Why this topic matters · 8 min read
Number System is one of the most tested Quant topics in SSC CHSL, appearing directly in 2-4 questions per paper and indirectly in many others. Questions focus on divisibility rules, HCF/LCM, remainders, types of numbers, unit digits, and number of factors. Difficulty is easy to moderate — a prepared student can score full marks here in under 4 minutes.
Types of Numbers
Numbers are classified based on their properties. Knowing the definitions quickly helps you answer classification and true/false type questions in SSC CHSL without wasting time.
- Natural Numbers: 1, 2, 3, ... (counting numbers, starts at 1)
- Whole Numbers: 0, 1, 2, 3, ... (natural numbers + zero)
- Integers: ...-2, -1, 0, 1, 2... (includes negatives)
- Rational Numbers: can be written as p/q where q is not zero (includes fractions, terminating decimals)
- Irrational Numbers: cannot be written as p/q — examples are root 2, root 3, pi
- Prime Numbers: exactly 2 factors — 1 and itself. Note: 1 is NOT prime, 2 is the only even prime
Divisibility Rules
SSC CHSL directly asks which number is divisible by 4, 8, 11, etc. Memorise these rules cold — they save time and prevent silly errors. Divisibility by 7 is rarely tested so skip it.
- Div by 2: last digit even
- Div by 3: sum of digits divisible by 3
- Div by 4: last two digits divisible by 4
- Div by 8: last three digits divisible by 8
- Div by 9: sum of digits divisible by 9
- Div by 11: (sum of digits at odd positions) minus (sum of digits at even positions) = 0 or divisible by 11
HCF and LCM
Highest Common Factor (HCF) is the largest number that divides both numbers. Lowest Common Multiple (LCM) is the smallest number divisible by both. These are tested in word problems about bells ringing together, cutting ropes, tiling floors, etc.
- For two numbers: HCF x LCM = Product of the two numbers
- HCF is always less than or equal to the smaller number
- LCM is always greater than or equal to the larger number
- Fractions: HCF of fractions = HCF of numerators / LCM of denominators
- Fractions: LCM of fractions = LCM of numerators / HCF of denominators
Key formulas
HCF x LCM relationship
HCF(a,b) x LCM(a,b) = a x b
When: Use when one of HCF, LCM, or one number is missing and you need to find the other
Worked examples
HCF of 12 and 18: Factors of 12 = 1,2,3,4,6,12. Factors of 18 = 1,2,3,6,9,18. Common factors = 1,2,3,6. HCF = 6.
LCM of 4 and 6: HCF = 2. LCM = (4 x 6) / 2 = 24 / 2 = 12.
Remainder and Divisibility Tricks
Remainder questions are a favourite in SSC CHSL. The most common pattern: a number leaves remainder R when divided by D — find remainder when divided by another number. Also tested: what value of x makes the expression divisible by a number.
- If N = D x Q + R, then R is the remainder (0 <= R < D)
- Remainder of (a + b) divided by n = (remainder of a + remainder of b) divided by n
- Remainder of (a x b) divided by n = (remainder of a x remainder of b) divided by n
- A number divisible by both 4 and 9 is also divisible by 36 (LCM of 4 and 9)
Key formulas
Remainder of a power
a^n mod m — reduce a mod m first, then raise to power n
When: Use for questions like: find remainder when 7^50 is divided by 5
Worked example
Remainder when 7^50 is divided by 5: 7 mod 5 = 2. So find 2^50 mod 5. Pattern: 2^1=2, 2^2=4, 2^3=3, 2^4=1 (mod 5), cycle of 4. 50 divided by 4 = remainder 2. So answer = 2^2 mod 5 = 4.
Unit Digit Problems
SSC CHSL regularly asks: what is the unit digit of a large power like 7^84 or 3^100? Unit digits of powers follow a cycle. Memorise the cycle lengths and you can solve in under 30 seconds.
