If log_b a = p, log_d c = 2p and log_f e = 3p, then what is (ace)^(1/p) equal to?
A.bd²f³✓ Correct
B.bdf
C.b³d²f
D.b²d²f²
Explanation
From log_b a = p: a = b^p. From log_d c = 2p: c = d^(2p). From log_f e = 3p: e = f^(3p). So ace = b^p · d^(2p) · f^(3p) = (bd²f³)^p. Therefore (ace)^(1/p) = bd²f³.
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