Sarkari RiseLogin
CDS 2022 · PYQ · Algebra · medium

If (x+√(1+x²))(y+√(1+y²)) = 1, where x and y are real numbers, then what is the value of (x+y)²?

  1. A.0✓ Correct
  2. B.4
  3. C.9
  4. D.1

Explanation

The condition implies y = -x (since (x+√(1+x²)) and (-x+√(1+x²)) are reciprocals). So x+y = 0, hence (x+y)² = 0.
💡 Practice unlimited CDS PYQs + AI-tracked progress on each topic. Sign up free →

More Algebra questions

Want more CDS practice?

Free daily 10-Q quiz · adaptive mocks · 4,000+ verified PYQs · AI doubt solver in Hindi + English

Sign up freeMore Algebra practice