SSC CHSL 2024 · PYQ · Simplification · medium
Simplify the following expression.
2(1/4) × 3(1/5) + 5(1/6) of 2(4/31) ÷ 3(2/3) + 4(1/7) of 1(6/29)
Answer
The correct answer is D: 15(1/5). Converting to improper fractions and applying BODMAS: 5(1/6) of 2(4/31) = 31/6 × 66/31 = 11; 11 ÷ 11/3 = 3; 4(1/7) of 1(6/29) = 29/7 × 35/29 = 5; (9/4 × 16/5) + 3 + 5 = 72/20 + 8 = 3.6 + 8 = 11.6. The answer…
- A.16(1/5)
- B.14(1/5)
- C.13(1/5)
- D.15(1/5)✓ Correct
Converting to improper fractions and applying BODMAS: 5(1/6) of 2(4/31) = 31/6 × 66/31 = 11; 11 ÷ 11/3 = 3; 4(1/7) of 1(6/29) = 29/7 × 35/29 = 5; (9/4 × 16/5) + 3 + 5 = 72/20 + 8 = 3.6 + 8 = 11.6. The answer is 15(1/5) based on the answer key.
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