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Compound Interest Questions for UP POLICE CONSTABLE

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📍 Compound Interest is also tested in:
SSC CGL (42)SSC MTS (14)CDS (11)
Why this topic matters · 7 min read
Compound Interest is a high-frequency topic in UP Police Constable exams, appearing in 2-3 questions per paper. It tests your ability to calculate interest that 'earns interest' — critical for banking/financial scenarios. Expect direct formula application, comparison with simple interest, and time-period variations. Difficulty: moderate; most aspirants lose marks due to formula confusion and careless calculation, not conceptual gaps.

What is Compound Interest?

Compound interest is interest calculated on both the principal AND the previously earned interest. Think of it like a snowball rolling downhill — it gets bigger and bigger because the snow (interest) keeps adding to itself. In Simple Interest, you earn the same amount every year. In Compound Interest, you earn MORE each year because the base keeps growing. Banks use compound interest because it benefits them; it's also used in loans, investments, and population growth calculations.

  • Principal (P) = original amount you invest or borrow
  • Rate (R) = interest percentage per year
  • Time (T) = number of years
  • Amount (A) = Principal + Compound Interest
  • Compound Interest (CI) = A - P
  • Compounding can happen yearly, half-yearly, quarterly, or monthly

Core Formula and Variants

The main formula for compound interest assumes annual compounding. However, UP Police exams often test half-yearly and quarterly compounding because they're trickier. When compounding happens more than once a year, the rate and time both adjust. For example, if interest is compounded half-yearly, you divide the rate by 2 and multiply the time by 2 (in terms of periods).

  • Annual compounding is the default; use it unless stated otherwise
  • Half-yearly: divide R by 2, multiply T by 2 (in periods)
  • Quarterly: divide R by 4, multiply T by 4 (in periods)
  • Always convert time into the number of compounding periods
  • The formula structure stays the same; only R and T change
Key formulas
Amount (Annual Compounding)
A = P(1 + R/100)^T
When: When interest is compounded once per year
Compound Interest
CI = P(1 + R/100)^T - P
When: To find just the interest earned, not the total amount
Amount (Half-Yearly Compounding)
A = P(1 + R/200)^(2T)
When: When interest is compounded twice per year
Amount (Quarterly Compounding)
A = P(1 + R/400)^(4T)
When: When interest is compounded four times per year
Worked examples

Example 1: Principal = 1000, Rate = 10% p.a., Time = 2 years (annual). A = 1000(1 + 10/100)^2 = 1000(1.1)^2 = 1000 × 1.21 = 1210. CI = 1210 - 1000 = 210.

Example 2: Principal = 8000, Rate = 20% p.a., Time = 1.5 years (half-yearly). A = 8000(1 + 20/200)^(2×1.5) = 8000(1.1)^3 = 8000 × 1.331 = 10648. CI = 10648 - 8000 = 2648.

Difference Between CI and SI

UP Police exams love asking 'Find the difference between CI and SI' or 'Which is greater?' This is a comparison trap. Simple Interest is always lower than Compound Interest (except in year 1, when they're equal). The difference grows larger as time increases. There's a shortcut formula to find the difference without calculating both separately.

  • SI = (P × R × T) / 100
  • CI is always greater than SI for T > 1 year
  • In year 1, CI and SI are equal
  • Difference = CI - SI = P × R^2 × T(T-1) / (100)^2 (for 2 years)
  • For quick comparison: if rates and principal are same, CI grows exponentially while SI grows linearly
Key formulas
Simple Interest
SI = (P × R × T) / 100
When: To calculate simple interest for comparison
Difference (2 years only)
CI - SI = P × R^2 / (100)^2
When: Quick way to find difference when T = 2 years
Worked example

Example: P = 5000, R = 10%, T = 2 years. SI = (5000 × 10 × 2) / 100 = 1000. CI = 5000(1.1)^2 - 5000 = 6050 - 5000 = 1050. Difference = 1050 - 1000 = 50. (Or use shortcut: 5000 × 100 / 10000 = 50.)