- Digits 0, 1, 5, 6 always give the same unit digit regardless of power
- Digit 4: cycle is 4, 6 (odd power = 4, even power = 6)
- Digit 9: cycle is 9, 1 (odd power = 9, even power = 1)
- Digits 2, 3, 7, 8: cycle of 4 — divide the power by 4 and use the remainder
- Cycle for 2: 2, 4, 8, 6. Cycle for 3: 3, 9, 7, 1. Cycle for 7: 7, 9, 3, 1. Cycle for 8: 8, 4, 2, 6
Worked examples
Unit digit of 7^84: Cycle of 7 is 4. 84 divided by 4 = remainder 0. When remainder is 0, take the 4th value in cycle. Cycle of 7 = 7,9,3,1. 4th value = 1. Answer: 1.
Unit digit of 3^51: 51 divided by 4 = remainder 3. 3rd value in cycle 3,9,7,1 = 7. Answer: 7.
Number of Factors
Questions asking how many factors (divisors) a number has are asked occasionally in SSC CHSL. The method uses prime factorisation.
- Step 1: Write the number as a product of prime factors — N = p^a x q^b x r^c
- Step 2: Number of factors = (a+1)(b+1)(c+1)
- Number of odd factors: ignore the power of 2 in the factorisation, apply formula to remaining primes
- A perfect square always has an odd number of factors
Key formulas
Total Factors
If N = p^a x q^b x r^c, then Total Factors = (a+1)(b+1)(c+1)
When: Use when asked how many divisors or factors a number has
Worked example
Number of factors of 360: 360 = 2^3 x 3^2 x 5^1. Factors = (3+1)(2+1)(1+1) = 4 x 3 x 2 = 24.
⚠ Common mistakes to avoid
- Treating 1 as a prime number — it is NOT prime. 2 is the smallest and only even prime number.
- In HCF x LCM = a x b, this formula works ONLY for two numbers, not three or more numbers.
- In unit digit of powers, when the power is exactly divisible by 4 (remainder 0), many students pick the 0th term instead of the 4th term of the cycle.
- Confusing divisibility by 4 (check last two digits) with divisibility by 8 (check last three digits) — a common exam trap is to give a number like 1312 and ask divisibility by 8.
- In remainder problems, forgetting that remainder must be non-negative and less than the divisor — writing negative remainders is a mistake.
🧠 Memory aids
- WHOLE = NATURAL + ZERO. Think: a WHOLE roti includes the NATURAL ingredients plus the ZERO (the hole in a donut).
- For divisibility by 11, remember ODD minus EVEN = 0 or 11. Shortcut word: OMEO (Odd Minus Even is the Operation).
- Unit digit cycles of 2, 3, 7, 8 all repeat every 4 steps — remember the phrase FOUR IS THE FLOOR for these four digits.
- HCF x LCM = Product — think of it as a SEESAW: if HCF goes up, LCM must come down to keep the product balanced.
🎯 SSC CHSL exam tips
- SSC CHSL typically has 2 to 4 direct Number System questions per paper. Unit digit and divisibility questions appear almost every year — prioritise these two.
- HCF/LCM word problems are set in real-life contexts like traffic lights blinking, bells ringing, or workers completing tasks together — recognise the pattern and apply formula immediately.
- Remainder questions involving large powers (like 17^30 divided by 7) appear at moderate difficulty — practice the modular arithmetic trick of reducing the base first.
- Do not spend more than 45 seconds on any Number System question in the exam. If you are stuck on a remainder or factor question, skip and return — these are solvable but time-consuming if formula is forgotten.
- Negative marking is 0.5 marks in SSC CHSL. For divisibility questions you should be near 100 percent accurate since rules are fixed — never guess here.
Q1 · hard · AI-verified
How many positive integers less than 1000 are coprime to 210?
- 504
- 432
- 456
- 480
Q2 · hard · AI-verified
How many factors of 7200 are perfect squares?
- 6
- 8
- 12
- 9
Q3 · hard · AI-verified
A number when divided by 357 gives remainder 39. What will be the remainder when the same number is divided by 17?
- 5
- 7
- 9
- 11
Q4 · medium · PYQ 2025
Which number is NOT real?
- √7
- -√7
- 1/√7
- √-7
Q5 · medium · PYQ 2025
The largest four-digit number which when divided by 4, 7, or 13 leaves a remainder of 3 in each case is:
- 9893
- 9831
- 8739
- 9834