic mean works ONLY for equal distances at different speeds.
  • In boat problems, subtracting stream speed incorrectly. Upstream is always (Boat - Stream), not (Stream - Boat).
🧠 Memory aids
  • DeST: Distance = Speed × Time. Rearrange as needed (D/S = T, D/T = S).
  • SODA: Same direction = Opposite (subtract), Opposite direction = Add. Helps recall relative speed rules.
  • 5/18 Magic: km/h to m/s multiply by 5/18; m/s to km/h multiply by 18/5. These are reciprocals.
  • Harmonic Mean Trick: Equal distances, different speeds → use 2S1×S2/(S1+S2). Unequal distances → use Total D / Total T.
  • Boats: Down = B+S, Up = B-S. Think of stream as helper (down) or obstacle (up).
🎯 SSC CGL exam tips
  • SSC CGL Tier 1 typically has 1-2 straightforward TSD questions (basic formula, unit conversion, or simple relative speed). Solve in under 90 seconds.
  • Tier 2 (Maths) has 2-3 questions, often combining TSD with algebra. Expect multi-leg journeys or boat-stream problems requiring equation setup.
  • Train crossing problems are almost guaranteed. Practice pole, platform, and train-crossing variants. These appear in 60% of papers.
  • Average speed trap is very common. Examiners deliberately give arithmetic mean as a distractor. Always calculate Total D / Total T.
  • Recent papers show increased focus on boats/streams and relative speed of two moving objects. Less emphasis on pure distance-time graphs.

Sample questions

Q1 · hard · AI-verified
A train 250 m long traveling at 72 km/h takes 30 seconds to completely cross a bridge. What is the length of the bridge?
  1. 600 m
  2. 350 m
  3. 400 m
  4. 300 m
Q2 · medium · PYQ 2021
A train covers the distance between two stations in a certain time. If speed is (b−a) km/h it arrives 24 minutes late and if speed is (b+a) km/h it arrives 24 minutes early. If b = 20 km/h, find the value of a.
  1. 5 km/hr
  2. 4 km/hr
  3. 2 km/hr
  4. 3 km/hr
Q3 · hard · AI-verified
A boat takes 6 hours to travel 120 km downstream and 8 hours to travel the same distance upstream. What is the speed of the current?
  1. 2 km/h
  2. 2.5 km/h
  3. 5 km/h
  4. 3 km/h
Q4 · medium · PYQ 2024
A thief is running at 12 km/h and a policeman chases at 15 km/h. The thief has a head start of 600 m. How long will the policeman take to catch the thief?
  1. 10 minutes
  2. 8 minutes
  3. 15 minutes
  4. 12 minutes
Q5 · medium · PYQ 2012
Two trains are moving in the same direction at 11 kmph and 10 kmph. If the faster train is 200 metres long, how far ahead of the slower train's engine is the faster train's engine after 6 minutes?
  1. 50 metres
  2. 100 metres
  3. 125 metres
  4. 75 metres
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