If the numbers X + 2, X + 5, 2X − 3 and 3X − 5 are in proportion, then which of the following pairs of values is possible for X?
Answer
The correct answer is A: 5 and 1. For proportion: (X+2)(3X−5) = (X+5)(2X−3). Expanding and simplifying gives x²−6x+5=0, so (x−1)(x−5)=0, yielding x=1 or x=5.
A.5 and 1✓ Correct
B.3 and 2
C.4 and 2
D.5 and 3
Explanation
For proportion: (X+2)(3X−5) = (X+5)(2X−3). Expanding and simplifying gives x²−6x+5=0, so (x−1)(x−5)=0, yielding x=1 or x=5.
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