Why this topic matters · 8 min read
Pipes and Cisterns is a high-frequency topic in UP Police Constable Numerical section (appears in ~2-3 questions per paper). Tests your ability to calculate work rates, combined efficiency, and time to fill/empty tanks. Requires clear understanding of positive work (inlet pipes) vs negative work (outlet pipes). Most questions involve 2-3 pipes working together; difficulty is moderate but errors are common due to sign confusion.
Core Concept: Work Rate and Efficiency
In pipes and cisterns, we treat each pipe as a 'worker' with a specific work rate. If a pipe fills a tank in 10 hours, its rate is 1/10 of the tank per hour. If a pipe empties a tank in 15 hours, its rate is -1/15 per hour (negative because it removes water). When pipes work together, their rates add up algebraically. The key insight: always think in terms of 'fraction of tank per unit time', not absolute volumes.
- Inlet pipe (fills tank): positive work rate = 1/time taken
- Outlet pipe (empties tank): negative work rate = -1/time taken
- Combined rate = sum of individual rates (with signs)
- Time to complete combined work = 1 / combined rate
- If combined rate is negative, the tank empties; if positive, it fills
Two-Pipe Problems: Standard Pattern
Most UP Police papers ask: 'Pipe A fills a tank in 6 hours, Pipe B empties it in 9 hours. How long to fill if both open?' This is a classic combined-rate problem. Calculate individual rates, add them (with correct signs), then invert to get time. Watch the wording carefully: 'fills' = positive, 'empties' = negative.
- Identify which pipes fill (positive) and which empty (negative)
- Write rate for each: Rate_A = 1/6, Rate_B = -1/9
- Combined rate = 1/6 - 1/9 (find common denominator)
- Time = 1 / combined rate
- Always check: does answer make sense? (Should be between slowest and fastest individual time)
Key formulas
Combined Rate (2 pipes)
R_combined = 1/T_A + 1/T_B (or - if outlet)
When: When two pipes work simultaneously; use + for inlet, - for outlet
Time to Fill/Empty
T_combined = 1 / R_combined
When: After calculating combined rate, invert to get time
Worked examples
Pipe A fills tank in 8 hours, Pipe B empties in 12 hours. Time to fill both open? Rate_A = 1/8, Rate_B = -1/12. Combined = 1/8 - 1/12 = 3/24 - 2/24 = 1/24. Time = 24 hours.
Pipe X fills in 5 hours, Pipe Y fills in 10 hours. Time if both open? Rate_X = 1/5, Rate_Y = 1/10. Combined = 1/5 + 1/10 = 2/10 + 1/10 = 3/10. Time = 10/3 = 3.33 hours.
Three-Pipe and Partial-Opening Problems
Harder variants involve 3 pipes or pipes opening/closing at different times. For 3 pipes: calculate all three rates, sum them. For partial opening: calculate combined rate for the first period, then adjust when a pipe closes/opens, and recalculate. Break the problem into time intervals and track cumulative work.
- Three pipes: R_total = R_A + R_B + R_C (with signs)
- Partial opening: split into phases, calculate work in each phase separately
- Track cumulative work: if 1/4 tank filled in phase 1, remaining = 3/4 for phase 2
- Recalculate time for remaining work using new combined rate
- Common trap: forgetting to subtract work already done before calculating remaining time
Worked examples
Pipes A, B, C fill in 6, 8, 12 hours respectively. Time if all three open? Rates: 1/6 + 1/8 + 1/12. LCM(6,8,12)=24. Combined = 4/24 + 3/24 + 2/24 = 9/24 = 3/8. Time = 8/3 = 2.67 hours.
Pipe A fills in 10 hours, Pipe B empties in 15 hours. A opens for 4 hours, then B also opens. Time to fill? Phase 1 (A only, 4 hrs): work = 4 × 1/10 = 2/5. Remaining = 3/5. Phase 2 (A+B): rate = 1/10 - 1/15 = 3/30 - 2/30 = 1/30. Time for 3/5 = (3/5) / (1/30) = 18 hours. Total = 4 + 18 = 22 hours.
Leak and Waste Problems
A 'leak' or 'waste' is an outlet pipe that drains water unintentionally. Treat it exactly like an emptying pipe: negative work rate. If a tank has a leak that empties a full tank in 20 hours, its rate is -1/20. The presence of a leak increases the time to fill the tank.
- Leak = outlet pipe with negative rate
- Combined rate with leak = inlet rate - leak rate
- If leak rate is large, tank may never fill (combined rate ≤ 0)
- Check: if combined rate is negative or zero, answer is 'never fills' or 'infinity'
- Leak problems often ask: 'How long to fill if leak is present vs. absent?'
