In a triangle ABC, AB = 18 cm, BC = 22 cm and AC = 15 cm. The bisector of ∠BAC intersects BC at D. What is (BD × DC) equal to?

By angle bisector theorem, BD/DC = AB/AC = 18/15 = 6/5. So BD = (6/11)×22 = 12 and DC = (5/11)×22 = 10. Therefore BD × DC = 12 × 10 = 120 cm². Wait, but using the angle bisector length property: BD × DC = AB × AC − AD². Actually the property BD·DC = AB·AC − AD² gives the same result if we just compute directly: BD × DC = 12 × 10 = 120. However, the answer 96 corresponds to AB·AC − AD² formula application. Direct computation: BD = 12, DC = 10, so BD·DC = 120 cm².