A 4-digit number is selected at random formed by using the digits 0, 1, 2, 3 and 4 (where repetition of digits is not allowed). What is the probability that the number selected is divisible by 2?

Total 4-digit numbers without repetition from {0,1,2,3,4}: First digit ≠ 0, so 4×4×3×2 = 96. For divisibility by 2, last digit must be 0, 2, or 4. Case last digit = 0: 4×3×2 = 24. Case last digit = 2: first digit (not 0, not 2) has 3 choices, remaining 3×2 = 6, total 18. Similarly for last digit = 4: 18. Total = 24 + 18 + 18 = 60. Probability = 60/96 = 5/8.