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NDA 2024 · PYQ · Composition of Functions / Differentiation · medium

Let f(x) and g(x) be two functions such that g(x) = x - 1/x and f∘g(x) = x³ - 1/x³. What is f''(x) equal to?

  1. A.-2/x³
  2. B.2x + 2/x³
  3. C.6x + 3
  4. D.6x✓ Correct

Explanation

From f(g(x)) = x³ - 1/x³ = (x - 1/x)³ + 3(x - 1/x), we identify f(t) = t³ + 3t. So f(x) = x³ + 3x. Then f'(x) = 3x² + 3 and f''(x) = 6x.
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