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Profit and Loss Questions for UP POLICE CONSTABLE

Free, AI-curated practice for the Profit and Loss section of UP POLICE CONSTABLE. We have 40+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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📍 Profit and Loss is also tested in:
SSC CGL (73)SSC MTS (52)RRB NTPC (30)SSC CHSL (21)
Why this topic matters · 7 min read
Profit and Loss is a high-frequency topic in UP Police Constable quant section, appearing in 2-4 questions per paper. Tests basic cost price, selling price, profit %, loss %, discount, and marked price concepts. Medium difficulty; most questions are straightforward if you know the formulas and avoid sign errors. Aspirants often confuse profit % base (CP vs SP) and miscalculate discount chains.

Core Definitions and Formulas

Profit and Loss revolves around three prices: Cost Price (CP) is what you buy for, Selling Price (SP) is what you sell for, and Marked Price (MP) is the tag price before discount. Profit happens when SP > CP; Loss when SP < CP. The key insight is that profit % and loss % are ALWAYS calculated on Cost Price unless the question explicitly says otherwise. Discount % is calculated on Marked Price. This distinction is where most errors occur.

  • Profit = SP - CP; Loss = CP - SP
  • Profit % = (Profit / CP) × 100; Loss % = (Loss / CP) × 100
  • Discount % = (Discount / MP) × 100, where Discount = MP - SP
  • SP = CP + Profit OR SP = CP × (100 + Profit%) / 100
  • SP = CP - Loss OR SP = CP × (100 - Loss%) / 100
  • SP = MP - Discount OR SP = MP × (100 - Discount%) / 100
Key formulas
Profit Percentage
Profit % = ((SP - CP) / CP) × 100
When: When you know SP and CP, and need profit as a percentage
Loss Percentage
Loss % = ((CP - SP) / CP) × 100
When: When SP < CP and you need loss as a percentage
Selling Price from Profit %
SP = CP × (100 + Profit%) / 100
When: When CP and profit % are given; find SP
Selling Price from Discount %
SP = MP × (100 - Discount%) / 100
When: When MP and discount % are given; find SP
Cost Price from Profit %
CP = SP × 100 / (100 + Profit%)
When: When SP and profit % are given; find CP
Worked examples

A shopkeeper buys a pen for Rs 10 and sells it for Rs 12. Profit = 12 - 10 = Rs 2. Profit % = (2/10) × 100 = 20%.

A book is marked at Rs 500. A discount of 20% is given. SP = 500 × (100 - 20) / 100 = 500 × 80/100 = Rs 400.

An item is sold at Rs 600 with a profit of 25%. Find CP. CP = 600 × 100 / (100 + 25) = 600 × 100/125 = Rs 480.

Marked Price, Discount, and Successive Discounts

Marked Price (MP) is the list price shown on the tag. Shopkeepers mark up goods above cost price to allow room for discount while still making profit. When multiple discounts are applied one after another (like 10% then 20%), you cannot simply add them; you must apply them sequentially. This is called successive discounts. The formula for two successive discounts is: Final SP = MP × (100 - D1) / 100 × (100 - D2) / 100.

  • Markup = MP - CP; Markup % = (Markup / CP) × 100
  • Discount is always on Marked Price, not Cost Price
  • For successive discounts, apply one after the other; do NOT add percentages
  • Equivalent single discount for D1 and D2: D_eq = D1 + D2 - (D1 × D2) / 100
  • If profit % and discount % are given, use: SP = CP × (100 + Profit%) / 100 and SP = MP × (100 - Discount%) / 100, then equate
Key formulas
Successive Discounts (Two)
Final SP = MP × (100 - D1)/100 × (100 - D2)/100
When: When two discounts are applied one after the other
Equivalent Single Discount
D_eq = D1 + D2 - (D1 × D2) / 100
When: To find the single discount equivalent to two successive discounts
Markup Percentage
Markup % = ((MP - CP) / CP) × 100
When: When you need to find how much above cost price the item is marked
Worked examples

MP = Rs 1000, Discount = 10% then 20%. SP = 1000 × (90/100) × (80/100) = 1000 × 0.9 × 0.8 = Rs 720. Equivalent single discount = 10 + 20 - (10×20)/100 = 30 - 2 = 28%.

CP = Rs 400, Profit = 20%, Discount = 10%. SP from profit = 400 × 120/100 = Rs 480. MP from discount: 480 = MP × 90/100, so MP = 480 × 100/90 = Rs 533.33.

Profit and Loss with Quantity and Mixtures

Sometimes questions involve buying and selling multiple items, or mixing items at different costs. The key is to calculate total CP and total SP, then find overall profit or loss. If items are sold at different profit %s, you must track each separately or use weighted averages. Be careful: if 10 items are bought at Rs 5 each and 15 items at Rs 8 each, total CP = 10×5 + 15×8 = 50 + 120 = Rs 170.

  • Total CP = sum of (quantity × unit cost) for all batches
  • Total SP = sum of (quantity × unit selling price) for all batches
  • Overall Profit % = ((Total SP - Total CP) / Total CP) × 100
  • When items are mixed, calculate total CP and total SP first, then profit %
  • Be alert: profit % on different items may differ; always use total figures for overall %
Worked examples

A shopkeeper buys 10 pens at Rs 5 each and 15 pens at Rs 8 each. He sells all at Rs 10 each. Total CP = 10×5 + 15×8 = 50 + 120 = Rs 170. Total SP = 25×10 = Rs 250. Profit = 250 - 170 = Rs 80. Profit % = (80/170) × 100 = 47.06%.

