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SSC CHSL 2021 · PYQ · Trigonometry · medium

If a triangle ABC is right-angled at A, then what is the value of sin((B+C)/2) · cos((B+C)/2)?

  1. A.1/4
  2. B.√2
  3. C.√3/4
  4. D.1/2✓ Correct

Explanation

Since triangle ABC is right-angled at A, B+C = 90°, so (B+C)/2 = 45°. sin45° × cos45° = (1/√2)(1/√2) = 1/2.
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