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Mensuration Areas Perimeters Class 10 Questions for UP POLICE CONSTABLE

Free, AI-curated practice for the Mensuration Areas Perimeters Class 10 section of UP POLICE CONSTABLE. We have 39+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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📍 Mensuration Areas Perimeters Class 10 is also tested in:
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Why this topic matters · 8 min read
Mensuration appears in 2-4 questions per UP Police Constable paper, usually mixing 2D shapes (rectangle, circle, triangle) with real-world scenarios like field fencing, painting walls, or tank capacity. You need speed with formulas and the ability to spot when a problem requires multiple shapes combined. Expect 1-2 easy direct formula questions and 1-2 tricky application questions.

Rectangle and Square

These are the foundation shapes. A rectangle has length and width; a square has all sides equal. In UP Police exams, rectangle questions often involve fencing a field (perimeter) or painting a wall (area). Square problems test whether you remember that diagonal = side × root 2, which sometimes appears in indirect questions.

  • Rectangle: Perimeter = 2(L + B), Area = L × B
  • Square: Perimeter = 4 × side, Area = side²
  • Square diagonal = side × √2 (useful for indirect problems)
  • Common trap: confusing area and perimeter units (cm² vs cm)
  • Real-world: fencing cost = perimeter × rate per unit
Key formulas
Rectangle Perimeter
P = 2(L + B)
When: Finding fence length, border length, or distance around a field
Rectangle Area
A = L × B
When: Finding paint needed, tile count, or land area
Square Diagonal
d = s√2
When: Finding distance across a square field or diagonal measurement
Worked examples

A rectangular field is 50m long and 30m wide. Cost of fencing at Rs 10 per meter? Perimeter = 2(50+30) = 160m. Cost = 160 × 10 = Rs 1600.

A square room has side 8m. How much tile needed? Area = 8² = 64 m². If each tile is 1m², need 64 tiles.

Triangle

Triangle questions in UP Police usually involve right triangles or equilateral triangles. The most common formula is half × base × height. For right triangles, you may need Pythagoras. Equilateral triangle area uses the formula with √3, which appears occasionally.

  • General triangle: Area = (1/2) × base × height
  • Right triangle: Area = (1/2) × leg1 × leg2
  • Equilateral triangle: Area = (√3/4) × side²
  • Perimeter = sum of all three sides
  • Heron's formula rarely asked in UP Police (skip unless time permits)
Key formulas
Triangle Area (general)
A = (1/2) × b × h
When: Base and height are given
Equilateral Triangle Area
A = (√3/4) × s²
When: All three sides are equal
Triangle Perimeter
P = a + b + c
When: All three sides given
Worked examples

A triangle has base 12cm and height 8cm. Area = (1/2) × 12 × 8 = 48 cm².

An equilateral triangle has side 4m. Area = (√3/4) × 16 ≈ 6.93 m².

Circle

Circle questions test radius vs diameter confusion and whether you use π correctly. UP Police papers often ask about area of a circular field, circumference for a circular fence, or comparing two circles. Remember: radius is half diameter. Use π = 22/7 for exact answers, π ≈ 3.14 for approximations.

  • Circumference (perimeter) = 2πr or πd
  • Area = πr²
  • Radius = diameter/2
  • Common mistake: using diameter in area formula instead of radius
  • Sector area = (θ/360) × πr² (less common but appears sometimes)
Key formulas
Circle Circumference
C = 2πr or πd
When: Finding distance around circle or circular fence length
Circle Area
A = πr²
When: Finding area of circular field or circular region
Sector Area
A_sector = (θ/360) × πr²
When: Finding area of a pie-slice portion of circle
Worked examples

A circular park has radius 7m. Circumference = 2 × (22/7) × 7 = 44m. Area = (22/7) × 49 = 154 m².

A circle has diameter 10cm. Radius = 5cm. Area = π × 25 ≈ 78.5 cm².

Combined Shapes and Application Problems

UP Police loves mixing shapes. A question might ask for area of a rectangle with a semicircle on top (like a door), or a square with a circle inside. The key is to break the shape into known pieces, calculate each, then add or subtract. Always draw a rough sketch to avoid missing parts.

