Consider the following electric circuit: A 10 V battery is connected to a series combination of 5 Ω, a parallel network (10 Ω, 0 Ω, 10 Ω in parallel), and 5 Ω. The current in the above electric circuit is:

The middle parallel branch contains a 0 Ω resistor in parallel with two 10 Ω resistors. A 0 Ω wire short-circuits all parallel branches, so the equivalent resistance of the parallel combination is 0 Ω. Therefore, the total resistance in the circuit is 5 Ω + 0 Ω + 5 Ω = 10 Ω. By Ohm's law, current I = V/R = 10 V / 10 Ω = 1 A. Hence, the current in the circuit is 1 A.