If both length and breadth of a cuboid is increased by 50 percent, then by how much percent its height should be reduced so that its volume remains same?
A.37.25 percent
B.55.55 percent✓ Correct
C.48.75 percent
D.62.34 percent
Explanation
New length and breadth are each 1.5 times original. For volume to remain constant: 1.5l × 1.5b × h' = lbh → h' = h/2.25. Percentage reduction = (1 – 1/2.25) × 100 ≈ 55.55%.
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