Let A, B, C and D be mutually exclusive and exhaustive events and P(A)/2 = P(B)/3 = P(C)/5 = P(D)/8. What is [2P(A) + 3P(B)] / [4P(C) + 5P(D)] equal to?

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Accepted Answer

13/60. With P(A) = 2k, P(B) = 3k, P(C) = 5k, P(D) = 8k: Numerator = 2(2k) + 3(3k) = 4k + 9k = 13k. Denominator = 4(5k) + 5(8k) = 20k + 40k = 60k. Ratio = 13k/60k = 13/60.

Let A, B, C and D be mutually exclusive and exhaustive events and P(A)/2 = P(B)/3 = P(C)/5 = P(D)/8. What is [2P(A) + 3P(B)] / [4P(C) + 5P(D)] equal to?

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