SSC CHSL 2021 · PYQ · Trigonometry · medium
If a triangle ABC is right-angled at A, then what is the value of sin((B+C)/2) · cos((B+C)/2)?
Answer
The correct answer is D: 1/2. Since triangle ABC is right-angled at A, B+C = 90°, so (B+C)/2 = 45°. sin45° × cos45° = (1/√2)(1/√2) = 1/2.
- A.1/4
- B.√2
- C.√3/4
- D.1/2✓ Correct
Since triangle ABC is right-angled at A, B+C = 90°, so (B+C)/2 = 45°. sin45° × cos45° = (1/√2)(1/√2) = 1/2.
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