Inverse Problems: Finding Individual Times
Sometimes the exam gives combined time and asks for individual pipe time. Example: 'Pipes A and B together fill in 6 hours. A alone fills in 10 hours. How long for B alone?' Use algebra: if R_A + R_B = 1/6 and R_A = 1/10, then R_B = 1/6 - 1/10. Solve for T_B.
- Write equation: R_A + R_B = R_combined
- Substitute known rates, solve for unknown
- Be careful with signs: if one empties, use subtraction
- Check: combined time should be less than fastest individual pipe (if both fill)
Worked example
A and B fill tank in 12 hours. A alone in 20 hours. B alone? 1/20 + 1/T_B = 1/12. 1/T_B = 1/12 - 1/20 = 5/60 - 3/60 = 2/60 = 1/30. T_B = 30 hours.
⚠ Common mistakes to avoid
- Forgetting to use negative sign for outlet/emptying pipes. Many students add all rates as positive and get wrong answer. Always: inlet = +, outlet = -.
- Confusing 'time to fill' with 'rate'. If pipe fills in 10 hours, rate is 1/10, NOT 10. Invert the time.
- Not finding common denominator when adding fractions. 1/6 + 1/9 is NOT 2/15. Find LCM: 1/6 + 1/9 = 3/18 + 2/18 = 5/18.
- In partial-opening problems, forgetting to subtract work already done. If 1/3 tank filled in phase 1, remaining is 2/3, not 1/3.
- Misreading 'both pipes open' vs 'pipes open alternately'. Simultaneous = add rates. Alternating = split time and calculate separately.
🧠 Memory aids
- INLET = POSITIVE, OUTLET = NEGATIVE. Think: water in = +, water out = -. Like bank account: deposit is +, withdrawal is -.
- RATE = 1/TIME. Always invert. If fills in 5 hours, rate is 1/5 per hour. If empties in 10 hours, rate is -1/10 per hour.
- COMBINED RATE = SUM OF RATES. Then TIME = 1 / COMBINED. Two-step process: add rates, invert result.
- LCM IS YOUR FRIEND. When adding fractions like 1/6 + 1/9, find LCM(6,9)=18, convert to 3/18 + 2/18 = 5/18. Avoids decimals and errors.
🎯 UP POLICE CONSTABLE exam tips
- UP Police typically asks 2-3 pipes and cisterns questions per paper. Usually 1 straightforward two-pipe problem (6-8 min), 1 three-pipe or partial-opening (10-12 min). Difficulty: moderate.
- Watch for 'trick' wording: 'pipe A fills tank in 6 hours' vs 'pipe A fills 1/6 of tank in 1 hour' (same thing, but second form is rate directly). Read carefully.
- Time management: these questions are solvable in 5-8 minutes if you know the method. Don't spend >10 minutes on one question; move on and come back.
- Common wrong options in MCQ: answers that use only one pipe's time, or answers that add times instead of rates. If you see 'sum of times', it's likely wrong.
- Recent papers (2022-2024) show preference for 2-pipe problems with one inlet and one outlet (leak scenario). Practice this pattern heavily.
Q1 · medium · AI-verified
Pipe A fills a tank in 10 hours and Pipe B fills it in 15 hours. Both pipes are opened at 6 AM. At what time will the tank be full?
- 11:30 AM
- 11:00 AM
- 1:00 PM
- 12:00 PM (noon)
Q2 · medium · AI-verified
Ramu can do a piece of work in 15 days and Shyamu can do it in 25 days. They work together for 5 days, then Ramu leaves. In how many more days will Shyamu complete the remaining work?
- 12 days
- 15 days
- 8 days
- 10 days
Q3 · hard · AI-verified
Two pipes together fill a cistern in 6 hours 40 minutes. If one pipe alone takes 3 hours more than the other to fill the cistern, in how many hours does the slower pipe alone fill it?
- 10 hours
- 12 hours
- 15 hours
- 18 hours
Q4 · easy · AI-verified
Pipe A can fill a tank in 20 minutes and Pipe B can fill the same tank in 30 minutes. If both pipes are opened together, in how many minutes will the tank be full?
- 25 minutes
- 12 minutes
- 15 minutes
- 10 minutes
Q5 · medium · AI-verified
A pipe can fill a tank in 4 hours. Due to a leak at the bottom, it takes 6 hours to fill. If the tank is full, how long will the leak take to empty it?
- 12 hours
- 10 hours
- 8 hours
- 15 hours