Eight persons P, Q, R, S, T, U, V and W sit around a round table in eight different seats placed with equal distance between any two consecutive seats. Both P and R are adjacent to Q. Both T and R are adjacent to S. Both U and W are adjacent to V. S and W are on opposite chairs. If while going in the clockwise direction around the table from P, one meets R before T, then how many persons shall Q cross while moving in the clockwise direction around the table before meeting W?

P and R are adjacent to Q, so order around Q is P-Q-R or R-Q-P. T and R adjacent to S means S is between T and R: T-S-R or R-S-T. Combining: P-Q-R-S-T sequence. S and W opposite: with 8 seats, opposite of S is 4 seats away. U and W adjacent to V: U-V-W or W-V-U. Given clockwise from P meets R before T: clockwise order P→Q→R→S→T. Continuing clockwise after T: next is opposite-of-Q etc. Seats clockwise: P, Q, R, S, T, ?, ?, ?. The remaining three are U, V, W with U-V-W or W-V-U consecutive, and W opposite S. S at position 4, so W at position 8 (opposite). Then V at 7 and U at 6 (since U-V-W consecutive). Final order clockwise from P: P(1), Q(2), R(3), S(4), T(5), U(6), V(7), W(8). From Q (pos 2) clockwise to W (pos 8): crosses R, S, T, U, V = 5 persons. Hence 5.