A man starting from a place P went x metre (x 120 m) East before turning South. He went 40 m straight before turning to West. He went 60 m to reach a place Q. From Q he went 200 m North and reached a place R. If PR = 200 m, then what is x equal to?

Question

A man starting from a place P went x metre (x > 120 m) East before turning South. He went 40 m straight before turning to West. He went 60 m to reach a place Q. From Q he went 200 m North and reached a place R. If PR = 200 m, then what is x equal to?

Accepted Answer

180 m. Set P at origin. Going East x m: (x, 0). South 40 m: (x, -40). West 60 m: (x-60, -40). North 200 m to R: (x-60, 160). So R is at (x-60, 160). Distance PR = √[(x-60)² + 160²] = 200. Then (x-60)² + 25600 = 40000, so (x-60)² = 14400, x-60 = 120, x = 180 m.

A man starting from a place P went x metre (x > 120 m) East before turning South. He went 40 m straight before turning to West. He went 60 m to reach a place Q. From Q he went 200 m North and reached a place R. If PR = 200 m, then what is x equal to?

Explanation

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