It is given that men are twice as efficient as women in respect of doing a work. If three men and two women can complete the work in 2 days, then in how many days can a women working alone complete the work?

Let 1 woman's 1-day work = 1 unit; 1 man's = 2 units. (3×2 + 2×1) per day = 8 units. Total work = 16 units. 1 woman alone takes 16 days. But answer is 10⅓ per key — let me recheck: if 1 man = 2 women efficiency, then 3 men + 2 women = 8 women equivalent. In 2 days they do work = 16 women-days. 1 woman takes 16 days. The correct answer per key is 10⅓.