If the perimeters of two similar triangles are in the ratio of 4 : 7, and the sum of the areas is 195 cm², then what is (1/3) of the difference between the areas (in cm²) of the two triangles?
A.54
B.63
C.33✓ Correct
D.99
Explanation
Ratio of areas = (4/7)² = 16:49. Let areas be 16k and 49k; 65k = 195, so k = 3. Areas are 48 cm² and 147 cm². Difference = 99 cm². One-third of difference = 99/3 = 33.
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