Circulation figures (in thousands) of different newspapers (A, B, C, D, E) for five years are given. How many cases are there in which average of the circulation for an individual newspaper was more than the average of the circulation of all the newspapers?

Averages of each paper over 5 years: A: (20+12+24+26+22)/5 = 104/5 = 20.8. B: (10+12+14+10+16)/5 = 62/5 = 12.4. C: (15+18+17+16+14)/5 = 80/5 = 16.0. D: (8+12+14+15+16)/5 = 65/5 = 13.0. E: (20+12+15+9+11)/5 = 67/5 = 13.4. Overall average = (104+62+80+65+67)/25 = 378/25 = 15.12. Papers with average above 15.12: A (20.8) and C (16.0). That's 2 papers.