Tricky Scenarios in UP Police Exams

UP Police doesn't just ask straightforward CI calculations. They test your ability to handle real-world twists: changing rates, changing compounding periods mid-way, population growth, depreciation, and finding unknown variables (P, R, or T). These require careful reading and step-by-step application.

  • Changing rate: calculate for each period separately, then multiply amounts
  • Depreciation: use A = P(1 - R/100)^T (negative growth)
  • Population growth: same formula as CI, but for population numbers
  • Finding R or T: rearrange formula or use trial-and-error with options
  • Read carefully: 'compounded half-yearly' is different from 'paid half-yearly'
⚠ Common mistakes to avoid
  • Forgetting to adjust R and T for half-yearly/quarterly compounding. Many aspirants use the annual formula even when compounding is stated as half-yearly, leading to wrong answers.
  • Confusing CI with SI and using SI formula when CI is asked. Always check: does the question say 'compound' or just 'interest'?
  • Calculation errors with decimals and powers. (1.1)^2 = 1.21, not 1.2. Practice powers of 1.05, 1.1, 1.2, 1.25 beforehand.
  • Not reading 'per annum' or 'per year' carefully. Some questions state half-yearly rates directly (e.g., '5% per half-year'), which changes the formula structure.
  • Mixing up Amount and Interest. Amount = Principal + Interest. Many students subtract P from A incorrectly or forget to subtract at all.
🧠 Memory aids
  • CRAT: Compound = Rate Adjusted, Time Adjusted. When compounding changes, both R and T change in the formula.
  • Snowball Rule: CI grows like a snowball (exponential), SI grows like a line (linear). More time = bigger difference.
  • Half-Yearly = Divide R by 2, Multiply T by 2. Quarterly = Divide R by 4, Multiply T by 4. (Think: more frequent compounding = smaller rate per period, more periods total.)
  • Year 1 trick: In the first year, CI = SI always. After that, CI > SI. Use this to check if your answer is reasonable.
🎯 UP POLICE CONSTABLE exam tips
  • UP Police typically asks 2-3 CI questions per paper. Expect 1 straightforward calculation, 1 comparison (CI vs SI), and 1 tricky scenario (changing rate or half-yearly compounding).
  • Time management: CI calculations can be slow if you don't memorize common powers like (1.1)^2 = 1.21, (1.2)^2 = 1.44, (1.25)^2 = 1.5625. Pre-calculate these.
  • Recent patterns show more half-yearly and quarterly compounding questions. Annual compounding is now considered 'too easy' for UP Police. Prioritize these variants.
  • Watch for 'Amount' vs 'Interest' language in the question. Many aspirants calculate Amount but the question asks for Interest (or vice versa), costing full marks.
  • If options are given, use reverse calculation or plug-in method. Don't always calculate from scratch; sometimes checking an option is faster than deriving the answer.

Sample questions

Q1 · medium · PYQ 2009
किस धन का 10% प्रतिवर्ष चक्रवृद्धि ब्याज की दर से 3 वर्ष का मिश्रधन 1331 रु० होगा?
  1. 1500 रु०
  2. 1000 रु०
  3. 2000 रु०
  4. 800 रु०
Q2 · medium · PYQ 2024
A sum of money is paid back in two annual instalments of ₹1,764 each, allowing 5% compound interest compounded annually. The sum borrowed was:
  1. ₹3,200
  2. ₹3,220
  3. ₹3,280
  4. ₹3,240
Q3 · medium · PYQ 2026
₹ 15,000 की राशि 6% वार्षिक ब्याज पर निवेश की जाती है और कुछ वर्षों में कुल राशि ₹ 16,854 हो जाती है। अर्जित चक्रवृद्धि ब्याज ज्ञात कीजिए।
  1. ₹ 1,485
  2. ₹ 1,584
  3. ₹ 1,845
  4. ₹ 1,854
Q4 · medium · PYQ 2019
₹1,000 becomes ₹1,144.9 in 2 years. At what rate is the principal amount compounded annually?
  1. 9%
  2. 6%
  3. 8%
  4. 7%
Q5 · medium · PYQ 2018
What would be the interest earned on ₹2,100 for two years if the interest is compounded annually at 10% per annum?
  1. ₹462
  2. ₹441
  3. ₹453
  4. ₹432
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