If 2sin²A + 2√2 cosA − 3 = 0, then find the value of tan A.

Question

Accepted Answer

1. Substituting 2sin²A = 2(1-cos²A): 2-2cos²A+2√2 cosA-3=0 → -2cos²A+2√2 cosA-1=0 → 2cos²A-2√2 cosA+1=0. Using quadratic formula: cosA = (2√2 ± √(8-8))/4 = 2√2/4 = √2/2, so A=45° and tanA=1.

If 2sin²A + 2√2 cosA − 3 = 0, then find the value of tan A.

Explanation

More Trigonometry questions

Want more SSC CHSL practice?