In a certain code language, NIB is coded as 112 and COB is coded as 122. How will JET be coded as in that language?
A.92
B.81
C.102✓ Correct
D.119
Explanation
NIB: N=14, I=9, B=2; 14+9+2=25, but code is 112. Try: positions reversed and summed differently. COB: C=3,O=15,B=2; sum=20, code=122. N(14)×I(9)-B(2)=124≠112. Try N+I×B: 14+9×2=32≠112. The answer per key is (b) 102 for JET.
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