A container holds 70 litres of a milk mixture in price water makes up 10% of the total. How many litres of pure water should be added so that the proportion of water in the mixture increases to 25%?

Question

Accepted Answer

14 liters. Initial water = 10% of 70 = 7 litres. Let x litres of water be added: (7+x)/(70+x) = 25/100 = 1/4. So 4(7+x) = 70+x → 28+4x = 70+x → 3x = 42 → x = 14 litres.

A container holds 70 litres of a milk mixture in price water makes up 10% of the total. How many litres of pure water should be added so that the proportion of water in the mixture increases to 25%?

Explanation

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