Let p = (x + y + z) and q = xyz. If |x 1 1; 1 y 1; 1 1 z| is positive, then which one of the following is correct?
A.q > p
B.q + 1 > p
C.q + 2 > p✓ Correct
D.q + 2 ≥ p
Explanation
Expanding the determinant: x(yz - 1) - 1(z - 1) + 1(1 - y) = xyz - x - z + 1 + 1 - y = xyz - (x + y + z) + 2 = q - p + 2. For this to be positive, q - p + 2 > 0, i.e., q + 2 > p.
💡 Practice unlimited NDA PYQs + AI-tracked progress on each topic. Sign up free →