CDS 2022 · PYQ · Algebra · medium
If (x+√(1+x²))(y+√(1+y²)) = 1, where x and y are real numbers, then what is the value of (x+y)²?
Answer
The correct answer is A: 0. The condition implies y = -x (since (x+√(1+x²)) and (-x+√(1+x²)) are reciprocals). So x+y = 0, hence (x+y)² = 0.
- A.0✓ Correct
- B.4
- C.9
- D.1
The condition implies y = -x (since (x+√(1+x²)) and (-x+√(1+x²)) are reciprocals). So x+y = 0, hence (x+y)² = 0.
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