If two sides of a square lie on the lines 2x + y – 3 = 0 and 4x + 2y + 5 = 0, then what is the area of the square in square units?

The two lines are parallel: 2x + y – 3 = 0 and 4x + 2y + 5 = 0, i.e., 2x + y + 5/2 = 0. Distance between parallel lines = |–3 – 5/2|/√(4 + 1) = |–11/2|/√5 = 11/(2√5). This is the side length. Area = (11/(2√5))² = 121/20 = 6.05. Hmm, that gives 6.05 (option a). Let me recompute: distance = |c₁ – c₂|/√(a² + b²) where both lines normalized to same coefficients. Line 1: 2x + y – 3 = 0. Line 2: 4x + 2y + 5 = 0 ÷ 2 = 2x + y + 5/2 = 0. Distance = |–3 – 5/2|/√5 = (11/2)/√5 = 11/(2√5). Side² = 121/20 = 6.05. The answer is 6.05, option (a).