  • Identify each simple shape within the complex shape
  • Calculate area/perimeter of each part separately
  • Add areas if shapes are joined; subtract if one is cut out
  • Watch units: convert all to same unit before calculating
  • Sketch the problem—visual clarity prevents errors
Worked examples

A rectangular field 20m × 15m has a circular pond of radius 3.5m in the middle. Area of field minus pond = (20×15) - π(3.5)² = 300 - 38.5 ≈ 261.5 m².

A door is a rectangle 2m × 1m with a semicircle on top (radius 0.5m). Total area = (2×1) + (1/2)π(0.5)² = 2 + 0.39 ≈ 2.39 m².

Perimeter vs Area: Common Confusion

Aspirants often mix up perimeter (distance around) and area (space inside). Perimeter is measured in units (m, cm); area is measured in square units (m², cm²). A small perimeter can have large area and vice versa. In UP Police, questions test this by asking 'how much fencing' (perimeter) vs 'how much paint' (area).

  • Perimeter = boundary length (units: m, cm, km)
  • Area = space covered (units: m², cm², hectare)
  • A long thin rectangle can have same area as a square but different perimeter
  • Fencing, border, fence = perimeter questions
  • Paint, tile, carpet, grass = area questions
⚠ Common mistakes to avoid
  • Using diameter instead of radius in circle area formula. Always check: is it radius or diameter given? If diameter, divide by 2 first.
  • Forgetting to square the radius. Area = πr² not πr. This is the #1 mistake in UP Police papers.
  • Mixing units. If length is in meters and width in centimeters, convert to same unit before multiplying.
  • In combined shapes, forgetting to subtract. If a circle is cut out from a square, you must subtract circle area from square area.
  • Using wrong value of π. Use 22/7 for exact answers; use 3.14 only if problem says 'approximately' or gives π = 3.14.
  • Reading 'perimeter' as 'area' or vice versa. Slow down and read the question twice.
🧠 Memory aids
  • LBSCT = Length, Breadth, Side, Circle, Triangle. These are the 5 main shapes in UP Police mensuration.
  • Area = INSIDE (space), Perimeter = OUTSIDE (boundary). Think of perimeter as the fence around a field.
  • For circles: 2πr for circumference (2 in front), πr² for area (squared). The squared is the key difference.
  • Equilateral triangle has √3 in formula because all sides equal—remember √3 ≈ 1.73, so area is roughly 0.43 × side².
  • Sector = slice of pie. Angle/360 tells you what fraction of the full circle you have.
🎯 UP POLICE CONSTABLE exam tips
  • UP Police papers typically have 1 direct formula question (easy, 30 seconds) and 1-2 application questions (medium, 2-3 minutes). Prioritize speed on direct questions.
  • Recent papers show a trend toward combined shapes (rectangle + semicircle, square with circle inside). Practice these combinations.
  • Always draw a rough diagram in the margin. This prevents misreading and helps you spot if you need to add or subtract areas.
  • Use π = 22/7 unless told otherwise. This avoids decimal confusion and is faster in mental math.
  • Watch for 'cost' or 'rate' questions. These require perimeter or area first, then multiply by given rate. Two-step problems are common.
  • If a question seems too easy, re-read it. UP Police often hides a twist like 'both sides' or 'minus the door' that changes the calculation.

Sample questions

Q1 · hard · AI-verified
The sides of a triangle are 13 cm, 14 cm, and 15 cm. What is the area of the triangle using Heron's formula?
  1. 90 cm²
  2. 84 cm²
  3. 96 cm²
  4. 72 cm²
Q2 · medium · AI-verified
The diagonal of a square is 10√2 cm. What is the area of the square?
  1. 50 cm²
  2. 200 cm²
  3. 100 cm²
  4. 141.4 cm²
Q3 · medium · AI-verified
The radius of a circle is 14 cm. What is the area of the circle? (Use π = 22/7)
  1. 196 cm²
  2. 308 cm²
  3. 616 cm²
  4. 88 cm²
Q4 · hard · AI-verified
The diameter of a circular field is 42 m. A farmer wants to fence it. If the cost of fencing is ₹15 per metre, what is the total cost? (Use π = 22/7)
  1. ₹1,980
  2. ₹1,650
  3. ₹1,320
  4. ₹2,640
Q5 · hard · AI-verified
A semicircular region has a perimeter of 72 cm. What is the radius of the semicircle? (Use π = 22/7)
  1. 14 cm
  2. 7 cm
  3. 21 cm
  4. 18 cm
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