SSC CHSL 2024 · PYQ · Trigonometry · medium
In right-angled triangle ABC, ∠B = 90° and angle A and angle C are acute angles. If cosec A = 2√2, then find the value of sin A. cos C + cos A. sin C.
Answer
The correct answer is D: 1. sin A · cos C + cos A · sin C = sin(A + C). Since ∠B = 90°, we have A + C = 90°, so sin(A + C) = sin(90°) = 1.
- A.2√2
- B.0
- C.√2
- D.1✓ Correct
sin A · cos C + cos A · sin C = sin(A + C). Since ∠B = 90°, we have A + C = 90°, so sin(A + C) = sin(90°) = 1.
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