An item is bought at Rs 100 and sold at 20% profit. Another item is bought at Rs 200 and sold at 10% loss. Total CP = 100 + 200 = Rs 300. Total SP = 100×1.2 + 200×0.9 = 120 + 180 = Rs 300. Overall profit = 0% (break-even).

False Weight and Adulteration (Common in UP Police)

UP Police exams often include profit-loss questions disguised as false weight problems. A shopkeeper claims to sell at cost price but uses false weights (e.g., gives 900g instead of 1000g). This creates hidden profit. The formula: if he claims to give W1 but gives W2, his profit % = ((W1 - W2) / W2) × 100. Similarly, if he mixes cheaper items with expensive ones, the profit is the difference in cost weighted by quantity.

  • False weight profit % = ((Claimed weight - Actual weight) / Actual weight) × 100
  • If shopkeeper claims to sell at cost price but uses false weights, profit = false weight profit %
  • Adulteration: if pure item costs Rs X per kg and adulterant costs Rs Y per kg, profit from mixing depends on ratio
  • Always identify: what is claimed vs. what is actual
Worked examples

A shopkeeper claims to sell at cost price but gives 900g for every 1000g. Profit % = ((1000 - 900) / 900) × 100 = (100/900) × 100 = 11.11%.

Pure ghee costs Rs 500/kg, adulterant costs Rs 200/kg. If mixed 1:1 by weight and sold at Rs 500/kg, CP per kg = (500 + 200) / 2 = Rs 350. Profit % = ((500 - 350) / 350) × 100 = 42.86%.

⚠ Common mistakes to avoid
  • Calculating profit % on Selling Price instead of Cost Price. Remember: profit % is ALWAYS on CP unless stated otherwise. If SP = 120 and profit = 20, CP = 100, profit % = 20%, NOT 20/120 × 100 = 16.67%.
  • Adding successive discounts instead of multiplying. If two 20% discounts are applied, final price is NOT 60% of MP; it is 80% × 80% = 64% of MP.
  • Confusing Marked Price with Cost Price. Discount is on MP, not CP. If MP = 1000, CP = 600, discount = 10%, then SP = 900, and profit = 300, profit % = 50%, NOT based on discount.
  • Forgetting to convert percentages to decimals. Always use (100 + Profit%) / 100 or (100 - Loss%) / 100 in formulas, not just the percentage number.
  • In false weight problems, using claimed weight as denominator instead of actual weight. Profit % = ((Claimed - Actual) / Actual) × 100, not / Claimed.
🧠 Memory aids
  • CP-SP-MP Triangle: CP is base (cost), SP is middle (selling), MP is top (marked/tag). Profit/Loss measured from CP. Discount measured from MP.
  • PROFIT = SP > CP; LOSS = SP < CP. Think: Profit is when you sell Higher than you bought.
  • Successive Discount Multiply Rule: D1 then D2 means multiply (1 - D1/100) × (1 - D2/100), NOT add. Example: 20% then 10% = 0.8 × 0.9 = 0.72 = 28% equivalent single discount.
  • False Weight Trick: If you claim to give 1000g but give 900g at cost price, you're actually making profit = 1000/900 - 1 = 11.11%. The 'extra' 100g is free profit.
🎯 UP POLICE CONSTABLE exam tips
  • UP Police Constable typically includes 2-3 profit-loss questions in the 60-minute quant section. They are usually straightforward (not tricky) if you know formulas; expect 1 easy, 1 medium, 1 hard.
  • False weight and adulteration questions are VERY common in UP Police. If you see a question about 'selling at cost price' but with a twist (false weights, mixing), immediately think hidden profit.
  • Successive discount questions appear frequently. Practice the equivalent single discount formula; it saves time and avoids calculation errors.
  • Watch for questions that mix profit % with discount %. These require you to set up two equations: SP from profit side and SP from discount side, then solve for unknown (usually CP or MP).
  • Time management: Profit-loss questions should take 1.5-2 minutes max. If you're stuck, skip and return. Most questions follow standard patterns; if it looks unfamiliar, re-read carefully—it's likely a false weight or adulteration variant.

Sample questions

Q1 · medium · PYQ 2024
A trader marked the price of a commodity to include a profit of 25% but allowed a discount of 16% on the marked price. What will be his actual profit?
  1. 25%
  2. 5%
  3. 9%
  4. 16%
Q2 · medium · PYQ 2024
A book vendor sold a book at a loss of 10%. Had he sold it for ₹1,080 more, he would have earned a profit of 10%. Find out the cost of the book.
  1. ₹4,420
  2. ₹7,400
  3. ₹6,480
  4. ₹5,400
Q3 · medium · PYQ 2018
By selling an item for Rs. 434, Ramesh makes a profit of 24%. What was the rate at which Ramesh purchased it?
  1. Rs. 340
  2. Rs. 360
  3. Rs. 375
  4. Rs. 350
Q4 · medium · PYQ 2024
The printed price of an article is 40% higher than its cost price. Then, what is the rate of discount so that the gain is 12% profit?
  1. 15%
  2. 18%
  3. 21%
  4. 20%
Q5 · medium · PYQ 2013
एक दुकानदार अपने सामान पर क्रय-मूल्य से 20% अधिक अंकित करता है तथा अंकित मूल्य पर 10% की छूट देता है। उसका लाभ प्रतिशत बताएँ
  1. 12%
  2. 20%
  3. 8%
  4. 10%
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