A man leaves from P at 6 am and reaches Q at 2 pm on the same day. Another man leaves Q at 8 am and reaches P at 3 pm on the same day. At what time do they meet?

Let total distance = 56 units. First person's speed = 56/8 = 7, second person's speed = 56/7 = 8. They start towards each other at 8 am, relative speed = 15. Distance covered by first in 2 hrs = 14. Remaining = 42. Time to meet after 8 am = 42/15 = 2 hrs 48 min. Meeting time = 8:00 + 2:48 = 10:48 am.