CTET PAPER II 2019 · PYQ · Motion / Speed and Distance · easy
A bus travels at a speed of 50 km/h for 12 minutes & then at a speed of 40 km/h for the next 18 minutes. Total distance covered by the bus during this time is –
A.20 km
B.22 km✓ Correct
C.24 km
D.28 km
Explanation
Distance covered in first segment = 50 km/h × (12/60) h = 50 × 0.2 = 10 km. Distance covered in second segment = 40 km/h × (18/60) h = 40 × 0.3 = 12 km. Total distance = 10 + 12 = 22 km.
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