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CDS 2022 · PYQ · Trigonometry · medium

If A, B, C, D are the angles of a cyclic quadrilateral, then what is the value of sin((A+C)/2) + sin((B+D)/2)?

Answer

The correct answer is A: 2. A+C = B+D = 180°, so (A+C)/2 = (B+D)/2 = 90°. sin90° + sin90° = 2.

  1. A.2✓ Correct
  2. B.1
  3. C.0
  4. D.-1

Explanation

A+C = B+D = 180°, so (A+C)/2 = (B+D)/2 = 90°. sin90° + sin90° = 2.
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